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April 19, 2014

April 19, 2014

**Recent Homework Questions About Statistics**

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**Statistics**

Use confidence interval formulas for proportions. CI95 = p + or - (1.96)(√pq/n) ...where √ = square root, p = x/n, q = 1 - p, and n = sample size. Hint: x = 150, n = 240 Convert all fractions to decimals to work the formulas. I hope this will help get you started.
*Tuesday, April 8, 2014 at 5:15pm*

**Statistics**

Use confidence interval formulas for proportions. CI95 = p + or - (1.96)(√pq/n) ...where √ = square root, p = x/n, q = 1 - p, and n = sample size. CI90 = p + or - (1.645)(√pq/n) Hint: x = 396, n = 621 Convert all fractions to decimals to work the formulas. I ...
*Tuesday, April 8, 2014 at 5:08pm*

**Statistics PLEASE HELP ME!**

You might try this formula: Pr[T ≤ t] = 1 - e^-ht h = reciprocal of the mean t = time Therefore, the reciprocal of 25 is 1/25 or .04 Substituting into the formula: Pr[T ≤ 20] = 1 - e^-.04(20) = 1 - e^-.8 = 1 - .4493 = .5507 Check these calculations.
*Tuesday, April 8, 2014 at 5:01pm*

**statistics**

If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events. a. .39^2 = ? b. .39 * (39-1)/(100-1) = ?
*Tuesday, April 8, 2014 at 3:26pm*

**statistics**

a. with replacement? b. without replacement?
*Monday, April 7, 2014 at 11:51pm*

**statistics**

if 2 out of 100 second graders are randomly selected, find the probability that they are both boys and like spring. boys/spring 39
*Monday, April 7, 2014 at 11:48pm*

**Statistics PLEASE HELP ME!**

Collina’s Italian Café in Houston, Texas, advertises that carryout orders take about 25 minutes (Collina’s website, February 27, 2008). Assume that the time required for a carryout order to be ready for customer pickup has an exponential distribution with a ...
*Monday, April 7, 2014 at 10:36pm*

**Economic/Statistics**

Collina’s Italian Café in Houston, Texas, advertises that carryout orders take about 25 minutes (Collina’s website, February 27, 2008). Assume that the time required for a carryout order to be ready for customer pickup has an exponential distribution with a ...
*Monday, April 7, 2014 at 9:27pm*

**Statistics**

In a survey of 621 males ages 18-64 , 396 say they have gone to the dentist in the past year. Construct 90% and 95% confidence intervals for the proportion. Interpret the results and compare the widths of the confidence intervals. Please show step by step. Thank you!
*Monday, April 7, 2014 at 9:09pm*

**statistics**

Collina’s Italian Café in Houston, Texas, advertises that carryout orders take about 25 minutes (Collina’s website, February 27, 2008). Assume that the time required for a carryout order to be ready for customer pickup has an exponential distribution with a ...
*Monday, April 7, 2014 at 7:52pm*

**Statistics**

In a recent study, 100 males used a new weight-loss supplement, and all but 20 of them experienced weight loss after two weeks. In the same study, 20 females used the same supplement, and all but 4 of them experienced weight loss after two weeks. The new weight loss supplement...
*Monday, April 7, 2014 at 7:29pm*

**Statistics**

Professor York randomly surveyed 240 students at Oxnard University, and found that 150 of the students surveyed watch more than 10 hours of television weekly. Develop a 95% confidence interval to estimate the true proportion of students who watch more than 10 hours of ...
*Monday, April 7, 2014 at 6:54pm*

**statistics**

P(z <-1.0) = 0.1587 P(z <-1.5) = 0.0668 P(z <-2.5) = 0.0062 P(-3 < z < 0) = 0.500-0.0013
*Monday, April 7, 2014 at 5:48pm*

**statistics**

c. z = (100-120)/(200sqrt(120*.4) z = (110-120)/200/sqrt(120*.4)) d. z = (130-120)/200/sqrt((120*.4)) Use Z table
*Monday, April 7, 2014 at 5:37pm*

**statistics**

Assume a binomial probability distribution has p = .60 and n = 200. c. What is the probability of 100 to 110 successes (to 4 decimals)? d. What is the probability of 130 or more successes (to 4 decimals)?
*Monday, April 7, 2014 at 5:14pm*

**statistics**

Given that z is a standard normal random variable, compute the following probabilities (to 4 decimals). P(z -1.0) P(z -1.0) P(z -1.5) P(z -2.5) P(-3 < z 0)
*Monday, April 7, 2014 at 5:13pm*

**statistics**

Collina’s Italian Café in Houston, Texas, advertises that carryout orders take about 25 minutes (Collina’s website, February 27, 2008). Assume that the time required for a carryout order to be ready for customer pickup has an exponential distribution with a ...
*Monday, April 7, 2014 at 5:13pm*

**Statistics**

I think you are referring to "dummy coding" but you may want to check this.
*Monday, April 7, 2014 at 5:04pm*

**statistics**

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportions/probabilities related to the Z scores.
*Monday, April 7, 2014 at 11:52am*

**Statistics**

A
*Monday, April 7, 2014 at 10:11am*

**Statistics / Math**

Calculate the standard deviation for: 10, 20, 30 to the nearest tenth presuming a sample
*Monday, April 7, 2014 at 12:41am*

**statistics**

30
*Sunday, April 6, 2014 at 11:08pm*

**statistics**

21
*Sunday, April 6, 2014 at 11:07pm*

**statistics**

28
*Sunday, April 6, 2014 at 11:06pm*

**statistics**

47
*Sunday, April 6, 2014 at 11:02pm*

**statistics**

by the way that calculator uses x - mean for z instead of (x-mean)/sigma
*Sunday, April 6, 2014 at 10:04pm*

**statistics**

Here is an online normal distribution calculator: http://davidmlane.com/hyperstat/z_table.html
*Sunday, April 6, 2014 at 9:49pm*

**statistics**

well, you have enough data points to use normal distribution rather than computing with binomials forever and a day. Otherwise use a program or spreadsheet to compute all the binomial coefs and powers and products mean = n p = 200 * .6 = 120 sigma^2 = 120 (.4) = 48 so sigma = ...
*Sunday, April 6, 2014 at 9:20pm*

**statistics**

Collina’s Italian Café in Houston, Texas, advertises that carryout orders take about 25 minutes (Collina’s website, February 27, 2008). Assume that the time required for a carryout order to be ready for customer pickup has an exponential distribution with a ...
*Sunday, April 6, 2014 at 9:04pm*

**statistics**

Given that z is a standard normal random variable, compute the following probabilities (to 4 decimals). P(z -1.0) P(z -1.0) P(z -1.5) P(z -2.5) P(-3 < z 0)
*Sunday, April 6, 2014 at 9:02pm*

**statistics**

Assume a binomial probability distribution has p = .60 and n = 200. c. What is the probability of 100 to 110 successes (to 4 decimals)? d. What is the probability of 130 or more successes (to 4 decimals)?
*Sunday, April 6, 2014 at 9:01pm*

**statistics**

11.68 / 141 = 0.08284 = 8.28%
*Sunday, April 6, 2014 at 8:44pm*

**statistics**

11.68 is what percent of 141
*Sunday, April 6, 2014 at 5:47pm*

**Statistics**

1. For the following research question, specify the parameter and give the null and alternative hypotheses. "Is there a difference in the proportions of male and female college students who smoke cigarettes? 2. For the following research question, specify the parameter ...
*Sunday, April 6, 2014 at 4:04pm*

**Statistics**

A procedure in regression analysis where Predictor or Independent Variables are coded as 1 or 0 (representing categories) and can be used to produce ANOVA Tables under the General Linear Model is known as…?
*Sunday, April 6, 2014 at 12:42pm*

**Statistics**

fdgdfgf
*Sunday, April 6, 2014 at 10:42am*

**Statistics**

z = (32-30)/4sqrt(16)) z = 2. Z table
*Sunday, April 6, 2014 at 1:23am*

**statistics**

a. mean = np = 200(.6) =120 Standard deviation = sqrt((.6*.4*200))= sqrt(48)
*Sunday, April 6, 2014 at 1:18am*

**statistics**

Given that z is a standard normal random variable, compute the following probabilities (to 4 decimals). P(z -1.0) P(z -1.0) P(z -1.5) P(z -2.5) P(-3 < z 0)
*Saturday, April 5, 2014 at 11:42pm*

**statistics**

Assume a binomial probability distribution has p = .60 and n = 200. a)What are the mean and standard deviation (to 2 decimals)? b)Why can the normal probability distribution be used to approximate this binomial distribution? c)What is the probability of 100 to 110 successes (...
*Saturday, April 5, 2014 at 11:42pm*

**statistics**

Collina’s Italian Café in Houston, Texas, advertises that carryout orders take about 25 minutes (Collina’s website, February 27, 2008). Assume that the time required for a carryout order to be ready for customer pickup has an exponential distribution with a ...
*Saturday, April 5, 2014 at 11:40pm*

**Statistics**

The height of a certain species of a tree are normally distributed with a mean of 30ft and stand dev of 4ft. If a random sample of 16 of these trees is taken, what is the probability that the sample mean is less than 32fy?
*Saturday, April 5, 2014 at 8:03pm*

**statistics**

Is the distribution normal, positively skewed or negatively skewed? The average (whichever) rounds to 2. The mean is most influenced by deviant scores, so it would be the lowest in a negatively skewed distribution, having relatively more scores above it. The mode would be ...
*Saturday, April 5, 2014 at 5:40pm*

**Statistics**

Z = (score-mean)/SD Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z scores.
*Saturday, April 5, 2014 at 5:26pm*

**Statistics**

I also agree
*Saturday, April 5, 2014 at 5:14pm*

**Business statistics**

If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events. .67^3 = ?
*Saturday, April 5, 2014 at 5:13pm*

**Statistics**

Typo P(all) = 3C3 (.67)^3(.33)^0 =0. 300763 Answer is 0.301
*Saturday, April 5, 2014 at 3:35pm*

**statistics**

76.8
*Saturday, April 5, 2014 at 3:24pm*

**Statistics**

P(all) = 3C3 (.67)^3(.33)^0 = 300763 Answer is 0.301
*Saturday, April 5, 2014 at 2:05pm*

**Statistics**

Yes it is
*Saturday, April 5, 2014 at 1:57pm*

**Statistics**

P(all) = 3C3 (.67)^3 (.33)^0 =
*Saturday, April 5, 2014 at 1:56pm*

**statistics**

You are responsible for planning the parking needed for a new 256-unit apartment complex, and you are told to base the needs on the statistic “average number of vehicles per household is 1.9.” Which average (mean, median, mode) would be best if: • You wanted to ...
*Saturday, April 5, 2014 at 1:13pm*

**Statistics**

You take a trip by air that involves three independent flights. If there is an 67% chance each specific leg of the trip is on time, what is the probability all three flights arrive on time? (Round your answer to 3 decimal places.) Probability= ? My answer is 0.301 3 decimal ...
*Saturday, April 5, 2014 at 11:35am*

**Statistics**

a procedure in REGRESSION NALYSIS WHERE PREDICTOR OR INDEPENDENT VARIABLES ARE CODED AS 1 OR 0 (REPRESENTING CATEGORIES) AND CAN BE USED TO PRODUCE ANOVA TABLES UNDER THE GENERAL LINEAR MODEL IS KNOWN AS?
*Saturday, April 5, 2014 at 8:58am*

**statistics**

I usually get help from free statistics homework help
*Saturday, April 5, 2014 at 8:19am*

**Statistics**

You take a trip by air that involves three independent flights. If there is an 67% chance each specific leg of the trip is on time, what is the probability all three flights arrive on time? (Round your answer to 3 decimal places.) Probability =??
*Friday, April 4, 2014 at 11:28pm*

**Statistics**

4.0
*Friday, April 4, 2014 at 9:54pm*

**statistics**

Dylan wants to determine a 90 percent confidence interval for the true proportion of high school students in the area who attend their home basketball games. How large of a sample must he have to get a margin of error less than 0.03? [To find n, use the value p* = 1/2 for the ...
*Friday, April 4, 2014 at 9:10pm*

**Business statistics**

You take a trip by air that involves three independent flights. If there is an 67% chance each specific leg of the trip is on time, what is the probability all three flights arrive on time? (Round your answer to 3 decimal places.) Probability=
*Friday, April 4, 2014 at 8:19pm*

**Statistics **

A survey of top executives revealed that 37% of them regularly read Time magazine, 21% read Newsweek and 38% read U.S. News & World Report. Eleven percent read both Time and U.S. News & World Report. What is the probability that a particular top executive reads either Time or ...
*Friday, April 4, 2014 at 7:46pm*

**Statistics**

You take a trip by air that involves three independent flights. If there is an 67% chance each specific leg of the trip is on time, what is the probability all three flights arrive on time? (Round your answer to 3 decimal places.) Probability=
*Friday, April 4, 2014 at 6:52pm*

**Statistics**

You're welcome.
*Friday, April 4, 2014 at 6:40pm*

**Statistics**

A survey of top executives revealed that 37% of them regularly read Time magazine, 21% read Newsweek and 38% read U.S. News & World Report. Eleven percent read both Time and U.S. News & World Report. What is the probability that a particular top executive reads either Time or ...
*Friday, April 4, 2014 at 6:39pm*

**Statistics**

Thank you
*Friday, April 4, 2014 at 6:38pm*

**Statistics**

25/894 or 0.028
*Friday, April 4, 2014 at 6:28pm*

**Statistics**

The National Center for Health Statistics reported that of every 894 deaths in recent years, 25 resulted from an automobile accident, 185 from cancer and 309 from heart disease. What is the probability that a particular death is due to an automobile accident? 25/309 or 0.081 ...
*Friday, April 4, 2014 at 6:20pm*

**Statistics **

The heights of 18 year old men are approximately normally distributed, with a mean of 67 inches and a standard deviation of 5 inches. What is the probability an 18 year old man selected at random is between 66 and 68 inches? Use FOUR decimal places.
*Friday, April 4, 2014 at 1:43pm*

**Algebra 2**

We do not do your homework for you. Although it might take more effort to do the work on your own, you will profit more from your effort. We will be happy to evaluate your work though. However, I will start you out with the first problem. I assume that you want the proportion ...
*Friday, April 4, 2014 at 12:19pm*

**Statistics - Please help**

Lmao, I said F U C K You
*Thursday, April 3, 2014 at 10:06pm*

**Statistics - Please help**

!@#$%^& YOU
*Thursday, April 3, 2014 at 10:06pm*

**statistics**

You can try a proportional one-sample z-test for this problem. Check a table for the critical value to compare to the test statistic. If the test statistic exceeds the critical value, then reject the null and accept the alternative hypothesis.
*Thursday, April 3, 2014 at 5:10pm*

**Statistics - Please help**

stop cheating
*Thursday, April 3, 2014 at 4:24pm*

**Statistics - Please help**

An experiment was conducted to determine the abrasion resistance of a new type of automobile paint. Twelve different strips of metal were painted with the new paint. The abrasion resistance of each piece was then tested on a machine. In the sample, the abrasion resistance ...
*Thursday, April 3, 2014 at 3:55pm*

**statistics**

Positive, since both are increasing together.
*Thursday, April 3, 2014 at 1:37pm*

**maths**

I searched Google under the key words "statistics alpha beta error" to get these possible sources: https://www.google.com/search?client=safari&rls=en&q=statistics+alpha+beta+error&ie=UTF-8&oe=UTF-8 In the future, you can find the information you desire ...
*Thursday, April 3, 2014 at 1:19pm*

**statistics**

à manufacturer of computers designed to aid social scientists in analyzing research data clams that his computers are opérational for at least 80 percent of the time. during the course of the year one computer was operational for 270 days. test, 1 percent ...
*Thursday, April 3, 2014 at 6:47am*

**Statistics**

Wft this question is older then my booty
*Thursday, April 3, 2014 at 1:32am*

**statistics**

Since, in general, the longer a car is owned the more miles it travels one can say there is ______ between age of a car and milege. a positive association, no association, a negative association, a scattered association
*Wednesday, April 2, 2014 at 8:09pm*

**statistics/probability**

lijlkjllkjlkj
*Wednesday, April 2, 2014 at 5:19pm*

**statistics**

a. E= 1.96 * sqrt((.56*.44/100)) = .09729 b. E= 1.96 * sqrt((.56*.44/400)) = .0486
*Wednesday, April 2, 2014 at 1:51pm*

**statistics**

For each combination of sample size and sample proportion, find the margin of error for the 95% confidence level. (a) n=100 and p-hat=.56 (b) n=400 and p-hat=.56
*Wednesday, April 2, 2014 at 11:27am*

**statistics**

An experiment was conducted to determine the abrasion resistance of a new type of automobile paint. Twelve different strips of metal were painted with the new paint. The abrasion resistance of each piece was then tested on a machine. In the sample, the abrasion resistance ...
*Wednesday, April 2, 2014 at 11:19am*

**Statistics**

0.2 = (230-226.2)/SD 0.2SD = 3.8 SD = 19
*Wednesday, April 2, 2014 at 1:16am*

**Statistics **

9 points) In a normally distributed data set, find the value of the standard deviation if the following information is given. a. The mean is 226.2. x = 230. z = 0.2. Standard deviation
*Tuesday, April 1, 2014 at 10:18pm*

**Business Statistics**

*
*Tuesday, April 1, 2014 at 9:19pm*

**Statistics**

5
*Tuesday, April 1, 2014 at 4:01pm*

**statistics**

105.88
*Tuesday, April 1, 2014 at 12:48pm*

**statistics**

Survey on concern for criminal in a survey 3 of 4 students said the court show too much concern for criminals find the probability that 3 out of 7 randomly selected students will agree with this statement
*Tuesday, April 1, 2014 at 9:24am*

**statistics**

plug in your data here .... http://davidmlane.com/hyperstat/z_table.html to get .4013
*Monday, March 31, 2014 at 7:52pm*

**statistics**

The volumes of soda in quart soda bottles are normally distributed with a mean of 32.3 oz and a standard deviation of 1.2 oz. What is the probability that the volume of soda in a randomly selected bottle will be less than 32 oz?
*Monday, March 31, 2014 at 7:13pm*

**Statistics**

You will have to collect the raw data yourself. Find the mean first = sum of scores/number of scores Subtract each of the scores from the mean and square each difference. Find the sum of these squares. Divide that by the number of scores to get variance. Standard deviation = ...
*Monday, March 31, 2014 at 1:38pm*

**statistics**

first one 12/45 second on 11/44 12/45 * 11/44
*Monday, March 31, 2014 at 8:38am*

**statistics**

In a statistics class of 45 students, 12 have a strong intrest in statistics. If two students are selected at random from this class, what is the propability that both of them have a strong interest in statisitcs?
*Monday, March 31, 2014 at 4:31am*

**Statistics**

I need assistance in calculating the mean and standard deviation from data collected using 2 surveys, strongly agree, agree, neutral, disagree, strongly disagree. Can someone help please? Need the raw data also.
*Sunday, March 30, 2014 at 8:10pm*

**statistics**

Binomial distribution find probability of zero boys P(0) answer is 1 - P(0) n = 6 p = .5 and 1-p = .5 P(0) = C(6,0) (.5)^0 (.5^6) coef for any n,0 = 1 so P(0) = .5^6 = .0156 1-P(0) = .984
*Sunday, March 30, 2014 at 5:03pm*

**statistics**

If boys and girls are equally likely to be born, what is the probability that in a randomly selected family of 6 children, there will be at least one boy? (Find the answer using a formula. Round your answer to three decimal places.)
*Sunday, March 30, 2014 at 4:25pm*

**Statistics**

44
*Sunday, March 30, 2014 at 3:09pm*

**Statistics**

. A 2003 Harris Poll of 993 randomly selected American adults found that 69% believed in capital punishment (death penalty). A sample size of 1010 American adults in 2000 found that 64% believed in capital punishment. Write the hypotheses for a significance test to determine ...
*Saturday, March 29, 2014 at 1:06pm*

**Statistics**

Sorry to ask another question but I keep struggling with this class. If all else remains the same, which of these will make a confidence interval for a proportion narrower? I. Increase the confidence level. II. Increase the sample size. III. Increase the margin of error. A. I ...
*Saturday, March 29, 2014 at 12:59pm*

**Statistics**

Which of these statements is always true for a researcher who is using standard statistical methods in a test of significance? A. A researcher who rejects a true null hypothesis has committed a Type II error. B. A researcher who rejects the null hypothesis has computed a test ...
*Saturday, March 29, 2014 at 12:33pm*

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