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April 17, 2014

April 17, 2014

**Recent Homework Questions About Statistics**

Post a New Question | Current Questions

**statistics**

1. In an ANOVA, one group has a much larger sample mean than the other. The analyst decides to remove this group and to conduct the analysis on the remaining groups only. Which of the following statements is correct? Select one: a. This analysis is not correct, as now the ...
*Monday, October 14, 2013 at 7:36am*

**Statistics**

69
*Monday, October 14, 2013 at 12:43am*

**statistics**

A sample has a mean of M 40 If a score of X 55 is removed from the sample then the sample mean will increase
*Sunday, October 13, 2013 at 6:27pm*

**STAT**

Given a sample size of 18, with sample mean 660.3 and sample standard deviation 95.9, we are to perform the following hypothesis testing: Null Hypothesis H0 : µ = 700 Research Hypothesis H1 : µ ≠ 700 •What is the test statistics? •At a 0.05 ...
*Sunday, October 13, 2013 at 9:15am*

**math**

Our statistics students, as noted in Exercise 6.32, were asked to rate their admiration of Hillary Rodham Clinton on a scale of 1 to 7. They also were asked to rate their admiration of Jennifer Lopez and Venus Williams on a scale of 1 to 7. As noted earlier, the mean rating of...
*Saturday, October 12, 2013 at 11:23pm*

**math**

A sample of 148 of our statistics students rated their level of admiration for Hillary Rodham Clinton on a scale of 1 to 7. The mean rating was 4.06, and the standard deviation was 1.70. (For this exercise, treat this sample as the entire population of interest.) a. Use these ...
*Saturday, October 12, 2013 at 11:20pm*

**STAT**

The weights of the 100 students in an introductory statistics class are normally distributed, with a mean of 170 pounds and a standard deviation of 5 pounds. How many students would you expect to have weight between 162 pounds and 178 pounds? What is the probability that a ...
*Saturday, October 12, 2013 at 9:26pm*

**College probability and statistics**

3 letters ---> 26^3 3 numbers, assuming it may start with a zero --- 10^4 number of plates = 26^3 (10^4) = 175760000 (about 176 million, long way to go) ii) so only 24 letters, and 8 numbers -- what do you think? iii) look at the letter part first: assume we put CC at the ...
*Saturday, October 12, 2013 at 9:18pm*

**College probability and statistics**

The current license plates in New York State consist of three letters followed by four digits. ( i ) How many possible distinct license plates can there be? ( ii ) How many possible distinct license plates could there be if the letters O and I and the digits, 0 and 1 were ...
*Saturday, October 12, 2013 at 5:30pm*

**statistics**

5x4x3
*Saturday, October 12, 2013 at 2:59pm*

**STAT**

The weights of the 100 students in an introductory statistics class are normally distributed, with a mean of 170 pounds and a standard deviation of 5 pounds. 1)How many students would you expect to have weight between 162 pounds and 178 pounds? 2)What is the probability that a...
*Saturday, October 12, 2013 at 12:32pm*

**STAT**

The weights of the 100 students in an introductory statistics class are normally distributed, with a mean of 170 pounds and a standard deviation of 5 pounds. How many students would you expect to have weight between 162 pounds and 178 pounds?
*Saturday, October 12, 2013 at 12:31pm*

**STAT**

Given a sample size of 18, with sample mean 660.3 and sample standard deviation 95.9, we are to perform the following hypothesis testing: Null Hypothesis H0 : µ = 700 Research Hypothesis H1 : µ ≠ 700 •What is the test statistics? •At a 0.05 ...
*Saturday, October 12, 2013 at 12:27pm*

**statistics**

p(at least 5 have the same month) p(someone shows w/ at least someone else) P(s)+ P(d) = 100 % 100%- P(d) (12 *11*10*9*8)/12^5 P(d) =95040/248832 = .3819 100% -0.3819 = 0.6181 61.81%
*Friday, October 11, 2013 at 5:03pm*

**statistics**

37
*Friday, October 11, 2013 at 4:27pm*

**statistics**

37
*Friday, October 11, 2013 at 4:26pm*

**statistics**

37
*Friday, October 11, 2013 at 4:26pm*

**statistics**

37
*Friday, October 11, 2013 at 4:26pm*

**statistics**

How many friends must you have to guarantee that at least five of them will have birthdays in the same month?
*Friday, October 11, 2013 at 2:35pm*

**statistics**

Hi Shanice, Numbers in total : 1,2,3,4,5,6,7,8 In the first draw : 2 was selected, therefore the probability of drawing a 2 is 1/8. (since there is only one 2 in the list) In the second draw, 3 was selected. The probability is again 1/8. Therefore the overall probability is: 1...
*Friday, October 11, 2013 at 2:44am*

**college statistics**

7. Mary goes into the supermarket. The probability that she buys (a) regular coffee is .30, (b) decaffeinated coffee is .40, and (c) that she buys both is .30. What is the probability that she buys regular coffee, decaffeinated coffee, or both?
*Thursday, October 10, 2013 at 10:51pm*

**college statistics**

2. A researcher has developed a new questionnaire for measuring dominance and would like to estimate the population parameters for the test scores. The questionnaire is administered to a sample of n = 25 subjects. This sample has an average score of mean = 43 with SS = 2400. ...
*Thursday, October 10, 2013 at 10:51pm*

**statistics**

6. Out of eight numbers, what is the probability of drawing a two on the first draw and a three on the second draw using sampling with replacement?
*Thursday, October 10, 2013 at 10:41pm*

**statistics**

5. Find the weighted mean of the following two samples. Sample 1: n = 5 and the mean = 20 Sample 2: n = 15 and the mean = 10.
*Thursday, October 10, 2013 at 10:40pm*

**statistics**

2. A researcher has developed a new questionnaire for measuring dominance and would like to estimate the population parameters for the test scores. The questionnaire is administered to a sample of n = 25 subjects. This sample has an average score of mean = 43 with SS = 2400. ...
*Thursday, October 10, 2013 at 10:39pm*

**statistics**

You can try a proportional one-sample z-test for this one since this problem is using proportions. Here's a few hints to get you started: Null hypothesis: Ho: p = .759 -->meaning: population proportion is equal to .759 (converting the 75.9% to a decimal). Alternative ...
*Thursday, October 10, 2013 at 4:31pm*

**statistics**

Find the operating characteristics of this system. An airport ticket counter has a service rate of 180 per hour, exponentially distributed, with Poisson arrivals at the rate of 120 per hour
*Thursday, October 10, 2013 at 11:44am*

**statistics**

In 2006, 75.9% of first-year students said they used the Internet for research or homework. Administrators found that 168 of an SRS of 200 first-year students used the Internet for research or homework. Is the proportion of first-year students who used the Internet for ...
*Wednesday, October 9, 2013 at 10:29pm*

**statistics**

Z = (score-mean)/SEm SEm = SD/√n Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z score.
*Wednesday, October 9, 2013 at 11:54am*

**statistics**

Assume that a population is normally distributed with a mean of 100 and a standard deviation of 15. Would it be unusual for the mean of a sample of 3 to be 115 or more? Why or why not? how can i write this in a mathematical expression?
*Wednesday, October 9, 2013 at 3:51am*

**Statistics**

SEdiff = √(SEmean1^2 + SEmean2^2) SEm = SD/√n
*Tuesday, October 8, 2013 at 1:51pm*

**Statistics**

Z = (score-mean)/SEm SEm = SD/√n Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the z score.
*Tuesday, October 8, 2013 at 1:45pm*

**statistics**

Z = (mean1 - mean2)/standard error (SE) of difference between means SEdiff = √(SEmean1^2 + SEmean2^2) SEm = SD/√n If only one SD is provided, you can use just that to determine SEdiff. Find table in the back of your statistics text labeled something like "...
*Tuesday, October 8, 2013 at 1:31pm*

**Business Statistics**

Using the telephone numbers listed in your local directory as your population, randomly obtain 20 samples of size 3. From each telephone number identified as a source, take the fourth, fifth, and sixth digits. Calculate the mean of the 20 samples Draw a histogram showing the ...
*Tuesday, October 8, 2013 at 12:12pm*

**statistics (?)**

Is the probability the same for all 4? What does the "it" refer to?
*Tuesday, October 8, 2013 at 12:10pm*

**Statistics**

Compute SEdiff Mean1=23 Mean2=18 SD1 =4 SD2 =6 N1 =9 N2 =6
*Tuesday, October 8, 2013 at 11:42am*

**statistics**

To see whether people are keeping their car tires inflated to the correct level of 35 pounds per square inch (psi), a tire company manager selects a sample of 36 tires and checks the pressure. The mean of the sample is 33.5 psi, and the population standard deviation is 3 psi. ...
*Monday, October 7, 2013 at 8:31pm*

**Statistics**

An April 15, 2002 report in Time Magazine stated that the average age for women to marry in the United States is now 25.9 years of age. If the standard deviation is assumed to be 4.3 years, find the probability that a random sample of 32 U.S. women would show a mean age at ...
*Monday, October 7, 2013 at 5:39pm*

**STAT (?)**

What following statements? Z = (mean1 - mean2)/standard error (SE) of difference between means SEdiff = √(SEmean1^2 + SEmean2^2) SEm = SD/√n If only one SD is provided, you can use just that to determine SEdiff. Find table in the back of your statistics text ...
*Monday, October 7, 2013 at 1:55pm*

**Statistics (incomplete)**

You have no measure of variability. Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportions/probabilities in terms of Z scores. Z scores is your score in terms of standard deviations. Z = (score-...
*Monday, October 7, 2013 at 1:46pm*

**Statistics**

How do I find the deviation of each x-value from the expected value of 0.97? The chart looks like this... x P(x) x-u 0 0.24 ? 1 0.55 ? 2 0.21 ?
*Sunday, October 6, 2013 at 8:53pm*

**Statistics**

1a. Find the mean first = sum of scores/number of scores Subtract each of the scores from the mean and square each difference. Find the sum of these squares. Divide that by the number of scores to get variance. Standard deviation = square root of variance Range = highest score...
*Sunday, October 6, 2013 at 2:37pm*

**statistics**

suppose x is a uniform random variable with c=40 ana d= 70 find the probability that a randomly selected observation is between 43 and 65
*Sunday, October 6, 2013 at 12:54pm*

**Statistics**

Try the binomial probability table: n = 10 x = 5 p = .20 q = 1 - p = 1 - .20 = .80 You can use the table, or calculate by hand using the following formula: P(x) = (nCx)(p^x)[q^(n-x)] With your data using the formula: P(5) = (10C5)(.20^5)[.80^(10-5)] I'll let you take it ...
*Saturday, October 5, 2013 at 6:05pm*

**Statistics**

A manufacturer ship toasters in cartons of 10. In each carton, they estimate a 20% chance that one of the toasters will need to be sent back for minor repairs. What is the probability, that in one carton there will be 5 toasters that need repair? I have no idea on where to ...
*Saturday, October 5, 2013 at 5:20pm*

**Statistics**

A small software company bids on two contracts. It anticipates a profit of $60,000 if it gets the larger contract and $25,000 if it gets the smaller contract. The company estimates that there is a 32% chance it will get the larger contract and a 62% chance it will get the ...
*Saturday, October 5, 2013 at 5:17pm*

**Statistics**

1. A simple random sample of FICO credit rating scores is listed below: 714 751 664 789 818 779 698 836 753 834 693 802 a. Find range, variance, and standard deviation. b. As of this writing, the mean FICO score was reported to be 678. Based on these results, is a FICO score ...
*Saturday, October 5, 2013 at 3:55pm*

**Statistics**

How can you have a probability greater than 1? If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events. "Forty-six percent of students eat breakfast and also floss their teeth."
*Saturday, October 5, 2013 at 1:37pm*

**Statistics**

Please only post your questions once. Repeating posts will not get a quicker response. In addition, it wastes our time looking over reposts that have already been answered in another post. Thank you. See your later post.
*Saturday, October 5, 2013 at 1:33pm*

**Statistics**

The first two need to be non-Jacks. First card = (52-4)/52 With one card gone, the second card = (51-4)/51 The third card needs to be the Jack = 4/50 If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of ...
*Saturday, October 5, 2013 at 1:25pm*

**Statistics**

You are dealt a hand of three cards, one at a time. Find the probability that your third card is your first jack. A) 0.068 B) 0.145 C) 0.127 D) 0.077 E) 0.00018 How do I set this problem up?
*Saturday, October 5, 2013 at 9:28am*

**Statistics**

In an Intro Stats class, 57% of students eat breakfast in the morning and 80% of students floss their teeth. Forty-six percent of students eat breakfast and also floss their teeth. What is the probability that a student from this class eats breakfast given they floss their ...
*Friday, October 4, 2013 at 7:58pm*

**Statistics**

You are dealt a hand of three cards, one at a time. Find the probability that your third card is your first jack. A) 0.068 B) 0.145 C) 0.127 D) 0.077 E) 0.00018
*Friday, October 4, 2013 at 7:54pm*

**statistics**

Mean = np SD = √npq n = 200 p = 1/6 q = 1 - p = 5/6 Therefore: Mean = 200(1/6) = 33.33 SD = √[200(1/6)(5/6)] = 5.27 Use z-scores: z = (x - mean)/SD z = (30 - 33.33)/5.27 = -0.63 Check a z-table for the probability. (Remember the problem is asking "at most 30&...
*Friday, October 4, 2013 at 7:51pm*

**statistics**

Try using a binomial proportion CI formula: CI95 = p + or - 1.96(√pq/n) ...where p = proportion in the problem, q = 1 - p, n = sample size, √ = square root, and + or - 1.96 represents 95% CI using a z-table. Your data: p = .3 q = .7 n = 850 Substitute values into ...
*Friday, October 4, 2013 at 7:36pm*

**Statistics**

Hypotheses: H0: µ ≤ 1.6 H1: µ > 1.6 Test is one-tailed (H1 shows a specific direction). Use a one-sample z-test: z = (1.75 - 1.6)/(0.85/√101) Finish the calculation, then determine whether or not to reject the null hypothesis (H0). If the null is ...
*Friday, October 4, 2013 at 7:32pm*

**Statistics**

.271
*Friday, October 4, 2013 at 4:57pm*

**Statistics**

From your description, I'm not sure what is being asked. If it is "either blue or green," you are right. If it is just green ("green notepad is selected"), then 1/4 is correct.
*Friday, October 4, 2013 at 1:20pm*

**statistics**

Z = (score-mean)/SEm SEm = SD/√n Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z score.
*Friday, October 4, 2013 at 1:09pm*

**Statistics**

95% = mean ± 1.96 SD Insert values and calculate.
*Friday, October 4, 2013 at 1:02pm*

**Statistics**

The American Academy of Pediatrics (AAP) recommends that kids 2-5 years old watch no more than (on average) 1.6 hours a day of quality programming. A researcher selected a sample of 101 kids in the neighborhood and asked their parents how many hours per day they allow their ...
*Friday, October 4, 2013 at 12:32pm*

**Statistics**

1.The average number of acts of physical violence in a random sample of 150 TV movies was 4.5 acts with a standard deviation of 0.75. At the 95% confidence interval level, what is your estimation of the mean range of all movies shown in the television? Explain the result in ...
*Friday, October 4, 2013 at 12:31pm*

**statistics**

2. The National polling organization conducted a phone survey of 850 American adults on what they considered to be the most serious problem facing nation’s public schools; 30% said violence. This sample percent is an estimate of the percent of all adults who think that ...
*Friday, October 4, 2013 at 12:30pm*

**statistics**

Use the normal dist to approx the desired prob. Find the prob of getting at most 30 fives in 200 tosses of a fair 6 sided die
*Friday, October 4, 2013 at 10:20am*

**statistics**

An April 15, 2002 report in Time Magazine stated that the average age for women to marry in the United States is now 25.6 years of age. If the standard deviation is assumed to be 4.1 years, find the probability that a random sample of 30 U.S. women would show a mean age at ...
*Friday, October 4, 2013 at 1:32am*

**Statistics: IQ Score (X) and Exam Score (Y)**

The producers of a new toothpaste claim that it prevents more cavities than other brands of toothpaste. A random sample of 60 people used the new toothpaste for 6 months. The mean number of cavities at their next check up is 1.5 in the general population the mean # of cavities...
*Thursday, October 3, 2013 at 11:03pm*

**Statistics**

A package of self-sticking notepads contains 6 yellow, 6 blue, 6 green, and 6 pink notepads. An experiment consists of randomly selecting one of the notepads and recording its color. Find the probability that a green notepad is selected given that it is either blue or green. A...
*Thursday, October 3, 2013 at 8:09pm*

**Statistics**

Yes.
*Thursday, October 3, 2013 at 12:47pm*

**Statistics**

Yes.
*Thursday, October 3, 2013 at 12:46pm*

**Statistics**

i don't no the answer
*Thursday, October 3, 2013 at 12:18pm*

**Statistics**

Sorry for the 2nd post...please omit...
*Wednesday, October 2, 2013 at 7:25pm*

**Statistics**

In a survey conducted by researchers at the University of Wisconsin, subjects were asked the question "Have you ever used cocaine?" in one of three methods, anonymous survey, personal interview, or phone survey. The contingency table below shows the results of this ...
*Wednesday, October 2, 2013 at 7:24pm*

**Statistics**

In a survey conducted by researchers at the University of Wisconsin, subjects were asked the question "Have you ever used cocaine?" in one of three methods, anonymous survey, personal interview, or phone survey. The contingency table below shows the results of this ...
*Wednesday, October 2, 2013 at 6:49pm*

**Statistics**

If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events. First shirt = category/total = 11/30 Second shirt, since one XL shirt is gone = 10/29 Third shirt, since two XL are gone = 9/28 ...
*Wednesday, October 2, 2013 at 5:05pm*

**Statistics**

Forty-six percent of students eat breakfast and also floss their teeth.
*Wednesday, October 2, 2013 at 2:36pm*

**Stats**

Z = (score-mean)/SD Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability (.10) and its related Z score. Insert with other data in equation above and solve.
*Wednesday, October 2, 2013 at 1:57pm*

**College Statistics**

According to the experian automotive, 35% of all car owning households have three or more cars. In a random sample 20 car owning households, what is the probability that exactly 6 have three or more cars?
*Tuesday, October 1, 2013 at 11:30pm*

**Statistics**

10.12
*Tuesday, October 1, 2013 at 9:23pm*

**Statistics**

1. SUV = .12, V = .24. .12 + .24 ≠ .54 2. right 3. right, however, there is a problem with the missing .10. If it is included, it would be (1-.38)^3. = .62^3 = .388244 4. .16 + .16^2 + .16^3 = .238328 5. again to include the .10, (1-.12)^2 = .88^2 = .7744
*Tuesday, October 1, 2013 at 8:08pm*

**Statistics**

In an Intro Stats class, 57% of students eat breakfast in the morning and 80% of students floss their teeth. Forty-six percent of students eat breakfast and also floss their teeth. What is the probability that a student from this class flosses his/her teeth given they eat ...
*Tuesday, October 1, 2013 at 7:59pm*

**Statistics**

The soccer team's shirts have arrived in a big box and people start grabbing them. The box contains 7 medium, 12 Large, and 11 extra-large shirts. What is the probability that the first 4 shirts are all extra large? I have been struggling with the problem for an hour and ...
*Tuesday, October 1, 2013 at 7:06pm*

**College Statistics**

Suppose we want to model the number of rats captured in a single trap in a day, where the average number caught is 5 (i.e. X ∼ Poi(5)). (a) What is the probability of catching 6 rats in one trap in a day? (b) What is the probability of catching 12 rats in 2 traps in a ...
*Monday, September 30, 2013 at 9:09pm*

**College Statistics**

For X ∼ Bin(n, p), show that E(X) = np and Var(X) = np(1 − p) Our book defines this as true, but I don't know how to actually prove it.
*Monday, September 30, 2013 at 9:07pm*

**Statistics (Reiny)**

1. A consumer organization estimates that 30% of the households in a particular community have one television set, 39% have two sets, and 20% have three or more sets. What is the probability that a household chosen at random does not have two sets? A) 0.39 B) 0.80 C) 0.61 D) 0...
*Monday, September 30, 2013 at 7:51pm*

**Statistics**

No typo, that is how the question reads. Can you check my answers? 1. 0.54 2. 0.52 3. 0.140608 4. 0.405224 5. 0.4746
*Monday, September 30, 2013 at 4:04pm*

**Statistics**

Probabilities only add to .90. Is the remaining .10 people who decided not to rent, or do you have a typo? 1. Either-or probabilities are found by adding the individual probabilities. 2. .16 + .12 + .24 = ? 3. If the events are independent, the probability of both/all events ...
*Monday, September 30, 2013 at 2:57pm*

**Statistics**

Ricardo's car rental offers five different types of vehicles, compact cars (CC), midsize cars (MC), sport utility vehicles (SUV), vans (V), and luxury cars (L). Historically, if a random individual comes to rent a vehicle, the following probabilities apply: P(CC) = 0.16 P(...
*Monday, September 30, 2013 at 2:35pm*

**math **

find an advertisement for a weight loss product either online or in the print media, the more unbelievable the claims, the better a. What data does it offer for its promised benefits? Does it offer any descriptive statistics or merely testimonials? if it offers descriptive ...
*Monday, September 30, 2013 at 10:25am*

**Statistics **

1. A human gene carries a certain disease from a mother to her child with a probability rate of 0.58. That is, there is a 58% chance that the child becomes infected with the disease. Suppose a female carrier of the gene has five children. Assume that the infections, or lack ...
*Sunday, September 29, 2013 at 10:52pm*

**Statistics**

Thank you!
*Sunday, September 29, 2013 at 10:49pm*

**Statistics**

your #1 is correct #2. if prob(making A) = 15% then prob(not making A) = 100%-15% = 85% #3. to make A or B = 15% + 20% = 35% (since A and B are independent events, that is, you can't make both an A and a B), we can just add them up so prob(not making A or B) = 100-35 or 65...
*Sunday, September 29, 2013 at 8:45pm*

**Statistics**

1. In a certain game, the probability of getting a red outcome is 0.03. Find the probability of getting an outcome that is not red? The answer must be in a decimal. I put 0.97 as the answer ( 1-0.03=0.97) 2. The instructor in a Humanities class says that students have a 15% ...
*Sunday, September 29, 2013 at 7:27pm*

**Statistics/Math**

wef
*Sunday, September 29, 2013 at 3:50pm*

**statistics,math**

Pearson would use two variables to find their relationship, like height and weight. Choose your own behavioral variables. Chi square would use categories, like college majors of graduates by gender. Choose your own behavioral variables.
*Sunday, September 29, 2013 at 1:38pm*

**Probability and Statistics (Continuation)**

Katie, you were right, there should have been 3 successes and 2 failures, which would be 6( .9^3)(.1^2) Don't know why I miscounted. in my "prob( a specific 2F,2S, with S at end) = (.9^2)(.1^2)(.1) = .00081 " I had the first part correct, with 2F's and 3S'...
*Sunday, September 29, 2013 at 1:27pm*

**Probability and Statistics (Continuation)**

Assume 10% of the engines manufactured on an assembly line are defective. If engines are randomly selected one at a time and tested. What is the probability that the third nondefective engine will be found a)on the fifth trial? b) on or before the fifth trial? MY answers: a) P...
*Sunday, September 29, 2013 at 1:10pm*

**Probability and Statistics**

If I understand correctly, there are 5 trials and you are expecting 3 S's and 2 F's, (S = success, F = failure) defective - F -----> prob(F) = .1 non-defective - S --> prob(S) = .9 a) you want an S in the 5th spot e.g. SFFSS is one of these number of ways for ...
*Sunday, September 29, 2013 at 8:14am*

**Probability and Statistics**

a) so you want F,F,S prob = (.8)(.8)(.2) = .128 ---- you were correct b) you want 10 consecutive failures prob = .8^10 = .1073... ------ you are correct again 2. This question falls under the catergory: Number of trials until we have success Here is a page that details it, and...
*Sunday, September 29, 2013 at 7:44am*

**Probability and Statistics**

Assume 10% of the engines manufactured on an assembly line are defective. If engines are randomly selected one at a time and tested. What is the probability that the third nondefective engine will be found a)on the fifth trial? b) on or before the fifth trial? MY answers: a) P...
*Sunday, September 29, 2013 at 3:12am*

**Probability and Statistics**

An oil prospector will drill a succession of holes in a given area to find a productive well. The probability that he is successful on a given trial is 0.2. a) What's the probability that that the third hole drilled is the first to yield a productive well? b) If the ...
*Sunday, September 29, 2013 at 3:06am*

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