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April 19, 2014

April 19, 2014

**Recent Homework Questions About Statistics**

Post a New Question | Current Questions

**Statistics**

I already found part A just need help with B! The computer-science aptitude score, x, and the achievement score, y (measured by a comprehensive final), were measured for 10 students in a beginning computer-science course. The results were as follows. (Give your answers correct...
*Thursday, November 7, 2013 at 11:06pm*

**statistics**

a. z = (65-64.6)/(2.8/sqrt(1)) z = 0.14 b. z = (65-64.6)/(2.8/sqrt(49)) z = 1
*Thursday, November 7, 2013 at 10:42pm*

**statistics**

great webpage for your problem, just plug in the values that you have http://davidmlane.com/hyperstat/z_table.html
*Thursday, November 7, 2013 at 9:43pm*

**statistics**

Assume that women's heights are normally distributed with a mean given by u=64.6 in and a standard deviation given by 0=2.8in. a) If 1 woman is randomly selected, find the probability that her height is less than 65in. b) If 49 women are randomly selected, find the ...
*Thursday, November 7, 2013 at 9:03pm*

**Statistics**

In a study of caffeine and stress, college students indicate how many cups of coffee they drink per day and their stress level on a scale of 1 to 10. The date follow: Number of Cups of Coffee 3,2,4,6,5,1,7,3 Stress Level 5,3,3,9,4,2,10,5 Calculate a Pearsons r to determine the...
*Thursday, November 7, 2013 at 8:47pm*

**Statistics**

When groups of data are separated, an association can get stronger because of a lurking variable. That lurking variable is usually the number of observations in the different groups of data.
*Thursday, November 7, 2013 at 8:44pm*

**statistics**

Please only post your questions once. Repeating posts will not get a quicker response. In addition, it wastes our time looking over reposts that have already been answered in another post. Thank you. See your previous post.
*Thursday, November 7, 2013 at 12:19pm*

**statistics**

Assume that adults have IQ score that are normally distributed with a mean of 105 and a standard deviation 20. Find P, which is the IQ score separating the bottom 10% from the top 90%. Round to the nearest hundredth as needed.
*Thursday, November 7, 2013 at 11:13am*

**Statistics**

You draw nine cards from a standard deck of cards. What is the probability that a. four or more will be red, b. exactly two or three will be red, c. two or fewer will be red, and d. exactly five will be red?.
*Thursday, November 7, 2013 at 8:30am*

**math**

a nice calculator can be found at http://easycalculation.com/statistics/standard-deviation.php It will verify the answers which you have calculated on your own >wink wink<
*Thursday, November 7, 2013 at 4:09am*

**Statistics**

Using a 0.05 level of significance, test the hypothesis that the probability of the NCAA Division I basketball champion being from the Pac 10 is 20%. Repeat the test for the hypothesis that the probability the champion is UCLA is 20%. What do these results say about testing ...
*Thursday, November 7, 2013 at 2:49am*

**Statistics**

2E + 188 = 206 2E = 206-188 2E = 18 E = 9 Answer B
*Wednesday, November 6, 2013 at 9:13pm*

**Statistics**

When consumers apply for credit, their credit is rated using the FICO score. A bank manager used a random sample of the credit scores of 18 customers and determined the following 95% confidence interval: (613.6, 708.0) If the sample used 45 customers rather than 18 customers, ...
*Wednesday, November 6, 2013 at 7:51pm*

**Statistics**

A scientist in Smallville tested the cholesterol of a random sample of 35 town residents. He constructed the following confidence interval: t-interval for μ: with 99.00% Confidence: 188 < μ(Cholesterol) < 206 What is the margin of error? A) 18 B) 9 C) 1.09 D) ...
*Wednesday, November 6, 2013 at 7:49pm*

**statistics**

Z = (score-mean)/SD Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z score. Multiply by 100 to get the percentage.
*Wednesday, November 6, 2013 at 1:20pm*

**Statistics**

In a large collection of real SMS text messages from particular cellphone users, 13.40% of messages are identified as spam. Of all spam messages 17.0% contain both the word "free" and the word "text" ("txt") For example, "Congrats!! You have ...
*Tuesday, November 5, 2013 at 5:54pm*

**Statistics**

I'm not sure
*Tuesday, November 5, 2013 at 5:07pm*

**statistics**

The weight of a can made from a machine is normally distributed with a mean of 25 grams and a standard deviation of 0.4 grams. What percentage of the cans from this machine would not meet the minimum required weight of 24 grams? Round to the nearest hundredth of a percent
*Tuesday, November 5, 2013 at 4:49pm*

**Statistics**

1. 29 2. What do you think?
*Tuesday, November 5, 2013 at 1:52pm*

**Statistics**

1,3,5,3,2,29,3,4,2,1,2 Mean 5 Range 28 Variance 64.8 Standard Deviation 8.0 1.What value is affecting the mean and SD of this distribution? 2.Does the mean adequately represent this disribution? If bot, what would be a better measure of central tendency for this data set?
*Tuesday, November 5, 2013 at 11:13am*

**Statistics**

True 1. CORRELATION Correlation means that two variables (sets of data) have some type of association with each other, such that as one variable increases, the other also increases (a positive correlation), or decreases (a negative correlation).
*Tuesday, November 5, 2013 at 11:03am*

**Statistics**

when two variables are correlated it means that one is the cause of the other. true or false?
*Tuesday, November 5, 2013 at 10:41am*

**statistics**

P(20 < x < 23) = P(X = 20 ) + P (X = 21) + P(X = 22) + P(X = 23) P(20 < x < 23) = (30C20)(.23)^20(.77)^10 + (30C21)(.23)^21(.77)^9 + (30C22)(.23)^22(.77)^8 + (30C23)(.23)^23(.77)^7 = ?
*Tuesday, November 5, 2013 at 1:43am*

**statistics**

P(X ≥ 13) = P (X= 13) + P (X = 14) + P (X = 15) P(X ≥ 13) =(15C13)(.9)^13(.1)^2+ (15C14)(.9)^14(.1)^1+ (15C15)(.9)^15(.1)^0 = .8159
*Monday, November 4, 2013 at 9:24pm*

**statistics**

In a region, 90% of the population have brown eyes. If 15 people are randomly selected, find the probability that at least 13 of them have brown eyes. Is it unusual to randomly select 15 people and find that at least 13 of them have brown eyes? Why or why not?
*Monday, November 4, 2013 at 8:08pm*

**Statistics**

P value (e.g., P ≤ .05) is the probability that the null hypothesis is true, even though it may be rejected at this level.
*Monday, November 4, 2013 at 6:22pm*

**statistics**

z = (score -mean)/sd a. z = (74-69)/2.8 z = 5/2.8 = 1.79 is .0367 The percentage of men that are taller than in is 3.67% b. z = (score -mean)/sd z = ((70-63.6)/2.5 z = 6.4/2.5 = 2.56 is .0052 The percentage of women that are taller than in is .52%.
*Monday, November 4, 2013 at 5:34pm*

**Statistics**

The p-value is the probability of the observed statistic given the null hypothesis is true. A) True B) False False?
*Monday, November 4, 2013 at 4:59pm*

**Statistics**

Politicians are interested in knowing the opinions of their constituents on important issues. One administrative assistant to a senator claims that more than 63% of adult women favor stricter gun laws. A recent telephone survey (randomly generated phone numbers were used) of ...
*Monday, November 4, 2013 at 4:57pm*

**statistics-PLEASE HELP quick**

I have less than 24 hours to find the binomial probability of P(20<x<23)= and P(x>23)= if n=30 p=.23 u=6.9 q=.77 and the standard deviation is 2.3 can someone please show me how to get the outcome they want?
*Monday, November 4, 2013 at 3:44pm*

**Statistics**

answer A
*Monday, November 4, 2013 at 3:28pm*

**Statistics**

It is normal model z-score
*Monday, November 4, 2013 at 3:08pm*

**Statistics**

Politicians are interested in knowing the opinions of their constituents on important issues. One administrative assistant to a senator claims that more than 63% of adult women favor stricter gun laws. A recent telephone survey of 1026 adults by IBR Polls found that 65.9% of ...
*Monday, November 4, 2013 at 2:44pm*

**Statistics Help Please**

A bank is testing a new method for getting delinquent customers to pay their past-due credit card bills. The standard way was to send a letter (costing about $0.45) asking the customer to pay. That worked 30% of the time. The bank wants to test a new method that involves ...
*Monday, November 4, 2013 at 2:42pm*

**Statistics**

The business college computing center wants to determine the proportion of business students who have laptop computers. If the proportion exceeds 35%, then the lab will scale back a proposed enlargement of its facilities. Suppose 200 business students were randomly sampled and...
*Monday, November 4, 2013 at 2:35pm*

**statistics**

Tall clubs international is a social organization for tall people. It has a height requirement that men must be at least 74 in. and women must be at least 70 in. tall. If men's heights have a normal mean of 69.0 in and a deviation of 2.8 and women's normal heights have...
*Monday, November 4, 2013 at 1:55pm*

**statistics**

If P=.23 and n=30 what is the outcome of P(20<x<23)= P(x>23)= please show the whole solution so I can learn how and why the outcome was achieved. Thanks so much.
*Monday, November 4, 2013 at 1:42pm*

**statistics**

binompdf(3, .60, 1)
*Monday, November 4, 2013 at 12:31am*

**Statistics Problems**

A market sells potatoes whose weights are normally distributed with mean 65 grams and standard deviation 15 grams. (i) Find the probability that a randomly chosen potato weighs between 40 grams and 80 grams. The market sells potatoes weighing more than 80 grams separately ...
*Sunday, November 3, 2013 at 10:22pm*

**Healthcare Statistics**

You've already stated that the required payback period is 3 years. 3,500x > 28,000 Solve for x to find how long the company would need to keep this equipment.
*Sunday, November 3, 2013 at 9:06pm*

**Statistics**

No Left-tailed
*Sunday, November 3, 2013 at 8:56pm*

**Healthcare Statistics**

In deciding whether to purchase or lease a new dictation system, the HIM supervisor calculates the payback period. The hospital's required payback period is three years. If the equipment costs $ 28,000 and generates $3,500 per year in savings, what would be the payback ...
*Sunday, November 3, 2013 at 8:56pm*

**statistics**

binomial = (n, p, x) Binompdf (11, .6, 1)
*Sunday, November 3, 2013 at 7:54pm*

**Healthcare Statistics**

100(14,000 / 62,000) = ______%
*Sunday, November 3, 2013 at 7:08pm*

**Healthcare Statistics**

the coding section in the HIM department shows its first-quarter budget analysis as having an expected cost of operation of $62,000. However, the actual cost of operation was $76,000. calculate the budget variance.
*Sunday, November 3, 2013 at 7:01pm*

**Statistics**

In deciding whether to purchase or lease a new dictation system, the Him supervisor calculates the payback period. The hospital's required payback period is three years. If the equipment costs $ 28,00 and generates $3,500 per year in savings, what would be the payback ...
*Sunday, November 3, 2013 at 6:48pm*

**Statistics**

Politicians are interested in knowing the opinions of their constituents on important issues. One administrative assistant to a senator claims that more than 63% of adult women favor stricter gun laws. A recent telephone survey of 1026 adults by IBR Polls found that 65.9% of ...
*Sunday, November 3, 2013 at 6:37pm*

**Statistics Problems**

The bank sets up an experiment to test the effectiveness of the DVD. The mail it out to a random sample of delinquent customers and keep track of how many actually do contact the bank to arrange payments. The bank's statistician calculates a p-value (probability-value) of ...
*Sunday, November 3, 2013 at 6:35pm*

**Statistics**

A skeptical paranormal researcher claims that the proportion of Americans that have seen a UFO is less than 5%. the type of alternative hypothesis is: left-tailed right-tailed or two-tailed Is this right-tailed?
*Sunday, November 3, 2013 at 6:33pm*

**statistics**

Assume that a procedure yields a binomial distribution with a trial repeated n times. Use a binomial probabilities table to find the probability of x successes given the probability p of success in a given trial. n= 3 , x=1, p= 0.60
*Sunday, November 3, 2013 at 5:56pm*

**Statistics**

Politicians are interested in knowing the opinions of their constituents on important issues. One administrative assistant to a senator claims that more than 63% of adult women favor stricter gun laws. A recent telephone survey of 1026 adult women by IBR Polls found that 65.9...
*Sunday, November 3, 2013 at 4:16pm*

**Statistics**

Politicians are interested in knowing the opinions of their constituents on important issues. One administrative assistant to a senator claims that more than 63% of adult women favor stricter gun laws. A recent telephone survey of 1026 adults by IBR Polls found that 65.9% of ...
*Sunday, November 3, 2013 at 4:13pm*

**Statistics**

Please only post your questions once. Repeating posts will not get a quicker response. In addition, it wastes our time looking over reposts that have already been answered in another post. Thank you.
*Sunday, November 3, 2013 at 12:45pm*

**Statistics**

a. k =90 n = 20 90th percentile = k/100 *n 90/100* 20 =18 90th percentile = 69 b. percentile = R/(n +1) 8/(20+ 1) 8/21 = .38095 *100 =
*Sunday, November 3, 2013 at 12:34pm*

**Statistics**

your medical terminology instructor listed the following grades for the class out of a 75 point test: 33,34,43,45,45,54,55,59,60,62,64,66,67,68,67,68,68,69,70,70 a.find the 90th percentile b. your score was 59, what is your percentile?
*Sunday, November 3, 2013 at 11:46am*

**Statistics**

Dear Lee, Please confirm these answers to this question. your medical terminology instructor listed the following grades for the class out of a 75 point test: 33,34,43,45,45,54,55,59,60,62,64,66,67,68,67,68,68,69,70,70 a.find the 90th percentile b. your score was 59, ...
*Sunday, November 3, 2013 at 11:25am*

**Statistics**

a. 69 b. 40th percentile
*Sunday, November 3, 2013 at 11:21am*

**Statistics**

a. 69 b. 40th percentile
*Sunday, November 3, 2013 at 11:20am*

**Statistics**

your medical terminology instructor listed the following grades for the class out of a 75 point test:<br /> 33,34,43,45,45,54,55,59,60,62,64,66,67,68,67,68,68,69,70,70<br /> a.find the 90th percentile<br /> b. your score was 59, what is your ...
*Sunday, November 3, 2013 at 11:17am*

**Statistics**

Is the p-value 0.4995?
*Saturday, November 2, 2013 at 7:25pm*

**Statistics**

n = 1026 za/2 = 1.645 phat = .659 qhat = 1-phat qhat = 1-.659 = .341 Error = z/2* sqrt( phat *qhat/n) E = 1.645 * sqrt(.659 * .341/1026)) E = 0.0243 Phat -E <p< phat + E (.659-.0243, .659+ .0243) (.6347, .6833) or ( 63.5% , 68.3%) The 90% confidence interval is : (63.5...
*Saturday, November 2, 2013 at 2:24pm*

**Probability and Statistics**

Random Variables X and Y follow a joint distribution: f(x,y)=(6-x-y)/8 if 0<x<2, 2<y<4 and 0, else Find P(1<Y<3|X=1) I first got the marginal distribution for x and got (3-x)/4 (Integrated from 2 to 4)and then got the conditional dist and got (5-y)/4 and then...
*Saturday, November 2, 2013 at 12:40pm*

**Statistics **

The bank sets up an experiment to test the effectiveness of the DVD. The mail it out to a random sample of delinquent customers and keep track of how many actually do contact the bank to arrange payments. The bank's statistician calculates a p-value (probability-value) of ...
*Saturday, November 2, 2013 at 10:37am*

**Statistics**

A bank is testing a new method for getting delinquent customers to pay their past-due credit card bills. The standard way was to send a letter (costing about $0.45) asking the customer to pay. That worked 30% of the time. The bank wants to test a new method that involves ...
*Saturday, November 2, 2013 at 10:36am*

**psy statistics**

Why is a correlation the most appropriate statistic?
*Saturday, November 2, 2013 at 9:29am*

**Statistics**

Is the p-value to the below question 0.4995? Do you reject or fail to reject the null hypothesis? Politicians are interested in knowing the opinions of their constituents on important issues. One administrative assistant to a senator claims that more than 63% of adult women ...
*Saturday, November 2, 2013 at 9:10am*

**Statistics**

Politicians are interested in knowing the opinions of their constituents on important issues. One administrative assistant to a senator claims that more than 63% of adult women favor stricter gun laws. A recent telephone survey of 1026 adult women by IBR Polls found that 65.9...
*Saturday, November 2, 2013 at 8:59am*

**statistics**

P(0) = 0.000729 P(1) = 0.010206 P(2) = 0.059535 P(3) = 0.18522 P(4) = 0. 324135 P(5) = 0.302526 P(6) = 0. 117649
*Friday, November 1, 2013 at 11:57pm*

**statistics**

Assure that a procedure yields abinomial distribution with a trial repeated n times. Use abinomial probabilities table to find the probability if x sucesses given the probability of sucess of a given trial. n=6 x=0 p= 0.70
*Friday, November 1, 2013 at 10:30pm*

**Probability and Statistics**

Random Variables X and Y follow a joint distribution: f(x,y)=(6-x-y)/8 if 0<x<2, 2<y<4 and 0, else Find P(1<Y<3|X=1) I first got the marginal distribution for x and got (3-x)/4 (Integrated from 2 to 4)and then got the conditional dist and got (5-y)/4 and then...
*Friday, November 1, 2013 at 6:53pm*

**Statistics**

A
*Friday, November 1, 2013 at 1:23pm*

**statistics**

y hat = .255x + 23.695 y bar = 26.4 x bar = 10.6 SE² = [ Σ(y-yBar)^2 - [Σ(x-xBar)(y-yBar)]²/Σ(x-xBar)² ] /(n-2)
*Friday, November 1, 2013 at 11:16am*

**statistics**

Use the following table to answer the questions. (Give your answers correct to two decimal places.) x 1 1 3 3 5 5 7 7 9 9 y 3 1 3 1 6 3 6 1 4 4 (a) Find the equation of the line of best fit. y hat = + x (ii) Graph this equation on a scatter diagram. (Do this on paper. Your ...
*Friday, November 1, 2013 at 3:46am*

**statistics**

The computer-science aptitude score, x, and the achievement score, y (measured by a comprehensive final), were measured for 10 students in a beginning computer-science course. The results were as follows. (Give your answers correct to two decimal places.) x 7 6 9 11 11 5 14 8 ...
*Friday, November 1, 2013 at 3:41am*

**statistics**

40
*Thursday, October 31, 2013 at 4:29pm*

**statistics**

40
*Thursday, October 31, 2013 at 4:29pm*

**Statistics Question**

56
*Thursday, October 31, 2013 at 2:40pm*

**Statistics**

The coding department of a large physician clinic is interested in purchasing a software program that will edit claims before they are sent out to billing. The license fee for the software costs $34,000 per year. The software is expected to reduce the number of errors on ...
*Thursday, October 31, 2013 at 2:12pm*

**statistics**

A good interactive Z table site is http://davidmlane.com/hyperstat/z_table.html You can play around there with various ideas, and compare the results with your Z table.
*Thursday, October 31, 2013 at 1:58pm*

**statistics**

if n=30 and p=.23 what is P(20,x,23)= and P(x.23)= I think I need to find the z scores in order to solve but how do I read the table or do I even need it. UGH! so confusing especially 20 years later.
*Thursday, October 31, 2013 at 12:32pm*

**statistics**

Where do I check it?
*Thursday, October 31, 2013 at 7:39am*

**statistics**

125.9, 230.3
*Thursday, October 31, 2013 at 12:10am*

**statistics**

what is P(20,x,23)= and P(x.23)= You have to check
*Thursday, October 31, 2013 at 12:04am*

**statistics**

if n=30 and p=.23 what is P(20,x,23)= and P(x.23)=
*Wednesday, October 30, 2013 at 11:39pm*

**statistics**

125.876,218.9?
*Wednesday, October 30, 2013 at 11:15pm*

**statistics**

they gave me n=30 and p=.23 to get the answers for P(20,x,23)= and P(x.23)= Im just having a hard time with all of this
*Wednesday, October 30, 2013 at 11:11pm*

**statistics**

[178.1-1.28(40.8), 178.1+ 1.28(40.8) ] =[ ] ?
*Wednesday, October 30, 2013 at 10:25pm*

**statistics**

you use that formula when you know what to do. nCr nPr
*Wednesday, October 30, 2013 at 10:07pm*

**statistics**

Are these using nCr? If not what formula do I use? P(20,x,23)= P(x.23)=
*Wednesday, October 30, 2013 at 9:52pm*

**statistics**

The serum cholesterol levels for men in in one age group are normally distributed with mean of 178.1 and standard deviation of 40.8. All units are in mg/100ml. Find two levels that cut off the top 10% and the bottom 10 % from the distribution of x.
*Wednesday, October 30, 2013 at 9:48pm*

**statistics**

p = 0.68 n = 800 µ = np µ = 800(.68) = 544 Standard deviation = √(np(1-p) ) = √(800(.68)(.32) ) = 13.1939 µ±2σ (544 -2(13.193), 544+2(13.1939)) (517.6, 570.4) 554 is not unusual because it is in interval.
*Wednesday, October 30, 2013 at 8:26pm*

**Statistics/Math**

Hey Michael 2 is wrong The correct answer is A
*Wednesday, October 30, 2013 at 7:49pm*

**Statistics**

z = (x -x bar)/ std dev/sqrt(n) z = (12.6-15)/ 6/sqrt(5) z = -0.89 .1867 z = (x -x bar)/ (std dev/sqrt(n)) z = (18.6-15)/ 6/sqrt(5) z= 1.34 .9099 .9909-.1867 = .8042
*Wednesday, October 30, 2013 at 7:23pm*

**statistics**

nPr 35!/(35-4)! = 35!/31! 35 * 34 * 33 * 32 * 31! / 31! = 1256640
*Wednesday, October 30, 2013 at 7:13pm*

**statistics**

A survey for brand recognition is done and it is determined that 68% of consumers have heard of Dull Computer Company. If a survey of 800 randomly selected consumers is to be held would it be unusual for 554 of them to recognize Dull Computer Company? Please show the work so I...
*Wednesday, October 30, 2013 at 7:11pm*

**statistics**

there are 35 members in a sports club. If an election is to be held to pick 4 officers; president, vice president, treasurer, and secretary, how many different lists of officers could result?
*Wednesday, October 30, 2013 at 7:06pm*

**Statistics**

The weights of the fish in a certain lake are normally distributed with a mean of 15lbs. and standard deviation of 6lbs. If a sample of 5 fish are taken from the lake, find the probability their means weights are between 12.6 lbs. and 18.6 lbs.
*Wednesday, October 30, 2013 at 7:05pm*

**Statistics**

A bank is testing a new method for getting delinquent customers to pay their past-due credit card bills. The standard way was to send a letter (costing about $0.45) asking the customer to pay. That worked 30% of the time. The bank wants to test a new method that involves ...
*Wednesday, October 30, 2013 at 7:03pm*

**Statistics p-value**

Is it 3.165?
*Wednesday, October 30, 2013 at 6:59pm*

**Statistics/Math**

Thank you, Kuai!
*Wednesday, October 30, 2013 at 6:53pm*

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