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April 16, 2014

April 16, 2014

**Recent Homework Questions About Geometry**

Post a New Question | Current Questions

**geometry**

can not figure out how to simplify a problem into scientific notation
*Wednesday, January 29, 2014 at 6:11pm*

**math**

well, look here: http://www.mathsisfun.com/geometry/interior-angles-polygons.html
*Wednesday, January 29, 2014 at 4:03pm*

**geometry**

there is no equals sign in the second equation.
*Sunday, January 26, 2014 at 9:27pm*

**geometry**

-4x+3y=3 7x-9y-6 solve
*Sunday, January 26, 2014 at 9:20pm*

**geometry**

solve for -4x=3y=3 7x-9y-6
*Sunday, January 26, 2014 at 9:12pm*

**geometry**

de is equal to 17
*Sunday, January 26, 2014 at 1:15pm*

**geometry**

de is equal to 17
*Sunday, January 26, 2014 at 1:15pm*

**Geometry**

Is there a drawing to go with this problem. either send me the text book or where I can find it so I can solve it for you.
*Sunday, January 26, 2014 at 1:09pm*

**Geometry**

Player hits the ball at point A an angle of 45 degrees on a pool table that measures 9’ by 4.5’. How many times will the bait a side of the table before going into a pocket?
*Sunday, January 26, 2014 at 11:27am*

**Geometry/Algebra/Calculus**

the problem is, that to rotate a curve, there has to be a variable radius of rotation. You have the 2pi, but don't specify what the radius of rotation is. area needs to be in square units, but you only have r once, a linear unit.
*Sunday, January 26, 2014 at 6:37am*

**Geometry/Algebra/Calculus**

Why isn't the surface area of a sphere with radius r the following: 2*pi * (pi*r) That comes from the following flow of logic: Doesn't it makes sense to think of the surface area of the sphere with radius r as the the circumference of the semi-circle with radius r, pi*...
*Sunday, January 26, 2014 at 1:46am*

**Math**

You can find your answer at the following site. http://www.mathsisfun.com/geometry/congruent.html
*Saturday, January 25, 2014 at 7:43pm*

**geometry**

In general h = 2*area/base here the base is EG = 21 the area is sqrt[ s(s-a)(s-b)(s-c) ] where s = (a+b+c)/2
*Saturday, January 25, 2014 at 3:46pm*

**geometry**

10, 17, 21 IS NOT a Right triangle, no hypotenuse here
*Saturday, January 25, 2014 at 3:38pm*

**geometry**

triangle GHE GH=10 HE = 17 hypotenuse GE =21 HF is an altitude Find HF
*Saturday, January 25, 2014 at 3:33pm*

**geometry**

A(0.0),B(0,2k),C(2h,0),P(h,k). (AP)^2 = (h-0)^2 + (k-0)^2 = h^2 + k^2 Ap = sqrt(h^2+k^2). (BP)^2=(h-0)^2 + (k-2k)^2=h^2 + (-k^2) BP = sqrt(h^2+(-k)^2). (CP)^2=(h-2h)^2 + (k-0)^2=(-h)^2 + k^2 CP = sqrt((-h)^2+k^2).
*Friday, January 24, 2014 at 7:28pm*

**geometry**

we have two angles of triangle DCB <dbc = 91 <cbd = 43, so <bdc = 46 That means that <adb = 44 Hmmm. Now we seem to be at an impasse. Given what we know, there's no way to determine <abd or <bad. Point A can be anywhere along the line joining A and D. ab ...
*Friday, January 24, 2014 at 4:43pm*

**geometry**

Quad ABCD with diagonal DB. <adc=90, <c=91, <cbd=43. segment ad=segment dc=9. Which segment is longer ab or ad and why? steve, how are you solving for <abd, what are you assuming about <abc?
*Friday, January 24, 2014 at 4:12pm*

**Geometry**

4. Provide the reasons for the proof: Given: Trapezoid RIAG with RI = RG = GA m„£I = m„£NAG Prove: „£T ƒ° „£N Answer: Statement Reason a. RG = GA a. Given b. Trapezoid RIAG b. Given c. || c. d. m„£TRG = m„&...
*Friday, January 24, 2014 at 1:20pm*

**geometry**

volumespace=volume cylinder-volumecone = PI*5^2*16 - 1/3 PI 4^2 * 12
*Thursday, January 23, 2014 at 7:31pm*

**Geometry**

surface area=PI*r*hs + PI*r^2 radius=4x hs=1/6 x modified area=2PI*hs/3 + PI (16)r^2 where r, hs are the original slant heights, and radius.
*Thursday, January 23, 2014 at 7:27pm*

**geometry**

A cylinder has a height of 16 cm and a radius of 5 cm. A cone has a height of 12 cm and a radius of 4 cm. If the cone is placed inside the cylinder as shown, what is the volume of the air space surrounding the cone inside the cylinder? (Use 3.14 as an approximation of π.)
*Thursday, January 23, 2014 at 7:20pm*

**Geometry **

For a cone, if the radius was quadrupled and the slant height was reduced to one sixth of its original size, what would be the formula to find the modified surface area?
*Thursday, January 23, 2014 at 7:01pm*

**Geometry**

area ratio = length ratio^2 if area ratio is 9 length ratio is 3 3 * 3 = 9 is the shortest side of the big one
*Thursday, January 23, 2014 at 3:28pm*

**Geometry**

I would say C but I'm not that far in Geometry
*Thursday, January 23, 2014 at 3:09pm*

**Geometry**

The sides of a quadrilateral are 3, 4, 5, and 6. Find the length of the shortest side of a similar quadrilateral whose area is 9 times as great. A. 9 B. 13.5 C. 27
*Thursday, January 23, 2014 at 3:07pm*

**math**

Hey, I got busy gosh sorry I was doing my Geometry homework at the sametime
*Thursday, January 23, 2014 at 2:46pm*

**math**

Well, sorry I was working on my Geometry math gosh.
*Thursday, January 23, 2014 at 2:19pm*

**Math**

Who knows how to do similar polygons in Geometry?!!!
*Thursday, January 23, 2014 at 2:12pm*

** Geometry**

QR=8, RS=16, UV=18, VT=34,M<S=36, M<T=36 A. No, the triangles are not similar. B. Yes, the scale factor is 1:2. C. Yes, the scale factor is 4:9. D. Yes, the scale factor is 8:17.
*Thursday, January 23, 2014 at 1:30pm*

**geometry**

IDK
*Thursday, January 23, 2014 at 9:56am*

**geometry**

Calculate lengths of ap,bp,cp. A(0,0) B(0,2k) C(2h,0) P(h,k)?
*Wednesday, January 22, 2014 at 2:10pm*

**geometry**

Didn't you just state that gcb = 13x - 9 ? I have no clue what gcb is, or what m fcg is.
*Tuesday, January 21, 2014 at 10:28pm*

**geometry**

If m fcg= 9x+3 and gcb= 13x-9 Find gcb
*Tuesday, January 21, 2014 at 9:45pm*

**geometry**

8/5=3.2/w solve for w w=5*3.2/8
*Tuesday, January 21, 2014 at 8:35pm*

**geometry**

A rectangle is 3.2 centimeters wide and 8 centimeterslong.A similar rectangle is 5centimeters long.What is the width of the second rectangle.
*Tuesday, January 21, 2014 at 8:32pm*

**geometry**

220
*Monday, January 20, 2014 at 11:28pm*

**PHYSICS(HELP)**

each F = k q^2/d^2 side of cube length s = .01 meter now lets put one corner at the origin and look at the one up and across d = sqrt [ (s sqrt 2)^2 + s^2] = s sqrt(3) and d^2 = 3 s^2 now you need directions i,j,k components first component in x y plane, cosines of angles cos ...
*Monday, January 20, 2014 at 5:57pm*

**HELP GEOMETRY**

PRM and QSM are right triangles RM=MS PR=QS by SAS, the triangles are congruent, so PM=QM
*Sunday, January 19, 2014 at 7:01am*

**HELP GEOMETRY**

If PQRS is a rectangle and M is the midpoint of RS, prove PM is congruent to QM. P----------------Q |\ /| | \ / | | \ / | | \ / | | \ / | R--------M-------S *be as explanatory as possible
*Saturday, January 18, 2014 at 6:40pm*

**Geometry Proofs (w/Pic)**

Well, if it is a rhombus we know all the sides are of equal length AND opposite sides are parallel. All we have to prove is that the corner angles are equal CBE=BCE given so CBE=BCE=ADE=DAE intersect parallel lines BE = CE isosceles AD = BC rhombus so triangle AED congruent ...
*Saturday, January 18, 2014 at 6:22pm*

**Geometry Proofs (w/Pic)**

If PQRS is a rectangle and M is the midpoint of RS, prove PM is congruent to QM. P----------------Q |\ /| | \ / | | \ / | | \ / | | \ / | R--------M-------S *be as explanatory as possible
*Saturday, January 18, 2014 at 5:50pm*

**Geometry - 8th grade**

Total Degrees = (N-2)*180 = (5-2)180=540 Missing Angle = 540-(85+110+135+95)=115o
*Friday, January 17, 2014 at 8:50pm*

**geometry**

If the first look is from distance x, then h/x = tan 32° h/(x+66) = tan 22° so, equating values for x, we have h/tan32° = h/tan22° - 66 now just solve for h
*Friday, January 17, 2014 at 4:19pm*

**geometry**

An ant looks to the top of a bulding at an angle of elevation of 32°. The ant then walks an additional 66 feet from the edge of the building. If the new angle of elevation from the ant to the top of the building is 22°, find the height of the building. Round to the ...
*Friday, January 17, 2014 at 3:35pm*

**Geometry**

correct. and volume is cubed.
*Friday, January 17, 2014 at 12:09pm*

**Geometry**

Use the figure of a square pyramid to answer the following questions. a.) Find the total surface area of the pyramid. b.) Find the volume of the pyramid. Do not answer them. I know How to find the answer. Surface Area is squared right?
*Friday, January 17, 2014 at 12:08pm*

**Geometry**

5 feet, 6 inches = 5.5 ft not 5.6 ft I don't have your diagram, so have no clue where your N, S etc are, but I can guess that 5.5/12 = height/30 height = 30(5.5/12) = 13.75 ft = 13 ft, 9 inches
*Friday, January 17, 2014 at 10:46am*

**Geometry**

A person who is 5 feet, 6 inches (5.6 feet) tall casts a shadow (from N to S) that is 12 feet long. The distance along the ground from the person (N) to the flagpole (G) is 18 feet. Find the height of the flagpole (FG) showing all calculations.
*Friday, January 17, 2014 at 10:34am*

**Geometry**

A=10.6cm H^2=84.27 H=9.1 cm
*Friday, January 17, 2014 at 12:40am*

**Geometry - 8th grade**

Well, I am trying to get geometry polygons and angles, but it's really hard to understand what to do. I'm not one to exaggerate and say I'm dying, but I'm pretty desperate for some help. If someone could explain the basics in simple terms or even post a helpful...
*Thursday, January 16, 2014 at 8:51pm*

**Geometry**

What is the reason called when there are two legs on an isosceles triangle, are bisected using a mid segment to form a trapezoid, and you are trying to prove the legs of the trapezoid are congruent?
*Tuesday, January 14, 2014 at 8:50pm*

**Geometry/Math**

According to my diagram, h/445 = 10/45 h = 10(445)/45 = ...
*Tuesday, January 14, 2014 at 5:24pm*

**Geometry/Math**

Judy lies on the ground 45 feet from her tent. Both the top of the tent and the top of a tall cliff are in her line of sight Her tent is 10 feet tall. About how is the cliff? Assume the two triangles are similar. Postscript: The distance from the tent to the cliff is 400 feet...
*Tuesday, January 14, 2014 at 5:15pm*

**geometry**

ratio of height to shadow length is the same for both 5.5/12 = FG/length of flagpole shadow I do not have your diagram so I do not know if the flagpole shadow is 18 feet or 18+12 or whatever
*Tuesday, January 14, 2014 at 11:22am*

**geometry**

A person who is 5 feet, 6 inches (5.5 feet) tall casts a shadow (from N to S) that is 12 feet long. The distance along the ground from the person (N) to the flagpole (G) is 18 feet. Find the height of the flagpole (FG) showing all calculations. What is the length of SP and PF?
*Tuesday, January 14, 2014 at 10:52am*

**Geometry**

You forgot to change 29m to 2900cm.
*Tuesday, January 14, 2014 at 8:26am*

**GEOMETRY**

50 degrees
*Monday, January 13, 2014 at 2:22am*

**Geometry**

Use a proportion to solve this problem. 1.2 / 1.8 = 10/x Cross multiply and solve for x.
*Saturday, January 11, 2014 at 8:45pm*

**Geometry**

Stephanie casts a shadow of 1.2m and she is 1.8m tall. A wind turbine casts a shadow of 10m at the same time that Stephanie measured her shadow. Draw a diagram of this situation and then calculate how tall the wind turbine is.
*Saturday, January 11, 2014 at 8:37pm*

**geometry**

efgh has half the area of abcd, so its side is 6/√2.
*Friday, January 10, 2014 at 5:34pm*

**Geometry**

If we are in one dimension here (on a number line) then -2 + 4 = 2 and -2 - 4 = -6
*Friday, January 10, 2014 at 2:58pm*

**Geometry**

Suppose point J has coordinate of -2 and JK=4. Then what is the possible coordinate(s) for K?
*Friday, January 10, 2014 at 2:42pm*

**geometry**

abcd is a square picture frame. efgh is a square inscribed within abcd as a space for a picture. the area of efgh (for the picture) is equal to the area of the picture frame (the area of abcd minus the area of efgh). if AB=6, what is the length of EF
*Friday, January 10, 2014 at 1:44pm*

**geometry**

Consider the right triangles with AD and BC as hypotenuses. Their height is the same, so their base legs are also the same. So, with all three sides congruent, the angles are also congruent.
*Friday, January 10, 2014 at 12:56pm*

**geometry**

Suppose ABCD is a trapezium in which AB is parallel to CD and AD=BC.prove that angle A=angle B and angle C=angle D.
*Friday, January 10, 2014 at 11:34am*

**geometry**

I don't know
*Wednesday, January 8, 2014 at 8:34pm*

**geometry**

y = [x/4] where [n] is the greatest integer less than or equal to n.
*Wednesday, January 8, 2014 at 5:45am*

**geometry**

what is the algebraic rule for x=4,y=1;x=6,y=1;x=8,y=2;x=10,y=2;x=12,y=3;x=14,y=3;x=16,y=4;x=18,y=4...
*Wednesday, January 8, 2014 at 5:39am*

**geometry**

just use a simple ratio .... 5/2 = h/8 h = 8(5/2) = 20
*Tuesday, January 7, 2014 at 8:30pm*

**geometry**

if a 5-foot tall bush casts a 2-foot shadow how tall is a tree standing next to the bush that casts an 8-foot shadow at the same time?
*Tuesday, January 7, 2014 at 8:27pm*

**Geometry**

its 15
*Tuesday, January 7, 2014 at 7:05pm*

**geometry**

so we are doing: (x,y) --->(x-1, y+3) ----> (x+4, y-1) so for R(-2,-2) (-2,-2) --->(-3, 1) ----> (1, 0) do the same for the other points (I am not sure why you have quotations around S and T in the final result. Are you saying that only S and T are transformed? If ...
*Monday, January 6, 2014 at 9:09pm*

**geometry**

RST with vertices R (-2, -2) , S (-3, 1) , and T (1, 1) is translated by (x, y) → (x - 1, y + 3) . Then the image, RST , is translated by (x, y) → (x + 4, y - 1) , resulting in R "S"T ". a. Find the coordinates for the vertices of R &...
*Monday, January 6, 2014 at 9:01pm*

**Geometry**

Open the book and learn the material. The examples in the textbook you have are pretty easy to follow and correspond to what you are asked on the assessments. HS math is not so difficult that you cannot get at least 60% of the material by your own work with a little effort. ...
*Monday, January 6, 2014 at 2:06pm*

**help hexagon geometry**

drwls you were close it's 4/3
*Friday, January 3, 2014 at 8:53pm*

**geometry**

You have 6 identical equilateral triangles. the area of one of them = (1/2)(11)(11)sin60° = (121/2)(√3/2) so the are of the hexagon = 6(121/2)(√3/2) =appr 314 to the nearest whole number
*Friday, January 3, 2014 at 5:03pm*

**geometry**

what is the area of a hexagon with a base of 11m to the nearest whole number?
*Friday, January 3, 2014 at 12:25pm*

**Geometry**

Since the diagonals of a rectangle are equal, 2x+30 = 36 x = 3
*Thursday, January 2, 2014 at 6:56pm*

**Geometry**

In rectamhle ABCD, diagonals AC and BD intersect at E. if AC=36 and BD=2x+30, find x.
*Thursday, January 2, 2014 at 6:03pm*

**Geometry**

idk
*Thursday, January 2, 2014 at 2:18pm*

**Geometry**

nigaa
*Tuesday, December 31, 2013 at 1:33pm*

**geometry**

Recall that surface area of cone is SA = pi*r^2 + pi*r*s where r = radius s = slant height Substituting, SA = 3.14 * 15^2 + 3.14 * 15 * 11 SA = 706.5 + 518.1 SA = 1224.6 sq units Hope this helps :3
*Monday, December 30, 2013 at 7:56am*

**geometry**

Find the surface area of a cone with a slant height of 11 and a radius of 15. Use 3.14 for ð. Round your answer to the nearest tenth.
*Sunday, December 29, 2013 at 11:44pm*

**Geometry**

200%
*Friday, December 27, 2013 at 11:50pm*

**geometry**

kkmk
*Friday, December 27, 2013 at 3:23am*

**Geometry**

thanks
*Tuesday, December 24, 2013 at 7:39pm*

**Geometry**

Since DE is parallel to OA, and DB = 1/2 AB and EB = 1/2 OB, DE = 1/2 OA
*Tuesday, December 24, 2013 at 6:50pm*

**Geometry**

a,b,o are points in the triangle Then it wants to know an distance and d Is the midpoint of ab and e is the midpoint of Bo so if who take the two midpoints and connect them it' wants to know the distance of them
*Tuesday, December 24, 2013 at 2:24pm*

**Geometry - eh?**

Hard to say. Are a and b points or distances? Where the heck are d and e? Usually, points are labeled with capital letters, and line segments with small letters, or by the two endpoints, as AB or DE.
*Tuesday, December 24, 2013 at 5:50am*

**Geometry**

If point a is (0,n) and b is (k,0) and point o is (0,0) what is the length of a and b And the length of de Do not solve just wants letters
*Tuesday, December 24, 2013 at 12:23am*

**geometry**

Did you sketch it ? AB= √(0^2 + 8^2) = 8 F is (5/2,8) E is (5/2, 0) FE = √( (5/2-5/2)^2 + (8-0)^2 ) = √(0 + 64) = 8 so AB = EF
*Saturday, December 21, 2013 at 8:37pm*

**geometry**

Given: Rectangle ABCD with coordinates A(0, 0), B(0, 8), C(5, 8), and D(5, 0). E is mdpt. of BC, and F is mdpt. of AD. Prove: EF = AB
*Saturday, December 21, 2013 at 7:24pm*

**Geometry.**

the distance must be less than the longest side The longest side is less than the sum of the other two sides The perimeter is the sum of the longest side and the other two sides. That should help.
*Friday, December 20, 2013 at 12:43am*

**Geometry.**

no; the altitudes always intersect. Nor can you infer anything.
*Friday, December 20, 2013 at 12:39am*

**Geometry.**

can you imply something if you are given that two altitudes intersect in a triangle?
*Thursday, December 19, 2013 at 7:08pm*

**Geometry.**

prove that the distance between any two points inside triangle abc is not greater than half the perimeter of triangle abc my teacher said to try doing this proof by contradiction. can someone please help??
*Thursday, December 19, 2013 at 6:59pm*

**geometry**

I sketched your triangle and concluded that the right angle must be at N It is easy to show that triangle MPN ≈ triangle NPO then MP/PN = PN/PO 15/9 = 9/PO 15PO = 81 PO = 81/15 = 27/5
*Thursday, December 19, 2013 at 11:52am*

**geometry**

M 15 z P 9 x N y O
*Thursday, December 19, 2013 at 9:02am*

**geometry**

In a triangle MNO with altitude NP with MP of 15 and NP of 9 what is the length of PO? MNO creates a right angle!
*Thursday, December 19, 2013 at 8:43am*

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