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April 16, 2014

April 16, 2014

**Recent Homework Questions About Statistics**

Post a New Question | Current Questions

**statistics**

after one month of operation the health information services at community health center determined that there were two records misfiled out of the 450 active records. what is the filing accuracy rate for this area?
*Thursday, August 1, 2013 at 12:18am*

**Statistics**

Of the 5,352 requests for medical records, 4,257 were located within the 20-minute time frame established by the supervisor as a qulaity improvement indicator. What is the rate of compliance in answering requests for records?
*Wednesday, July 31, 2013 at 11:03pm*

**math**

As you follow your favorite NBA basketball team’s statistics, you notice the point guard is successfully shooting 85% from the free-throw line for this season. Assuming he is fouled near the end of a game and shoots with that same success rate, what is the probability ...
*Wednesday, July 31, 2013 at 9:21pm*

**statistics**

Suppose a large-scale randomized experiment were conducted to compare two weight loss plans. At the end of the experiment, the weight loss for each subject (in pounds) was recorded. The p-value turned out to be .004, and a 99% confidence interval for the difference in means ...
*Wednesday, July 31, 2013 at 4:35pm*

**math**

Z = (mean1 - mean2)/standard error (SE) of difference between means SEdiff = √(SEmean1^2 + SEmean2^2) SEm = SD/√n If only one SD is provided, you can use just that to determine SEdiff. Find table in the back of your statistics text labeled something like "...
*Wednesday, July 31, 2013 at 1:17pm*

**Statistics**

C)
*Wednesday, July 31, 2013 at 12:57pm*

**statistics**

Try a one-sample z-test on this data: z = (sample mean - population mean)/(standard deviation divided by the square root of the sample size) z = (49 - 50)/(5/√36) I'll let you finish the calculation. Check a z-table for your critical or cutoff value at .05 level of ...
*Tuesday, July 30, 2013 at 7:04pm*

**statistics**

Try this formula: n = [(z-value)^2 * p * q]/E^2 = [(1.96)^2 * .2 * .8]/.05^2 I'll let you finish the calculation. Note: n = sample size needed; .2 (20%)for p and .8 (which is 1 - p) for q. E = maximum error, which is .05 (5%) in the problem. Z-value is found using a z-...
*Tuesday, July 30, 2013 at 6:58pm*

**Statistics **

There are two boxes, each with several million tickets marked “1” or “0”. The two boxes have the same number of tickets, but in one of the boxes, 49% of the tickets are marked “1” and in the other box 50.5% of the tickets are marked “1”...
*Tuesday, July 30, 2013 at 5:46pm*

**MTH315/statistics UOP**

1. The Myers Summer Casual Store tells its customers that a special order will take six weeks (42 days). During the recent months, the owner has received several complaints that the special orders are taking longer than 42 days. A sample of 12 special orders delivered in the ...
*Tuesday, July 30, 2013 at 3:43pm*

**Statistics**

Thank you Fran!
*Tuesday, July 30, 2013 at 2:51pm*

**Statistics**

Thank you very much Fran. Do you know the others i posted?
*Tuesday, July 30, 2013 at 2:11pm*

**Statistics**

4) 9.13 5) 10.38
*Tuesday, July 30, 2013 at 1:55pm*

**statistics**

In a poll of 700 selected people in the USA who are 50 years or older, 20% said they would prefer a complete overhauling of the social security system. Estimate the population proportion of the USA of 50 years or older who would prefer a complete overhauling of the social ...
*Tuesday, July 30, 2013 at 1:52pm*

**statistics**

It is claimed the average age of employee in a large company is 50. A sample of 36 employees is taken and the average age was 49. The standard deviation of the population was 5. Use a level of significance of .05. What do you think of this claim?
*Tuesday, July 30, 2013 at 1:51pm*

**Statistics**

Yes, it is false
*Tuesday, July 30, 2013 at 12:47pm*

**Statistics**

oh.. Thank you I.G!!
*Tuesday, July 30, 2013 at 8:30am*

**Statistics**

Thank you. Do you know the 4 and 5?
*Tuesday, July 30, 2013 at 6:44am*

**Statistics**

answer is c
*Tuesday, July 30, 2013 at 2:58am*

**statistics**

35424
*Tuesday, July 30, 2013 at 12:46am*

**Statistics**

3) It's b
*Monday, July 29, 2013 at 11:39pm*

**Statistics**

True or False Question: A die is rolled 600 times. The face with six spots appears 112 times. Is the die biased towards that face, or is this just chance variation? Answer the question in Problem 6. 6) “The test concludes that the die is biased towards the face with six ...
*Monday, July 29, 2013 at 4:36pm*

**Statistics**

Multiple Choice: A die is rolled 600 times. The face with six spots appears 112 times. Is the die biased towards that face, or is this just chance variation? Answer the question in the steps outlined in Problems 1-6. 3) If the null hypothesis were true, the expected number of ...
*Monday, July 29, 2013 at 4:33pm*

**Statistics**

Multiple Choice: A die is rolled 600 times. The face with six spots appears 112 times. Is the die biased towards that face, or is this just chance variation? Answer the question in the steps outlined in Problems 1-6. 2) The alternative hypothesis is a) The die is biased b) The...
*Monday, July 29, 2013 at 4:29pm*

**Statistics**

Multiple Choice: A die is rolled 600 times. The face with six spots appears 112 times. Is the die biased towards that face, or is this just chance variation? Answer the question in the steps outlined in Problems 1-6. 1) The null hypothesis is: a) The die is biased towards the ...
*Monday, July 29, 2013 at 4:27pm*

**Math Statistics**

a. The standard error of the sample mean is 4.564/sqrt(36) = 0.7607 b. yes The mother's mean age student birth lie in interval (28.358, 30.928)
*Monday, July 29, 2013 at 4:11pm*

**statistics**

z = (186.3-200)/(30/sqrt(9)) z = -1.37, you can use your table
*Monday, July 29, 2013 at 3:38pm*

**statistics**

The length of country and western songs is normally distributed and has a mean of 200 seconds and a standard deviation of 30 seconds. Find the probability that a random selection of 9 songs will have mean length of 186.30 seconds or less. Assume the distribution of the lengths...
*Monday, July 29, 2013 at 3:14pm*

**Statistics**

A researcher surveyed college students to study their opinion about the proposed change in smoking rules. The researcher asked a group of 30 students: 12 of them supported the change, 13 of them did not, and 5 had no opinion. This is not a binomial model because... A. ...the ...
*Monday, July 29, 2013 at 2:56pm*

**Math Statistics**

5. Students in an introductory statistics class were asked to report the age of their mothers when they were born. Summary statistics include Sample size: 36 students Sample mean: 29.643 years Sample standard deviation: 4.564 years a. Calculate the standard error of this ...
*Monday, July 29, 2013 at 1:15pm*

**Statistics**

A fair game would be when the price of all the tickets sold is equal to the total prize money. That is $10600. So the price of one ticket would need to be just one-thousandth of that.
*Sunday, July 28, 2013 at 11:45pm*

**Math/Statistics**

probability = 13/(13+225) = 13/238 = 0.0546...
*Sunday, July 28, 2013 at 11:28pm*

**Statistics**

There is a $2 raffle with a first prize of $10000, a second prize of $500, and a 3rd prize of $100. If 1000 tickets are sold find the expected value. How much should the raffle ticket cost to make this a fair game?
*Sunday, July 28, 2013 at 10:38pm*

**Statistics**

True or False. Help please! Statistics' students of a class of Lyceum want to calculate the average number of chocolate pieces in a standard package of biscuits SANTAS. They choose a random sample of biscuits, measure chocolate pieces in each cookie and calculate the 95% ...
*Sunday, July 28, 2013 at 3:12pm*

**Business Statistics**

a. Best estimate of the population value = sample mean. b-e. http://www.google.com/search?client=safari&rls=en&q=t+test+statistics&ie=UTF-8&oe=UTF-8
*Sunday, July 28, 2013 at 12:54pm*

**Business Statistics**

The U.S. Dairy Industry wants to estimate the mean yearly milk consumption. A sample of 16 people reveals the mean yearly consumption to be 60 gallons with a standard deviation of 20 gallons. a. What is the value of the population mean? What is the best estimate of this value...
*Sunday, July 28, 2013 at 12:47pm*

**Math Statistics**

It seems like you do not have a normal distribution, since the confidence interval goes from .003 below to .013 above .50. The confidence interval is determined by the standard error of the mean (SEm). SEm = SD/√n From your data, you would have an extreme large n. ...
*Sunday, July 28, 2013 at 12:45pm*

**Statistic/Psychology**

Do you mean standard error (SEm) or standard deviation (SD). SEm = SD/√n, but no n is indicated. If you meant SD, then use this equation. Z = (score-mean)/SD Find table in the back of your statistics text labeled something like "areas under normal distribution"...
*Sunday, July 28, 2013 at 12:34pm*

**statistics**

Equations are the same. Z = (score-mean)/SD For the second one, find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z scores. For the last problem, use the same ...
*Sunday, July 28, 2013 at 12:22pm*

**statistics**

Can you please tell me how to solve for the following? Pedro took an exam in a class in which the mean was 64 with a standard deviation of 6. If his z score was +3, what was his exam score? A students commute to school is normally distributed with a mean of 31 min and a ...
*Sunday, July 28, 2013 at 11:37am*

**Math Statistics**

2. A statistics professor has asked his students to flip coins over the years. He has kept track of how many flips land heads and how many land tails. Combining the results of his students over many years, he has formed a 95% confidence interval for the long-run population ...
*Saturday, July 27, 2013 at 2:19pm*

**Statistics**

I am confused.. maybe is D. I am copying this paragraph from wikipedia. Meaning and interpretation[edit] For users of frequentist methods, various interpretations of a confidence interval can be given. The confidence interval can be expressed in terms of samples (or repeated ...
*Saturday, July 27, 2013 at 9:16am*

**Statistic/Psychology**

If the correlation between one's interest in statistics and being a "fun date" was -0.70, it would mean that: a. The higher someone's interest was in statistics, the more likely it would be that he or she is a fun date b. The higher someone's interest was...
*Friday, July 26, 2013 at 7:08pm*

**Statistics**

Thank you PsyDAG. Are yousure about B? I believe that B is correct but maybe A is correct. I have to choose only one.. You believe B is absolutely correct?? Can you help me and with the other one please?
*Friday, July 26, 2013 at 4:57pm*

**Statistics**

(A-C) Z = (score-mean)/SD Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportions/probabilities related to the Z scores. Reverse the process with the 60% (.60). (D) Here you are dealing with a ...
*Friday, July 26, 2013 at 2:05pm*

**Statistics**

A may or may not be true, but B definitely is. Statistics deal with probabilities. You would expect about 95 of 100 to be within the limits, but may not find that exact number.
*Friday, July 26, 2013 at 1:52pm*

**Statistics**

Oh no.. Maybe the correct answer is A!!
*Friday, July 26, 2013 at 7:33am*

**Statistics**

Multiple Choice Which of the following statements is true about the 95% confidence interval of the average of a sample? A) 95 of 100 avgs of samples will be within the limits of the confidence interval. B) There is a 95% chance the avg of the population to be within the limits...
*Friday, July 26, 2013 at 6:00am*

**Statistics**

I forgot to state my answer. 1) True 2) False 3) True 4) False. Do you agree?
*Friday, July 26, 2013 at 5:52am*

**Statistics**

True or False Questions. Statistics' students of a class of Lyceum want to calculate the average number of chocolate pieces in a standard package of biscuits SANTAS. They choose a random sample of biscuits, measure chocolate pieces in each cookie and calculate the 95% ...
*Friday, July 26, 2013 at 5:49am*

**Statistics**

The inside diameter of the automobile wheel bearing sets at a factory is expected to be normally distributed with a mean of 1.30inches and a standard deviation of 0.04 inches. What is the probability that a randomly selected wheel bearing will have an inside diameter of, a) ...
*Thursday, July 25, 2013 at 7:56pm*

**Probability & Statistics**

jkhjkahfjkha
*Thursday, July 25, 2013 at 6:18pm*

**statistics**

z = (300-300)/(39/sqrt(700)) z = (378-300)/(39/sqrt(700))
*Thursday, July 25, 2013 at 5:56pm*

**statistics**

The scores for standardized test are normally distributed with a mean of 300 and standard deviation of 39. If the test is given to 700 students, how many are expected to have scores between 300 and 378.
*Thursday, July 25, 2013 at 5:51pm*

**statistics**

A simple random sample of voters will be taken in a large state. Researchers will use the methods of our course to construct an approximate 95% confidence interval for the percent of the state’s voters who will vote for Candidate X. The minimum sample size needed to ...
*Thursday, July 25, 2013 at 8:07am*

**psychology**

15. Maria is a Hispanic female, Natasha is a Black female, and Joan is a White female. Each has a high school level education but no work . Statistics show that ..
A. Natasha will earn less than Maria
B. Joan will earn less than Natasha
...
*Thursday, July 25, 2013 at 7:34am*

**Math Statistics**

Students enrolled in an introductory statistics course at a university were asked to take a survey that indicated whether the student has a visual or verbal learning style. Of the 39 students who took the survey, 25 were judged to have a visual learning style and 14 were ...
*Thursday, July 25, 2013 at 1:09am*

**statistics**

Let's see. Can you multiply 1.96 by 100 and add/subtract that from 500?
*Thursday, July 25, 2013 at 12:26am*

**statistics**

ok...i'm still looking for an aswer. be.t 330 and 630 ect?
*Wednesday, July 24, 2013 at 11:00pm*

**Statistics**

4.1
*Wednesday, July 24, 2013 at 9:12pm*

**statistics**

95% lie within 1.96 SD of the mean.
*Wednesday, July 24, 2013 at 5:50pm*

**statistics**

Suppose that the average score on the GMAT exam is 500 and that the standard deviation of all scores is 100 points. You would expect approximately 95% of all GMAT scores to be between
*Wednesday, July 24, 2013 at 5:37pm*

**English.....**

The following passage is taken from an article by a contemporary poet about Clement Clarke Moore, the nineteenth-century writer best known as the author of “A Visit From Saint Nicholas.” If he wasn’t a myth maker himself, at least Clement ...
*Wednesday, July 24, 2013 at 1:16pm*

**STATISTICS**

The probabilities of colors of each pill are independent. Let m[n] = C, be the event that the [n]th pill is a color (C). eg: P(m1=Blue) = 0.12 (1) P(m1=Blue and m2=Blue) = P(m1=Blue) P(m2=Blue) (2) P(m1<>Red and m2<>Red) = (1-P(m1=Red))(1-P(m2=Red)) (3) P(m1=Red or...
*Wednesday, July 24, 2013 at 4:56am*

**STATISTICS**

Alternatively: It's the complement of the probability that none of them is among that group. Let E[n] be the indexed event that the [n]th person selected is not one of the three oldest. 1 - P(E1) P(E2|E1) P(E3|E1 and E2) = 1 - (9/12) (8/11) (7/10) = 0.61818....
*Wednesday, July 24, 2013 at 4:32am*

**STATISTICS**

Hint: It's the complement of the probability that none of them is among that group. Let En be the indexed event that the nth person selected is not one of the three oldest. 1 - P(E1) P(E2|E1) P(E3|E1 and E2) = 1 - (9/12) (8/11) (7/10) = 0.61818....
*Wednesday, July 24, 2013 at 4:29am*

**Statistics**

For a 95% confidence interval, 95% of the sample lie within (μ - 1.96 σ/√n) and (μ + 1.96 σ/√n). Thus the width of the interval is: 3.92 σ/√n So we need to find: n = (3.92 σ/ 6%)² To do this we need to know (or ...
*Wednesday, July 24, 2013 at 4:11am*

**Statistics**

Any ideas please? Simple random sample of voters will be taken in a large state. Researchers will construct an approximate 95% confidence interval for the percent of the state¢s voters who will vote for Candidate A. Find the minimum sample size needed to ensure that the ...
*Wednesday, July 24, 2013 at 3:17am*

**STATISTICS**

There are 12C3 = 220 ways, group of 3 people from 12 There are 9C3 = 84 ways, none of the three oldest. 220-84 = 136 groups where at least one member is 3 oldest. 136/220 = 0..618
*Wednesday, July 24, 2013 at 12:56am*

**STATISTICS**

From a group of 12 people, you randomly select 3 of them. Find the probability that at least one of them is among the 3 oldest people in the group
*Wednesday, July 24, 2013 at 12:34am*

**STATISTICS**

According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. Compute the probability that two randomly selected peanut M&M’s are both blue. If you ...
*Wednesday, July 24, 2013 at 12:34am*

**STATISTICS**

From a group of 12 people, you randomly select 3 of them. Find the probability that at least one of them is among the 3 oldest people in the group
*Wednesday, July 24, 2013 at 12:02am*

**statistics (incomplete)**

We do not have your text with the chapter. However, you need to realize the social security numbers are only a nominal scale. http://drdavespsychologypage.intuitwebsites.com/Two___Two_____four.pdf
*Tuesday, July 23, 2013 at 7:06pm*

**statistics**

tr
*Tuesday, July 23, 2013 at 6:02pm*

**life orientation**

identify and dercribe 3 environmental health hazards that cause ill health,crises,and or disasters within ur community or any other community within s.a and globally.include evidence that is current of the identified issues(e.g graphs and statistics)
*Tuesday, July 23, 2013 at 4:13pm*

**statistics**

xBar > 50 => {49+61, 49+62, 61+62} => P(xBar>50)=3/7C2=3/28 xBar>60 => {61+62} => P(xBar>60)=1/7C2=1/28
*Tuesday, July 23, 2013 at 8:13am*

**Math Statistics**

3. Suppose 20% of all heart transplant patients do not survive the operation. a. Think about taking repeated random samples of 371 patients from this population. Describe how the sample proportion who die would vary from sample to sample. (Hint: Be sure to refer to the shape, ...
*Monday, July 22, 2013 at 11:50pm*

**statistics**

Suppose that two employees have to be fired from a group of seven: • Amy, female, age 35 • Bob, male, age 41 • Chad, male, age 43 • Diana, female, age 44 • Elvis, male, age 49 • Frank, male, age 61 • Ginger, female, age 62 Determine the ...
*Monday, July 22, 2013 at 11:24pm*

**statistics**

A government researcher wants to conduct a study to determine if there is a correlation between social security numbers and income. He collects the paired data from a random sample of 100 people. Should the methods of this chapter be used with the linear correlation ...
*Monday, July 22, 2013 at 9:39pm*

**stats (Partial)**

1. Correct. 2-7. I don't know how to solve without a measure of variability. 8-10. Z = (mean1 - mean2)/standard error (SE) of difference between means SEdiff = √(SEmean1^2 + SEmean2^2) SEm = SD/√n If only one SD is provided, you can use just that to determine ...
*Monday, July 22, 2013 at 12:54pm*

**Statistics**

I believe that: a) is False b) is True c) Is False. Any suggestions?
*Monday, July 22, 2013 at 4:27am*

**Statistics**

True or False Question. I need help please. A sientific paper reports the results of a drug test. This medicine used to reduce vision loss in people suffering from macular degeneration. The article state p = 0,04 section findings. The following issues are of three different ...
*Monday, July 22, 2013 at 4:27am*

**statistics**

Please help this question A simple random sample of voters is taken from the voters in a large state. Using the methods of our course, researchers construct an approximate 99% confidence interval for the percent of the state’s voters who will vote for Candidate A. The ...
*Monday, July 22, 2013 at 2:02am*

**statistics**

Thank you very much PsyDAG.
*Monday, July 22, 2013 at 2:02am*

**statistics**

A simple random sample of voters is taken from the voters in a large state. Using the methods of our course, researchers construct an approximate 99% confidence interval for the percent of the state’s voters who will vote for Candidate A. The interval goes from 37.3% to ...
*Monday, July 22, 2013 at 1:58am*

**sociolgy**

I haven't seen the statistics on this -- so my guess would be either sciences or applied sciences. What does your book say?
*Sunday, July 21, 2013 at 8:19pm*

**statistics**

Didn't understand Please answer.
*Sunday, July 21, 2013 at 2:23pm*

**statistics**

Please only post your questions once. Repeating posts will not get a quicker response. In addition, it wastes our time looking over reposts that have already been answered in another post. Thank you.
*Sunday, July 21, 2013 at 1:36pm*

**statistics**

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability (.34) and its Z score (score in terms of SD). A. 68% = mean ± 1 SEm SEm = SD/√n B. 68% = mean ± 1 SD
*Sunday, July 21, 2013 at 1:35pm*

**statistics**

1. A simple random sample of 400 students is taken at a large university. The average height of the sampled students is 68 inches and the SD is 2 inches. The distribution of heights in the sample follows the normal curve very closely. An approximate 68% confidence for the ...
*Sunday, July 21, 2013 at 9:42am*

**college statistics**

student of fortune has closed so all the users are at aceyourcollegeclasses . co m
*Sunday, July 21, 2013 at 5:26am*

**Statistics**

Yeah... I think you are absolutely correct. Also from the city is very possible to be there in 10 minutes so he will pay more for the parking. I changed my mind... Thank you a lot.
*Sunday, July 21, 2013 at 4:55am*

**statistics**

1. A simple random sample of 400 students is taken at a large university. The average height of the sampled students is 68 inches and the SD is 2 inches. The distribution of heights in the sample follows the normal curve very closely. An approximate 68% confidence for the ...
*Sunday, July 21, 2013 at 4:38am*

**Vocabulary**

choose the term that matches the definition. building and construction. a.architecture b. engineering c.nursing d.statistics b
*Saturday, July 20, 2013 at 10:34pm*

**Statistics**

I'm looking at it from a practical standpoint since no other criteria seems relevant. By going through the countryside, he knows within a couple of minutes when he will arrive. If he chooses the city, then he'll have to leave at least 20 minutes before class even ...
*Saturday, July 20, 2013 at 8:09pm*

**Statistics**

S. Sue, Thank you. To be honest i was not sure about c.. I am between a and c.. More positive on c.. Are you sure?
*Saturday, July 20, 2013 at 7:59pm*

**Statistics**

I'd choose a because of the consistency of time. Besides, the countryside is a more pleasant drive.
*Saturday, July 20, 2013 at 7:53pm*

**Statistics**

I need help with this please. It is a multiple choice question, so choose one from a,b,c please. I believe the correct is c. What do you think? Ari lives about 10 minutes away from the college to which he intend to attend a summer seminar of 10 weeks. There are two main routes...
*Saturday, July 20, 2013 at 7:46pm*

**Statistics**

Dear MathMate, Thank you for the paper it will be very usefull for me! As I understand from this paper i was correct? a) is False b) is True c) Is False. Thank you in advance.
*Saturday, July 20, 2013 at 7:35pm*

**Statistics**

The following reference may confirm your assumptions. http://cjasn.asnjournals.org/content/3/5/1246.full
*Saturday, July 20, 2013 at 7:03pm*

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