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April 16, 2014

April 16, 2014

**Recent Homework Questions About Statistics**

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**Statistics**

Would the interval be 63.5 to 68.3?
*Wednesday, October 30, 2013 at 6:51pm*

**Statistics/Math**

1. B 2. B
*Wednesday, October 30, 2013 at 6:35pm*

**Statistics/Math**

1. B 2. B
*Wednesday, October 30, 2013 at 6:30pm*

**Statistics**

The coding department of a large physician clinic is interested in purchasing a software program that will edit claims before they are sent out to billing. The license fee for the software costs $34,000 per year. The software is expected to reduce the number of errors on ...
*Wednesday, October 30, 2013 at 5:42pm*

**Statistics**

Formula: CI90 = p + or - (1.645)[√(pq/n)] ...where p = x/n, q = 1 - p, and n = sample size. Note: + or - 1.645 represents 90% confidence interval. p = .659 q = 1 - p = .341 n = 1026 I let you take it from here.
*Wednesday, October 30, 2013 at 5:36pm*

**Statistics p-value**

You can try a proportional one-sample z-test for this one since this problem is using proportions. Null hypothesis: Ho: p = .63 -->meaning: population proportion is equal to .63 Alternative hypothesis: Ha: p > .63 -->meaning: population proportion is greater than .63...
*Wednesday, October 30, 2013 at 5:24pm*

**Statistics p-value**

Politicians are interested in knowing the opinions of their constituents on important issues. One administrative assistant to a senator claims that more than 63% of adult women favor stricter gun laws. A recent telephone survey of 1026 adults by IBR Polls found that 65.9% of ...
*Wednesday, October 30, 2013 at 5:10pm*

**Statistics**

Politicians are interested in knowing the opinions of their constituents on important issues. One administrative assistant to a senator claims that more than 63% of adult women favor stricter gun laws. A recent telephone survey of 1026 adult women by IBR Polls found that 65.9...
*Wednesday, October 30, 2013 at 5:08pm*

**Statistics/Math**

I'm confused. Are you saying # 1 is more than, which is B? Or # 1 is more than and #2 is B?
*Wednesday, October 30, 2013 at 5:04pm*

**Statistics**

You will need to determine "degrees of freedom between" and "degrees of freedom within" before checking an ANOVA table using alpha level. Note: k = number of levels. To calculate df within: a) You have 4 levels. Your sample size is 23 Your alpha level ...
*Wednesday, October 30, 2013 at 4:44pm*

**Statistics/Math**

1. More than B
*Wednesday, October 30, 2013 at 3:51pm*

**Statistics/Math**

1. A magazine is considering the launch of an online edition. The magazine plans to go ahead only if it's convinced that more than 25% of the current readers would subscribe. The magazine contacted a simple random sample of 500 current subscribers and determine that 137 of...
*Wednesday, October 30, 2013 at 3:45pm*

**Statistics**

100 / 6 = 16.67 hours needed to code 100 records 16.67 / 7 = 2.38 FTEs
*Wednesday, October 30, 2013 at 2:57pm*

**Statistics**

The coding department of a large physician clinic is interested in purchasing a software program that will edit claims before they are sent out to billing. The license fee for the software costs $34,000 per year. The software is expected to reduce the number of errors on ...
*Wednesday, October 30, 2013 at 2:08pm*

**Statistics**

Sorry, I meant FTEs (Full time equivalents)
*Wednesday, October 30, 2013 at 2:05pm*

**Statistics**

X-bar = 23000
*Wednesday, October 30, 2013 at 1:45pm*

**Statistics**

What is an FET?
*Wednesday, October 30, 2013 at 1:31pm*

**Statistics**

HIM department at Community Hospital will experience a 15 percent increase in the number of discharges coded per day as the result of opening a cardiac clinic in the facility. The 15 percent incrase is projected to be 100 additional records per day. The standard time to code ...
*Wednesday, October 30, 2013 at 1:27pm*

**Statistics**

According to internal testing done by the Get-A-Grip tire company, the lifetime of tires sold on new cars is normally distributed with a mean of 23,000 miles, with a standard deviation of 2500 miles. If the claim by Get-A-Grip is true, what is the mean of the sampling ...
*Wednesday, October 30, 2013 at 10:47am*

**Statistics**

Consider the following ANOVA experiments. (Give your answers correct to two decimal places.) (a) Determine the critical region and critical value that are used in the classical approach for testing the null hypothesis Ho: ì1 = ì2 = ì3 = ì4, with n...
*Wednesday, October 30, 2013 at 8:30am*

**Statistics**

Consider the following table for a single-factor ANOVA. Level of Factor Replicates 1 2 3 1 1 2 5 2 2 4 7 3 2 4 7 (a) Find x1,2. (b) Find x2,1. (c) Find C1. (d) Find x. (e) Find (Ci )2.
*Wednesday, October 30, 2013 at 8:29am*

**Statistics Math**

Amount of true variance to observed variance is 81 percent
*Wednesday, October 30, 2013 at 2:03am*

**Statistics Math**

With a reliability coefficient of 0.81, using classical test theory we would interpret that the: Answer a.Amount of error variance to observed variance is 81 percent b.Amount of true variance to observed variance is 81 percent c.Instrument has good enough reliability d....
*Tuesday, October 29, 2013 at 11:28pm*

**Statistics**

F = 4.67
*Tuesday, October 29, 2013 at 10:19pm*

**statistics**

Range = highest value -lowest value Range = 2400-73 Range = 2327 Variance = 343044.49 Standard deviation = 585.7
*Tuesday, October 29, 2013 at 8:58pm*

**Statistics**

Thanks for your help!
*Tuesday, October 29, 2013 at 8:54pm*

**Statistics**

(38-23) -+ 3.169* sqrt((30^2/23 +35^2/11) Lower limit -23.88 Upper limit 53.88
*Tuesday, October 29, 2013 at 8:52pm*

**Statistics**

State the null hypothesis, Ho, and the alternative hypothesis, Ha, that would be used to test these claims. < ¡Ü = ¡Ù ¡Ý > (a) There is an increase in the mean difference between posttest and pretest scores. Ho: ¦Ìd 0 Ha...
*Tuesday, October 29, 2013 at 8:45pm*

**Statistics**

Find the critical value for the hypothesis test, given the following. (Give your answer correct to two decimal places.) Ha: ó1 > ó2, with n1 = 13, n2 = 8, and á = 0.025 F=
*Tuesday, October 29, 2013 at 8:43pm*

**Statistics**

Find the 99% confidence interval for the difference between two means based on this information about two samples. Assume independent samples from normal populations. (Use conservative degrees of freedom.) (Give your answers correct to two decimal places.) Sample Number Mean ...
*Tuesday, October 29, 2013 at 8:42pm*

**Statistics/Math**

Answer. A
*Tuesday, October 29, 2013 at 8:21pm*

**Statistics**

Looks OK!
*Tuesday, October 29, 2013 at 7:04pm*

**Statistics/Math**

I want to test H0: p = .12 vs. Ha: p ≠ .12 using a test of hypothesis. This test would be called a(n) ____________ test. A) two-tailed B) right-tailed (this one?) C) left-tailed
*Tuesday, October 29, 2013 at 7:03pm*

**statistics**

List below are the duration (in hours) of a simple random sample of all flights of a space shuttle program. Find the range, variance, and standard deviation for the sample data. Is the lowest duration time unusual? Why or hwy not? 73 95 238 199 166 268 198 374 260 235 382 339 ...
*Tuesday, October 29, 2013 at 6:46pm*

**Statistics**

Oldest Youngest Difference 174 168 6 173 169 4 169 175 -6 180 187 -7 51 53 -2 Sum of d = -5 d bar = -5/5 = -1 S = 5.83 n = 5 t = -1/[ (5.83/sqrt((5))] t = -.38 P-value = 0.7209
*Tuesday, October 29, 2013 at 5:39pm*

**Statistics**

What does mean? ƒÊd ‚ 0
*Tuesday, October 29, 2013 at 4:48pm*

**Statistics**

A new manager, hired at a large warehouse, was told to reduce the 26% employee sick leave. The manager introduced a new incentive program for the company's employees with perfect attendance. The manager decides to test the new program to see if it's better and plans to...
*Tuesday, October 29, 2013 at 4:32pm*

**Statistics**

Which of the following criteria must be met to do a one-proportion z- test? A. The data values in the sample must be dependent. B. The parent population must be normally distributed. C. The data must come from a random sample. D. The sample size must be more than 10% of the ...
*Tuesday, October 29, 2013 at 4:31pm*

**Statistics**

I glad to see your answer.
*Tuesday, October 29, 2013 at 4:26pm*

**Statistics**

Complete the hypothesis test with alternative hypothesis ƒÊd ‚ 0 based on the paired data that follows and d = O - Y. Use ƒ¿ = 0.01. Assume normality. Oldest 174 173 169 180 51 Youngest 168 169 175 187 53 (a) Find t. (Give your answer correct ...
*Tuesday, October 29, 2013 at 4:23pm*

**Statistics**

Thanks!!
*Tuesday, October 29, 2013 at 4:21pm*

**Statistics**

Sample n x G 375 324 H 414 333 n1 = 375 x1 = 324 p1 = x1/n1 = 324/375 = .864 n2 = 414 x2 = 333 p2 = x2/n2= 333/414 = .804 z = 2.24 p-value = .025
*Tuesday, October 29, 2013 at 4:13pm*

**Statistics**

H0: p1 = p2 Ha: p1 < p2 P1 = .28 p2 = .24 x1 = 200(.28) = 56 x2 = 200(.24) = 48 n1 = 200 n2 =200 z = -0.91 p-value = 0.1809 b. fail to reject the null hypothesis, there is not sufficient evidence that
*Tuesday, October 29, 2013 at 4:03pm*

**Statistics**

SSd = 6193- (231)^2/37 SSd = 4750.811 Sd = sqrt(SSd/n-1) Sd = sqrt(4750.811/36)) Sd = 11.488 Mean = 231/37 = 6.243 t = 6.243/11.488/sqrt((37)) t = 3.31 p-value = .0021
*Tuesday, October 29, 2013 at 3:16pm*

**Business Statistics**

44%
*Tuesday, October 29, 2013 at 2:42pm*

**Statistics**

Find the value of z that would be used to test the difference between the proportions, given the following. (Use G - H. Give your answer correct to two decimal places.) Sample n x G 375 324 H 414 333
*Tuesday, October 29, 2013 at 1:54pm*

**Statistics**

Help Me Please! In a survey of families in which both parents work, one of the questions asked was, "Have you refused a job, promotion, or transfer because it would mean less time with your family?" A total of 200 men and 200 women were asked this question. "Yes...
*Tuesday, October 29, 2013 at 1:53pm*

**Statistics**

Please Help! If someone could just show me how to do a problem like this! The corrosive effects of various soils on coated and uncoated steel pipe was tested by using a dependent sampling plan. The data collected are summarized below, where d is the amount of corrosion on the ...
*Tuesday, October 29, 2013 at 1:51pm*

**Statistics**

HIM department at Community Hospital will experience a 15 percent increase in the number of discharges coded per day as the result of opening a cardiac clinic in the facility. The 15 percent incrase is projected to be 100 additional records per day. The standard time to code ...
*Tuesday, October 29, 2013 at 11:32am*

**Business Statistics**

28.5
*Tuesday, October 29, 2013 at 10:46am*

**Statistics**

(38-23) -+ 3.169* sqrt((30^2/23 +35^2/11) Lower limit -23.88 Upper limit 53.88
*Tuesday, October 29, 2013 at 1:33am*

**Statistics**

t = -4.56 p-value = .0.0030 Reject the null hypothesis
*Monday, October 28, 2013 at 11:49pm*

**statistics**

Find the uniform continuous probability for P(X < 27) for U(0, 50). I need the formula to figure out with 4 place decimal place as an answer
*Monday, October 28, 2013 at 10:17pm*

**Statistics**

Find the 99% confidence interval for the difference between two means based on this information about two samples. Assume independent samples from normal populations. (Use conservative degrees of freedom.) (Give your answers correct to two decimal places.) Sample Number Mean ...
*Monday, October 28, 2013 at 10:03pm*

**Statistics**

Please Help I'm desperate! Complete the hypothesis test with alternative hypothesis ìd < 0 based on the paired data that follow and d = M - N. Use á = 0.02. Assume normality. M 48 47 67 79 73 66 N 52 55 68 87 78 70 (a) Find t. (Give your answer correct to ...
*Monday, October 28, 2013 at 10:02pm*

**statistics**

what
*Monday, October 28, 2013 at 8:33pm*

**Statistics**

I would say B.
*Monday, October 28, 2013 at 5:40pm*

**Statistics**

Which is true about a 99% confidence interval for a population proportion based on a given sample? I. We are 99% confident that the population proportion is in our interval. II. There is a 99% chance that our interval contains the sample proportion. III. The interval is wider ...
*Monday, October 28, 2013 at 3:43pm*

**Statistics Math**

p = .35 n = 325 z = 1.96 E = ('z critical value') * sqrt[p * (1 - p)/n] E = 1.96 * sqrt [.35* .65/325] E = 0.0519 p ± E = [.2891, .4019] The 95% confidence interval is 29.8% to 40.2%. The margin of error is 5.2.
*Monday, October 28, 2013 at 3:11pm*

**Statistics**

The coding department of a large physician clinic is interested in purchasing a software program that will edit claims before they are sent out to billing. The license fee for the software costs $34,000 per year. The software is expected to reduce the number of errors on ...
*Monday, October 28, 2013 at 2:57pm*

**statistics**

(.44)^6 * (1-.44)^3 = ?
*Monday, October 28, 2013 at 1:44pm*

**Probability (Partial)**

a. Z = (score-mean)/SEm SEm = SD/√n SD = √variance Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z score. b. Z = (score-mean)/SD Use same table. c...
*Monday, October 28, 2013 at 1:33pm*

**Statistics Math**

The sample proportion is never equal to the population proportion We expect 95% confidence intervals to contain the sample proportion 95% of the time Are the above statements true? I would say yes because the sample proportion is not the same as the population proportion and ...
*Monday, October 28, 2013 at 1:27pm*

**Statistics Math**

Pye and Associates recently conducted a survey to determine the percent of adult county residents who believe that students in public high schools should wear uniforms to school. The telephone poll of 325 adults found that 35% of the adults believe that public high school ...
*Monday, October 28, 2013 at 1:23pm*

**Statistics**

Thank you, but I'm still confused. So is there not enough info to answer this question? Thank you for your time.
*Monday, October 28, 2013 at 1:21pm*

**Statistics**

100(32/56) = _______%
*Monday, October 28, 2013 at 1:16pm*

**Statistics**

Conclude that their interval is too close to call because 50% is in the interval, meaning that it is quite likely that p could be 50%.
*Monday, October 28, 2013 at 1:15pm*

**Statistics**

All the patients who present to the emergency services dept with a suspecetd AMI are expected to receive an ECG within 10 mins of their arrival. Of the 56 patients who had a suspected AMI during the last quarter, 32 had an ECG within the specified time frame, what was the rate...
*Monday, October 28, 2013 at 1:11pm*

**statistics**

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability (.05) related to a Z score. Insert the values into the equation below and solve for the score. Z = (score-mean)/SD
*Monday, October 28, 2013 at 1:08pm*

**Statistics**

The forms costs $100.00 for the first 1,000 forms,, so it costs $100,000.00 100.00 for the second 1,000, so it costs $100,000.00 3,000 @ 50 = $150,000 The total cost is $350,000
*Monday, October 28, 2013 at 12:57pm*

**Statistics**

Analyze per 1000 forms. 2($100) + 3($50) = ?
*Monday, October 28, 2013 at 12:55pm*

**Statistics**

A city ballot includes a local initiative that would legalize gambling. The issue is hotly contested, and two groups decide to conduct polls to predict the outcome. The local newspaper finds that 53% of 1200 randomly selected voters plan to vote "yes," while a ...
*Monday, October 28, 2013 at 12:55pm*

**Statistics**

the forms used in your coding area cost $100.00 per 1,000 forms for the first 2,000 and $50 for every 1,000 thereafter. If you need to order 5,000 forms, what is the total cost?
*Monday, October 28, 2013 at 12:27pm*

**Statistics**

HIM department at Community Hospital will experience a 15 percent increase in the number of discharges coded per day as the result of opening a cardiac clinic in the facility. The 15 percent incrase is projected to be 100 additional records per day. The standard time to code ...
*Monday, October 28, 2013 at 11:51am*

**Statistics**

1. the point estimate of the population mean is 10 gallons. 2. [(10-2.575*5.10/sqrt((60)), 10+ 2.575*5.10/sqrt((60))]) = [8.3, 11.7]
*Monday, October 28, 2013 at 12:02am*

**Statistics**

A local grocery store wants to estimate the mean daily number of gallons of milk sold to customers. Assume the number of gallons sold follows the normal distribution, with a population standard deviation of 5.10 gallons. A random sample of 60 days shows that the mean daily ...
*Sunday, October 27, 2013 at 11:31pm*

**calculating and reporting health statistics**

Community Health Center, a new patient clinic in your town serving only underinsured and uninsured patients, has asked you to help its HIM department get started. Calculate the number of new shelving units needed for a medical record filing system based on 8 shelves per unit ...
*Sunday, October 27, 2013 at 11:07pm*

**Statistics**

Ans C Includes 25% [.207, .266]
*Sunday, October 27, 2013 at 11:06pm*

**Health statistics**

4257/5352 = 0.7954035 = 79.54%
*Sunday, October 27, 2013 at 10:51pm*

**Statistics**

The 90% confidence interval is 9.6 % to 12.8%. The margin of error is 1.6.
*Sunday, October 27, 2013 at 10:50pm*

**Health statistics**

Of the 5,352 requests for medical records in the question above, 4,257 were located within the 20-minute time frame established by the supervisor as a quality improvement indicator. What is the rate of compliance in answering requests for records? Round to two decimal points.
*Sunday, October 27, 2013 at 10:46pm*

**Statistics**

A. The standard error of the mean = 20/sqrt([100]) = 2 answer 2 B. z =(200-115)/(20/sqrt((100)) z = 42.5 answer 0 C. z = (120-115)/2 = 2.5 answer 0. 9938 D. z = (111-115) /2 z = -2 z = (119-115)/2 z = 2 .9772-.0228 = 0.9544 Answer 0.9544
*Sunday, October 27, 2013 at 10:29pm*

**statistics**

Psychology z =(48-87)/14 z = -2.796 Economics z =(52-53)/8 z = -0.125 The score of Economics is better.
*Sunday, October 27, 2013 at 9:36pm*

**Statistics**

A university has 1,000 computers available for students to use. Each computer has a 250-gigabyte hard drive. The university wants to estimate the space occupied on the hard drives. A random sample of 100 computers showed a mean of 115 gigabytes used with a standard deviation ...
*Sunday, October 27, 2013 at 9:30pm*

**Statistics**

A city ballot includes a local initiative that would legalize gambling. The issue is hotly contested, and two groups decide to conduct polls to predict the outcome. The local newspaper finds that 53% of 1200 randomly selected voters plan to vote "yes," while a ...
*Sunday, October 27, 2013 at 9:20pm*

**Statistics**

In 1998 a San Diego Reproductive clinic reported 49 live births to 207 women under the age of 40 who had previously been unable to get pregnant. Using the 90% confidence interval calculated above, would it be misleading for the clinic to report a success rate of 25%? A) Yes, ...
*Sunday, October 27, 2013 at 9:15pm*

**statistics**

If GMAT scores for applicants at Oxnard Graduate School of Business are N(500, 50) then the top 5 percent of the applicants would have a score of at least (choose the nearest integer):
*Sunday, October 27, 2013 at 9:15pm*

**statistics**

Which is relatively better a score of 48 on psychology test or a score of 52 on an economics test, Scores on the psychology test have a mean of 87 and a standard deviation of 14. Scores on the economics test have a mean of 53 and a standard deviation of 8.
*Sunday, October 27, 2013 at 9:08pm*

**Statistics**

Statistics - Kuai, Sunday, October 27, 2013 at 8:55pm z = (21-22)/.5 z = -2 1-.0228 = .9710 z = (20.75-22//.5 z = -2.5 z =( 23.25-22)/.5 z = 2.5 .9938-.0062= .9876
*Sunday, October 27, 2013 at 8:59pm*

**Statistics**

z = (21-22)/.5 z = -2 1-.0062 = .9938 z = (20.75-22//.5 z = -2.5 z =( 23.25-22)/.5 z = 2.5 .9938-.0228 = .9710
*Sunday, October 27, 2013 at 8:55pm*

**Statistics**

z = (21-22)/.5 z = -2 1-.0062 = .9938 z = (20.75-22//.5 z = -2.5 z =( 23.25-22)/.5 z = 2.5 .9938-.0228 = .9710
*Sunday, October 27, 2013 at 8:55pm*

**Statistics**

The weight of a bag of corn chips is normally distributed with a mean of 22 ounces and a standard deviation of 0.5 ounces. -The probability that a bag of corn chips weighs more than 21 ounces is? -The probability that a bag of corn chips weighs between 20.75 and 23.25 ounces is?
*Sunday, October 27, 2013 at 7:57pm*

**Statistics Math**

1. The best point estimate for p is the sample proportion. Answer: A 2. I agree with your choice.
*Sunday, October 27, 2013 at 7:54pm*

**Statistics**

Wow! Thank you for the help! Also, wouldn't the 90% confidence interval be 9.6% to 12.8%? Also, would the margin of error be 3.2 or 1.6? Thank you!
*Sunday, October 27, 2013 at 7:20pm*

**Statistics**

n = 1000 x = 112 p = x/n p = 112/1000 = 0.112 z critical value = 1.645 E = za/2 *sqrt((p (1-p)/)/n)) E = 1.645 *sqrt((.112*.888/1000) E = 0.016 p ± ('z critical value') * SQRT[p * (1 - p)/n] = 0.112 ± 1.645 * SQRT[0.112 * (1 - 0.112)/1000] = [0.096, 0.128...
*Sunday, October 27, 2013 at 7:11pm*

**Statistics**

Direct mail advertisers send solicitations (that is "junk mail") to thousands of potential customers in the hope that some will buy the company's products. The response rate is usually quite low. Suppose a company wants to test the response rate for a new flyer ...
*Sunday, October 27, 2013 at 6:48pm*

**statistics**

P(x = 6) = nCx *p^x (1-p)^n-x 9C6(.44)^6(1-.44)^n-x 9C6(.44)(.56)^3 = 0.1070
*Sunday, October 27, 2013 at 5:32pm*

**statistics**

Forty-four percent of customers who visit a department store make a purchase. The probability, rounded to four decimal places, that in a random sample of 9 customers who will visit this department store, exactly 6 will make a purchase is:
*Sunday, October 27, 2013 at 5:10pm*

**statistics**

Forty-four percent of customers who visit a department store make a purchase. The probability, rounded to four decimal places, that in a random sample of 9 customers who will visit this department store, exactly 6 will make a purchase is:
*Sunday, October 27, 2013 at 5:04pm*

**Statistics Math**

1. What type of car is more popular among college students, American or foreign? One hundred fifty-nine college students were randomly sampled and each was asked which type of car he or she prefers. A computer package was used to generate the printout below for the proportion ...
*Sunday, October 27, 2013 at 4:45pm*

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