Friday

April 18, 2014

April 18, 2014

**Recent Homework Questions About Statistics**

Post a New Question | Current Questions

**statistics**

A.7.81% B. ? C. 40.91%
*Thursday, November 14, 2013 at 7:01pm*

**statistics**

David wants to rent an unfurnished apartment for next semester. He took a random sample of 9 apartments adversised in the local Halifax paper, and recorded the rental rates. The rents (in $ per month) were: 500 650 600 505 450 550 515 495 640 a) Find a 90% confidence interval ...
*Thursday, November 14, 2013 at 5:59pm*

**Statistics**

Which of the following graphs would be best to use to display the number of discharges by medical service for the past year? Line or bar graph?
*Thursday, November 14, 2013 at 12:28pm*

**Statistics**

In the following two questions, identify which choices would be considered inferential statistics and which would be considered inferential statistics. 1. of 500 randomly selected people in new york city, 210 people had O+ blood. a) "42 percent of the people in NYC have O...
*Thursday, November 14, 2013 at 12:12pm*

**Statistics**

In the following two questions, identify which choices would be considered inferential statistics. 1. of 500 randomly selected people in new york city, 210 people had O+ blood. a) "42 percent of the people in NYC have O+ blood" Is the statement descriptive statistics...
*Thursday, November 14, 2013 at 12:11pm*

**statistics**

a. Mu = np = .89(204) = 181.56 p(r => 49.5) sd = 4.469 z = (49.5-181.56)/4.469 = b mu = .13(204) = 26.52 Sd = 4.803 z = (49.5-26.52)/4.80 = 4.7875
*Thursday, November 14, 2013 at 1:38am*

**statistics**

In the following problem, check that it is appropriate to use the normal approximation to the binomial. Then use the normal distribution to estimate the requested probabilities. More than a decade ago, high levels of lead in the blood put 89% of children at risk. A concerted ...
*Thursday, November 14, 2013 at 12:45am*

**Math Statistics**

A company sells cans of chicken soup that that are advertised to contain 20 oz. However due to variations in the manufacturing process, the volume of soup in the cans is, in fact, Normally distributed with a mean of 20.1 oz and a standard deviation of 0.4 oz. • What is ...
*Thursday, November 14, 2013 at 12:13am*

**Statistics**

Are you sure that is the variance. I got .14
*Wednesday, November 13, 2013 at 11:35pm*

**Statistics**

Thank you so much !
*Wednesday, November 13, 2013 at 9:49pm*

**statistics Question 2**

expect value x a. 8(0.1) + 9(.2) + 10(.25) + 11(.30) + 12 (.15) = 10.2 b. 8^2(0.1) + 9^2(.2) + 10^2(.25) + 11^2(.30) + 12^2(.15) = 180.5
*Wednesday, November 13, 2013 at 7:57pm*

**Statistics**

expect value x a. 8(0.1) + 9(.2) + 10(.25) + 11(.30) + 12 (.15) = 10.2 b. 8^2(0.1) + 9^2(.2) + 10^2(.25) + 11^2(.30) + 12^2(.15) = 180.5
*Wednesday, November 13, 2013 at 7:39pm*

**statistics**

(-0.0371, 0.3715)
*Wednesday, November 13, 2013 at 7:21pm*

**Statistics Question 3**

A company sells cans of chicken soup that that are advertised to contain 20 oz. However due to variations in the manufacturing process, the volume of soup in the cans is, in fact, Normally distributed with a mean of 20.1 oz and a standard deviation of 0.4 oz. • What is ...
*Wednesday, November 13, 2013 at 7:16pm*

**statistics Question 2**

Suppose a person buys 100 shares of stock at in a company at the cost price of $10 per share. He plans to sell at the end of the next month at whatever is the price at that time. The projected price of the stock at the end of next month and the corresponding probability of ...
*Wednesday, November 13, 2013 at 7:15pm*

**Statistics**

mean 26(400) = $10400 Standard deviation = 8(400) = 3200 10400-+ 2.3263*3200/sqrt(50)) [$9,347, 11,453]
*Wednesday, November 13, 2013 at 7:13pm*

**Statistics Question 1**

According to the American Heart Association, one in every four deaths in the U.S. is due to heart disease. Suppose 25 people will die in the U.S. in the next 5 minutes. • What is the chance that exactly 5 of the deaths will be due to heart disease? • What is the ...
*Wednesday, November 13, 2013 at 7:13pm*

**Statistics**

Suppose a person buys 100 shares of stock at in a company at the cost price of $10 per share. He plans to sell at the end of the next month at whatever is the price at that time. The projected price of the stock at the end of next month and the corresponding probability of ...
*Wednesday, November 13, 2013 at 7:09pm*

**statistics**

According to the American Heart Association, one in every four deaths in the U.S. is due to heart disease. Suppose 25 people will die in the U.S. in the next 5 minutes. • What is the chance that exactly 5 of the deaths will be due to heart disease? • What is the ...
*Wednesday, November 13, 2013 at 7:07pm*

**Statistics**

Suppose a random variable X has a uniform distribution over the interval [-10,10]. • Find the probability that X lies between -2 and 6? • Find the probability that X2 lies between 9 and 64? (Note X2 is the square of X.)
*Wednesday, November 13, 2013 at 7:05pm*

**statistics**

Please help- A random sample of n=500 households where 150 have combined cable,phone, and internet service. Firrst, calculate p-hat, the sample proportion of households having such service. Then use a confidence level for pi, the proportion of all households in this area that ...
*Wednesday, November 13, 2013 at 6:51pm*

**Statistics**

$9,531 to $11,269 $9,347 to $11,453 $10,028 to $10,772 $9,414 to $11,386 Are my multiple choice
*Wednesday, November 13, 2013 at 6:13pm*

**Statistics**

[ 23.37, 28.63]
*Wednesday, November 13, 2013 at 6:02pm*

**Statistics**

That's what I originally did but it's not one of the correct answers
*Wednesday, November 13, 2013 at 5:40pm*

**Statistics**

26-2.33*8/sqrt((50)), 26+ 2.33*8/sqrt((50)), = ( , ) ?
*Wednesday, November 13, 2013 at 4:48pm*

**Statistics**

A random sample of 50 students chosen from an elementary school with 400 students was found to have a mean allowance of $26 per week with a standard deviation of $8. Obtain a 98% confidence interval for the total amount of allowance money given to students in this school per ...
*Wednesday, November 13, 2013 at 4:32pm*

**Stats**

A company with two plants producing the same product, but with two slightly different manufacturing processes, conducted a sample study at each of the two plants with the following results: The sample statistics from the first group are: n = 40, x-bar = 18, s = 4.2. The sample...
*Wednesday, November 13, 2013 at 3:32pm*

**statistics**

75.5
*Wednesday, November 13, 2013 at 3:20pm*

**statistics**

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability ([1-.99]/2) and its Z score. 99% = mean ± Z(SEm) SEm = SD/√n
*Wednesday, November 13, 2013 at 11:51am*

**statistics**

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability ([1-.87]/2) and its Z score. 87% = mean ± Z(SD) Fill in the values and calculate.
*Wednesday, November 13, 2013 at 11:48am*

**statistics**

standard deviation 1.2. Random selection of 70 found a mean of 5.2. I have to find a 87% confidence level given this info?
*Wednesday, November 13, 2013 at 10:19am*

**statistics**

skating speeds are normally distributed with a mean of 60 and a standard deviation of 10. Determine the speed that separates the top 6% from the rest.
*Wednesday, November 13, 2013 at 10:08am*

**statistics**

average commuting distance 10.9 miles which is also the mean of a sample of 300 commuters. Sample sd is 6.2 miles . Estimate the true mean using 99% confidence please.
*Wednesday, November 13, 2013 at 10:05am*

**Math Statistics**

An amusement park, Dino World, considering adding some new attractions, conducted a study over several typical days and found that, of 10,000 families entering the park, 1020 brought just one child (defined as younger than age 12), 3370 brought two children, 3510 brought three...
*Wednesday, November 13, 2013 at 9:07am*

**statistic**

3 statistics professors and 7 chemistry professors are available to be advisors.If each professor has an equal chance of being selected, what is the probability that both professors are cgemistry professors?
*Wednesday, November 13, 2013 at 8:52am*

**Healthcare Statistic**

How could you say this is nonsense. This is a question of health statistics Do not be rude if you are helping someone. If I were you I would say I do not know this question instead of saying it nonsense.
*Wednesday, November 13, 2013 at 4:48am*

**statistics**

The average gasoline price of one of the major oil companies has been $3.20 per gallon. Because of cost reduction measures, it is believed that there has been a significant reduction in the average price. In order to test this belief, we randomly selected a sample of 36 of the...
*Tuesday, November 12, 2013 at 8:44pm*

**Statistics**

e) LOS = 29 for one of the patients. This would be considered an outlier. f) Perhaps a better measure of central tendency would be the median.
*Tuesday, November 12, 2013 at 5:15pm*

**Statistics**

You will need to compute the mean and standard deviation. Once you have those values, you can compute the rest using formulas. a) standard error of the mean = sd/√n Note: sd = standard deviation; n = sample size b) Margin of error = 1.96(sd/√n) Note: 1.96 ...
*Tuesday, November 12, 2013 at 5:01pm*

**Statistics**

a.( 13 +14 +17 +14 +17 +15)/6 = 90/6 = 15 b. 15 -+ 1.28 * 1.67/ sqrt(6)) = [ 14.127, 15.873] c. 15 -+ 2.33* 1.67/ sqrt(6)) = [13.411, 16.589]
*Tuesday, November 12, 2013 at 3:52pm*

**Statistics**

You are given the following information obtained from a random sample of 6 observations. Assume the population has a normal distribution. 13 14 17 14 17 15 a. What is the point estimate of µ? b. Construct an 80% confidence interval for µ. c. Construct a 98% ...
*Tuesday, November 12, 2013 at 2:44pm*

**Statistics**

The monthly incomes from a random sample of workers in a factory are shown below. Monthly Income (In $1,000) 4.0 5.0 7.0 4.0 6.0 6.0 7.0 9.0 a. Compute the standard error of the mean (in dollars). b. Compute the margin of error (in dollars) at 95% confidence. c. Compute a 95% ...
*Tuesday, November 12, 2013 at 2:33pm*

**Statistics**

The table below shows the LOS for a sample of 11 discharged patients. Using the data in the table, calculate the mean, range, variance, and standard deviation, and then answer questions e and f. Round the variance and standard deviation to one decimal place. a. Mean b. Range ...
*Monday, November 11, 2013 at 7:37pm*

**Statistics**

A state survey investigates whether the proportion of 8% for employees who commute by car to work is higher than it was five years ago. A test on employee commuting by car was done on a random sample size of 1000 and found 100 commuters by car. Test an appropriate hypothesis ...
*Monday, November 11, 2013 at 6:12pm*

**Statistics**

An opinion poll asks a random sample of 100 college seniors how they view their job prospects. In all, 53 say "Good." The 95% confidence interval has a margin of error of 9.9%. The sample used actually included 130 college seniors but 30 of the seniors refused to ...
*Monday, November 11, 2013 at 3:51pm*

**statistics**

a) Z = (score-mean)/SD Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z score. Do you consider it appropriate? b) It would help if you proofread your questions ...
*Monday, November 11, 2013 at 3:22pm*

**statistics**

Percent = mean ± ? SEm Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportions/probabilities related to one-half of the desired percentages to find the Z score and its distance from the ...
*Monday, November 11, 2013 at 3:16pm*

**statistics**

Percent = mean ± ? SEm Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportions/probabilities related to one-half of the desired percentages to find the Z score and its distance from the ...
*Monday, November 11, 2013 at 3:16pm*

**statistics**

P is less than OR equal (≤) .01, which leads me to believe that taking aspirin reduces mortality.
*Monday, November 11, 2013 at 3:08pm*

**Statistics**

The U.S. Department of Labor and Statistics released the current unemployment rate of 5.3% for the month in the U.S. and claims the unemployment has not changed in the last two months. However, the states statistics reveal that there is a decrease in the U.S. unemployment rate...
*Monday, November 11, 2013 at 2:52pm*

**Statistics**

To plan the budget for next year a college needs to estimate what impact current economic downturn might have on student requests for financial aid. Historically, this college has provided aid to 35% of its students. Officials look at a random sample of this year’s ...
*Monday, November 11, 2013 at 2:50pm*

**Statistics (Ooops)**

Excuse me. Is .05 > P > .01? Again, we don’t know.
*Monday, November 11, 2013 at 2:34pm*

**Statistics**

See Previous post.
*Monday, November 11, 2013 at 2:33pm*

**Statistics**

C. Is the .05 > Alpha > .01? We don’t know.
*Monday, November 11, 2013 at 2:32pm*

**Statistics**

http://www.chegg.com/homework-help/definitions/type-i-and-type-ii-errors-31
*Monday, November 11, 2013 at 2:29pm*

**Statistics**

1. A Type II error occurs when you reject the null hypothesis when the null hypothesis is true. A) True (this one?) B) False 2. A Type II error occurs when you fail to reject the null when the null hypothesis is false. A) True (this one?) B) False
*Monday, November 11, 2013 at 12:09pm*

**statistics**

hey
*Monday, November 11, 2013 at 10:09am*

**Statistics**

We conducted a hypothesis test for a population parameter at alpha = 0.05 and we failed to rejected Ho. If we decided to use alpha = 0.10, how would our conclusion change? A) At alpha = 0.10, we would still fail to reject HO. B) At alpha = 0.10, we would reject HO. C) It is ...
*Monday, November 11, 2013 at 9:51am*

**Statistics**

We conducted a hypothesis test for a population parameter at alpha = 0.01 and we failed to rejected Ho. If we decided to use alpha = 0.05, how would our conclusion change? A) At alpha = 0.05, we would still fail to reject HO. B) At alpha = 0.05, we would reject HO. C) It is ...
*Monday, November 11, 2013 at 9:50am*

**Statistics**

Standard error = .385/sqrt ((44)) = 0.058 E = 1.96 *. 385 sqrt(44) = 5.00 Mean - E, Mean + E 126-5, 126 + 5 ($121, $131) Standard error = .385/sqrt ((22) = 0.082 E = 1.96 * .385 sqrt(22) = 3.5 Mean - E, Mean + E 126- 3.5, 126 + 3.5 ( $122.5, $129.5)
*Sunday, November 10, 2013 at 8:03pm*

**Statistics**

You're right 2E + 121 = 131 2E + 121-121 = 131 -121 2E = 10 E = 5 Mean + E = 131 Mean +5 -5 =131-5 Mean =$126 You're right
*Sunday, November 10, 2013 at 7:03pm*

**Statistics**

Hoping to lure more shoppers downtown, a city builds a new parking garage in the central business district. The city hopes that the parking revenues will pay for the garage. During a recent two month period (44 days), the city statistician calculated the 95% confidence ...
*Sunday, November 10, 2013 at 6:32pm*

**Statistics**

Hoping to lure more shoppers downtown, a city builds a new parking garage in the central business district. The city hopes that the parking revenues will pay for the garage. During a recent two month period (44 days), the city statistician calculated the 95% confidence ...
*Sunday, November 10, 2013 at 6:31pm*

**Statistics**

s/(sqrt((n))
*Sunday, November 10, 2013 at 4:25pm*

**Statistics**

You're right.
*Sunday, November 10, 2013 at 4:04pm*

**Statistics**

According to a study by the Centers for Disease Control, the national mean hospital stay after childbirth is 2.1 days. Reviewing records at her own hospital, a hospital administrator calculates that the mean hospital stay for a random sample of 81 women after childbirth is 2.3...
*Sunday, November 10, 2013 at 3:07pm*

**Statistics**

According to a study by the Centers for Disease Control, the national mean hospital stay after childbirth is 2.1 days. Reviewing records at her own hospital, a hospital administrator calculates that the mean hospital stay for a random sample of 81 women after childbirth is 2.3...
*Sunday, November 10, 2013 at 3:06pm*

**Statistics**

According to a study by the Centers for Disease Control, the national mean hospital stay after childbirth is 2.1 days. Reviewing records at her own hospital, a hospital administrator calculates that the mean hospital stay for a random sample of 81 women after childbirth is 2.3...
*Sunday, November 10, 2013 at 3:05pm*

**statistics**

given the following information, determine the 68.3 percent, 95.5 percent, and 99.7 percent confidence intervals. Mean = 4.33, standard error of the mean =3
*Sunday, November 10, 2013 at 8:29am*

**statistics**

using the following information, determine if the differences between the means are significant medical terminolgy class. Group A = number of word elements remembered by students using flash cards, group B= number of word elements remembered by students not using flash cards. ...
*Saturday, November 9, 2013 at 11:08pm*

**statistics**

based on the results below, how would you decribe the relationship between heart attack patients being treated with aspirin and whether or not they live? males who lived and treated with aspirin = 15, males who did not live, and treated with aspirin = 2, and males who lived ...
*Saturday, November 9, 2013 at 10:57pm*

**statistics**

Assume that human body temperature are normally distributed with a mean 98.21 F and a standard deviation of 0.61F a)A hospital uses 100.6 as the lowest temperature considered to be a fever. What percentage of normal and healthy persons would be considered to have a fever. Does...
*Saturday, November 9, 2013 at 9:57pm*

**statistics**

given the following information, determine the 68.3 percent, 95.5 percent, and 99.7 percent confidence intervals. Mean = 4.33, standard error of the mean =3
*Saturday, November 9, 2013 at 9:48pm*

**Statistics**

Okay so my total is 1637 divided by 18 patients is it? 1637/18=90.9 round that off to one decimal place =91.0 days is that correct?? I confuse myself with all of this. Thanks so much for your help Kuai!
*Saturday, November 9, 2013 at 6:17pm*

**Statistics**

You're right. The total LOS divided by the number of patients discharge is the average length of stay (ALOS).
*Saturday, November 9, 2013 at 6:13pm*

**Statistics **

Use the following dates to compute the ALOS and median LOS and range. The discharge date is July 2nd (non-leap year). Round the ALOS to one decimal place. Admission Date LOS 1-2 January = 29; February = 28; March = 31; April = 30; May = 31; June = 30; July = 2; Total = 181 1-...
*Saturday, November 9, 2013 at 5:40pm*

**Statistics**

95% = mean ± 1.96 SEm SEm = SD/√n
*Saturday, November 9, 2013 at 5:07pm*

**Statistics**

a. mean = (1+3+5+3+2+29+3+4+2+1+2)/11 =55/11= 5 (1-5) = x (x-x̅) (x-x̅)^2 1 -4 16 3 -2 4 5 0 0 3 -2 4 2 -3 9 29 24 576 3 -2 4 4 -1 1 2 -3 9 1 -4 16 2 -3 9 b. Range= highest value - lowest value Range =29-1 = 28 c. variance = (x-x̅)^2 = 648 648/(11-) = 64.8 d. ...
*Saturday, November 9, 2013 at 2:47pm*

**Statistics**

It didn't come out right, the numbers 1,3,5,3,2, 29,3, 4, 2, 1, 2 are supposed to be under the column of length of stay. Columns Los-mean (5) and LOS-Mean)2 are intentionally left empty. And the x-x) and (x-x)2 signs are under the LOS mean columns. I need help, someone ...
*Saturday, November 9, 2013 at 2:19pm*

**Statistics **

The table below shows the LOS for a sample of 11 discharged patients. Using the data in the table, calculate the mean, range, variance, and standard deviation, and then answer questions e and f. Round the variance and standard deviation to one decimal place. a. Mean b. Range c...
*Saturday, November 9, 2013 at 2:14pm*

**Statistics**

Z = (mean1 - mean2)/standard error (SE) of difference between means SEdiff = √(SEmean1^2 + SEmean2^2) SEm = SD/√n If only one SD is provided, you can use just that to determine SEdiff. Find table in the back of your statistics text labeled something like "...
*Saturday, November 9, 2013 at 10:59am*

**Statistics**

99% = mean ± 2.575 SEm SEm = SD/√n
*Saturday, November 9, 2013 at 10:54am*

**Statistics**

Z = (score-mean)/SEm SEm = SD/√n Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to your Z score.
*Saturday, November 9, 2013 at 10:51am*

**Statistics**

30 randomly selected cans of Coke are measured for the amount of cola in ounces. The sample values have a mean of 12.18 ounces and a standard deviation of 0.118 ounces. The 99% confidence interval is ( ounces, ounces). Round each result to two decimal places.
*Saturday, November 9, 2013 at 9:56am*

**Statistics**

30 randomly selected cans of Coke are measured for the amount of cola in ounces. The sample values have a mean of 12.18 ounces and a standard deviation of 0.118 ounces. Test the claim that cans of coke have a mean amount of cola greater than 12 ounces. What is the p-value? A) ...
*Saturday, November 9, 2013 at 9:55am*

**Statistics**

According to a study by the Centers for Disease Control, the national mean hospital stay after childbirth is 2.1 days. Reviewing records at her own hospital, a hospital administrator calculates that the mean hospital stay for a random sample of 81 women after childbirth is 2.3...
*Saturday, November 9, 2013 at 9:10am*

**Statistics**

According to a study by the Centers for Disease Control, the national mean hospital stay after childbirth is 2.1 days. Reviewing records at her own hospital, a hospital administrator calculates that the mean hospital stay for a random sample of 81 women after childbirth is 2.3...
*Saturday, November 9, 2013 at 9:08am*

**statistics**

Assuming you want to be above 1.75, yes you are correct http://davidmlane.com/hyperstat/z_table.html enter 1.75 in "above" to get 0.0401
*Saturday, November 9, 2013 at 8:57am*

**statistics**

Find the indicated critical value. z 0.04 Round to two decimal places as needed. My answer is 1.75 what do guys think.
*Saturday, November 9, 2013 at 7:27am*

**Statistics**

a = 0.03 a = .05 Reject Ho. answer D. If a = 0.02 0.01 0.025 Then fail to reject the H0. Answer C
*Friday, November 8, 2013 at 11:59pm*

**Statistics**

So 72 is not in interval. answer A.
*Friday, November 8, 2013 at 11:38pm*

**statistics**

.9452 close to .945 Z = 1.60
*Friday, November 8, 2013 at 11:29pm*

**statistics**

Find the indicated z score. The graph depicts the standard distribution with a mean 0 and standard deviation 1. 0.945 My answer is 1.6901 but I am not sure if it is correct.
*Friday, November 8, 2013 at 8:52pm*

**Statistics**

A researcher performs a hypothesis test to test the claim that among girls aged 9-10, the mean score on a particular aptitude test differs from 72, which is the mean score for boys of the same age. Data were collected from a random sample of 43 girls aged 9-10 years and the 95...
*Friday, November 8, 2013 at 7:21pm*

**Statistics**

A local eat-in pizza restaurant wants to investigate the possibility of starting to deliver pizzas. The owner of the store has determined that home delivery will be successful if the average time spent on the deliveries does not exceed 30 minutes. The owner has randomly ...
*Friday, November 8, 2013 at 7:19pm*

**Statistics**

In creating a frequency distribution table, which of the following statement is not a basic rule to follow? a) Choose classes that cover the smallest and largest values. b) Make certain that each item can go into only one class. c) As a general rule, use between 10 and 15 ...
*Friday, November 8, 2013 at 10:12am*

**Statistics**

When creating histograms, which is true statement? a) Form classes of equal width b) Alwyas form frequency groups that do not overlap c) Establish between five and 15 frequency groups d) All of the above.
*Friday, November 8, 2013 at 10:09am*

**Statistics**

12
*Friday, November 8, 2013 at 3:33am*

**Statistics**

r = .8519 yhat = 0.411 + 1.216x
*Friday, November 8, 2013 at 12:26am*

**Statistics**

se2 = sqrt (SSE/n-2)) e = y-yhat e = 26.24-.18(22) =22.28 x. y. y hat e e^2 22. 15. 22.28. -7.28. 52.9984 11. 24. 24.26 -.26. 0.0676 7. 28. 24.98. 30.2. 9.1204 18. 28. 23. 5. 25 14. 33. 23.72. 9.28. 86.1184 8. 27. 24.8. 2.2. 4.84 22. 21. 22.28 -1.28. 1.6384 9. 30. 24.62. 5.38...
*Friday, November 8, 2013 at 12:01am*

Pages: <<Prev | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | **12** | 13 | 14 | 15 | 16 | 17 | 18 | Next>>

Post a New Question | Current Questions