Wednesday
April 16, 2014

Homework Help: Math: Geometry

Recent Homework Questions About Geometry

Post a New Question | Current Questions

geometry
can not figure out how to simplify a problem into scientific notation
Wednesday, January 29, 2014 at 6:11pm

math
well, look here: http://www.mathsisfun.com/geometry/inter​ior-angles-polygons.html
Wednesday, January 29, 2014 at 4:03pm

geometry
there is no equals sign in the second equation.
Sunday, January 26, 2014 at 9:27pm

geometry
-4x+3y=3 7x-9y-6 solve
Sunday, January 26, 2014 at 9:20pm

geometry
solve for -4x=3y=3 7x-9y-6
Sunday, January 26, 2014 at 9:12pm

geometry
de is equal to 17
Sunday, January 26, 2014 at 1:15pm

geometry
de is equal to 17
Sunday, January 26, 2014 at 1:15pm

Geometry
Is there a drawing to go with this problem. either send me the text book or where I can find it so I can solve it for you.
Sunday, January 26, 2014 at 1:09pm

Geometry
Player hits the ball at point A an angle of 45 degrees on a pool table that measures 9’ by 4.5’. How many times will the bait a side of the table before going into a pocket?
Sunday, January 26, 2014 at 11:27am

Geometry/Algebra/Calculus
the problem is, that to rotate a curve, there has to be a variable radius of rotation. You have the 2pi, but don't specify what the radius of rotation is. area needs to be in square units, but you only have r once, a linear unit.
Sunday, January 26, 2014 at 6:37am

Geometry/Algebra/Calculus
Why isn't the surface area of a sphere with radius r the following: 2*pi * (pi*r) That comes from the following flow of logic: Doesn't it makes sense to think of the surface area of the sphere with radius r as the the circumference of the semi-circle with radius r, pi*...
Sunday, January 26, 2014 at 1:46am

Math
You can find your answer at the following site. http://www.mathsisfun.com/geometry/congr​uent.html
Saturday, January 25, 2014 at 7:43pm

geometry
In general h = 2*area/base here the base is EG = 21 the area is sqrt[ s(s-a)(s-b)(s-c) ] where s = (a+b+c)/2
Saturday, January 25, 2014 at 3:46pm

geometry
10, 17, 21 IS NOT a Right triangle, no hypotenuse here
Saturday, January 25, 2014 at 3:38pm

geometry
triangle GHE GH=10 HE = 17 hypotenuse GE =21 HF is an altitude Find HF
Saturday, January 25, 2014 at 3:33pm

geometry
A(0.0),B(0,2k),C(2h,0),P(h,k). (AP)^2 = (h-0)^2 + (k-0)^2 = h^2 + k^2 Ap = sqrt(h^2+k^2). (BP)^2=(h-0)^2 + (k-2k)^2=h^2 + (-k^2) BP = sqrt(h^2+(-k)^2). (CP)^2=(h-2h)^2 + (k-0)^2=(-h)^2 + k^2 CP = sqrt((-h)^2+k^2).
Friday, January 24, 2014 at 7:28pm

geometry
we have two angles of triangle DCB <dbc = 91 <cbd = 43, so <bdc = 46 That means that <adb = 44 Hmmm. Now we seem to be at an impasse. Given what we know, there's no way to determine <abd or <bad. Point A can be anywhere along the line joining A and D. ab ...
Friday, January 24, 2014 at 4:43pm

geometry
Quad ABCD with diagonal DB. <adc=90, <c=91, <cbd=43. segment ad=segment dc=9. Which segment is longer ab or ad and why? steve, how are you solving for <abd, what are you assuming about <abc?
Friday, January 24, 2014 at 4:12pm

Geometry
4. Provide the reasons for the proof: Given: Trapezoid RIAG with RI = RG = GA m„£I = m„£NAG Prove: „£T ƒ° „£N Answer: Statement Reason a. RG = GA a. Given b. Trapezoid RIAG b. Given c. || c. d. m„£TRG = m„&...
Friday, January 24, 2014 at 1:20pm

geometry
volumespace=volume cylinder-volumecone = PI*5^2*16 - 1/3 PI 4^2 * 12
Thursday, January 23, 2014 at 7:31pm

Geometry
surface area=PI*r*hs + PI*r^2 radius=4x hs=1/6 x modified area=2PI*hs/3 + PI (16)r^2 where r, hs are the original slant heights, and radius.
Thursday, January 23, 2014 at 7:27pm

geometry
A cylinder has a height of 16 cm and a radius of 5 cm. A cone has a height of 12 cm and a radius of 4 cm. If the cone is placed inside the cylinder as shown, what is the volume of the air space surrounding the cone inside the cylinder? (Use 3.14 as an approximation of π.)
Thursday, January 23, 2014 at 7:20pm

Geometry
For a cone, if the radius was quadrupled and the slant height was reduced to one sixth of its original size, what would be the formula to find the modified surface area?
Thursday, January 23, 2014 at 7:01pm

Geometry
area ratio = length ratio^2 if area ratio is 9 length ratio is 3 3 * 3 = 9 is the shortest side of the big one
Thursday, January 23, 2014 at 3:28pm

Geometry
I would say C but I'm not that far in Geometry
Thursday, January 23, 2014 at 3:09pm

Geometry
The sides of a quadrilateral are 3, 4, 5, and 6. Find the length of the shortest side of a similar quadrilateral whose area is 9 times as great. A. 9 B. 13.5 C. 27
Thursday, January 23, 2014 at 3:07pm

math
Hey, I got busy gosh sorry I was doing my Geometry homework at the sametime
Thursday, January 23, 2014 at 2:46pm

math
Well, sorry I was working on my Geometry math gosh.
Thursday, January 23, 2014 at 2:19pm

Math
Who knows how to do similar polygons in Geometry?!!!
Thursday, January 23, 2014 at 2:12pm

Geometry
QR=8, RS=16, UV=18, VT=34,M<S=36, M<T=36 A. No, the triangles are not similar. B. Yes, the scale factor is 1:2. C. Yes, the scale factor is 4:9. D. Yes, the scale factor is 8:17.
Thursday, January 23, 2014 at 1:30pm

geometry
IDK
Thursday, January 23, 2014 at 9:56am

geometry
Calculate lengths of ap,bp,cp. A(0,0) B(0,2k) C(2h,0) P(h,k)?
Wednesday, January 22, 2014 at 2:10pm

geometry
Didn't you just state that gcb = 13x - 9 ? I have no clue what gcb is, or what m fcg is.
Tuesday, January 21, 2014 at 10:28pm

geometry
If m fcg= 9x+3 and gcb= 13x-9 Find gcb
Tuesday, January 21, 2014 at 9:45pm

geometry
8/5=3.2/w solve for w w=5*3.2/8
Tuesday, January 21, 2014 at 8:35pm

geometry
A rectangle is 3.2 centimeters wide and 8 centimeterslong.A similar rectangle is 5centimeters long.What is the width of the second rectangle.
Tuesday, January 21, 2014 at 8:32pm

geometry
220
Monday, January 20, 2014 at 11:28pm

PHYSICS(HELP)
each F = k q^2/d^2 side of cube length s = .01 meter now lets put one corner at the origin and look at the one up and across d = sqrt [ (s sqrt 2)^2 + s^2] = s sqrt(3) and d^2 = 3 s^2 now you need directions i,j,k components first component in x y plane, cosines of angles cos ...
Monday, January 20, 2014 at 5:57pm

HELP GEOMETRY
PRM and QSM are right triangles RM=MS PR=QS by SAS, the triangles are congruent, so PM=QM
Sunday, January 19, 2014 at 7:01am

HELP GEOMETRY
If PQRS is a rectangle and M is the midpoint of RS, prove PM is congruent to QM. P----------------Q |\ /| | \ / | | \ / | | \ / | | \ / | R--------M-------S *be as explanatory as possible
Saturday, January 18, 2014 at 6:40pm

Geometry Proofs (w/Pic)
Well, if it is a rhombus we know all the sides are of equal length AND opposite sides are parallel. All we have to prove is that the corner angles are equal CBE=BCE given so CBE=BCE=ADE=DAE intersect parallel lines BE = CE isosceles AD = BC rhombus so triangle AED congruent ...
Saturday, January 18, 2014 at 6:22pm

Geometry Proofs (w/Pic)
If PQRS is a rectangle and M is the midpoint of RS, prove PM is congruent to QM. P----------------Q |\ /| | \ / | | \ / | | \ / | | \ / | R--------M-------S *be as explanatory as possible
Saturday, January 18, 2014 at 5:50pm

Geometry - 8th grade
Total Degrees = (N-2)*180 = (5-2)180=540 Missing Angle = 540-(85+110+135+95)=115o
Friday, January 17, 2014 at 8:50pm

geometry
If the first look is from distance x, then h/x = tan 32° h/(x+66) = tan 22° so, equating values for x, we have h/tan32° = h/tan22° - 66 now just solve for h
Friday, January 17, 2014 at 4:19pm

geometry
An ant looks to the top of a bulding at an angle of elevation of 32°. The ant then walks an additional 66 feet from the edge of the building. If the new angle of elevation from the ant to the top of the building is 22°, find the height of the building. Round to the ...
Friday, January 17, 2014 at 3:35pm

Geometry
correct. and volume is cubed.
Friday, January 17, 2014 at 12:09pm

Geometry
Use the figure of a square pyramid to answer the following questions. a.) Find the total surface area of the pyramid. b.) Find the volume of the pyramid. Do not answer them. I know How to find the answer. Surface Area is squared right?
Friday, January 17, 2014 at 12:08pm

Geometry
5 feet, 6 inches = 5.5 ft not 5.6 ft I don't have your diagram, so have no clue where your N, S etc are, but I can guess that 5.5/12 = height/30 height = 30(5.5/12) = 13.75 ft = 13 ft, 9 inches
Friday, January 17, 2014 at 10:46am

Geometry
A person who is 5 feet, 6 inches (5.6 feet) tall casts a shadow (from N to S) that is 12 feet long. The distance along the ground from the person (N) to the flagpole (G) is 18 feet. Find the height of the flagpole (FG) showing all calculations.
Friday, January 17, 2014 at 10:34am

Geometry
A=10.6cm H^2=84.27 H=9.1 cm
Friday, January 17, 2014 at 12:40am

Geometry - 8th grade
Well, I am trying to get geometry polygons and angles, but it's really hard to understand what to do. I'm not one to exaggerate and say I'm dying, but I'm pretty desperate for some help. If someone could explain the basics in simple terms or even post a helpful...
Thursday, January 16, 2014 at 8:51pm

Geometry
What is the reason called when there are two legs on an isosceles triangle, are bisected using a mid segment to form a trapezoid, and you are trying to prove the legs of the trapezoid are congruent?
Tuesday, January 14, 2014 at 8:50pm

Geometry/Math
According to my diagram, h/445 = 10/45 h = 10(445)/45 = ...
Tuesday, January 14, 2014 at 5:24pm

Geometry/Math
Judy lies on the ground 45 feet from her tent. Both the top of the tent and the top of a tall cliff are in her line of sight Her tent is 10 feet tall. About how is the cliff? Assume the two triangles are similar. Postscript: The distance from the tent to the cliff is 400 feet...
Tuesday, January 14, 2014 at 5:15pm

geometry
ratio of height to shadow length is the same for both 5.5/12 = FG/length of flagpole shadow I do not have your diagram so I do not know if the flagpole shadow is 18 feet or 18+12 or whatever
Tuesday, January 14, 2014 at 11:22am

geometry
A person who is 5 feet, 6 inches (5.5 feet) tall casts a shadow (from N to S) that is 12 feet long. The distance along the ground from the person (N) to the flagpole (G) is 18 feet. Find the height of the flagpole (FG) showing all calculations. What is the length of SP and PF?
Tuesday, January 14, 2014 at 10:52am

Geometry
You forgot to change 29m to 2900cm.
Tuesday, January 14, 2014 at 8:26am

GEOMETRY
50 degrees
Monday, January 13, 2014 at 2:22am

Geometry
Use a proportion to solve this problem. 1.2 / 1.8 = 10/x Cross multiply and solve for x.
Saturday, January 11, 2014 at 8:45pm

Geometry
Stephanie casts a shadow of 1.2m and she is 1.8m tall. A wind turbine casts a shadow of 10m at the same time that Stephanie measured her shadow. Draw a diagram of this situation and then calculate how tall the wind turbine is.
Saturday, January 11, 2014 at 8:37pm

geometry
efgh has half the area of abcd, so its side is 6/√2.
Friday, January 10, 2014 at 5:34pm

Geometry
If we are in one dimension here (on a number line) then -2 + 4 = 2 and -2 - 4 = -6
Friday, January 10, 2014 at 2:58pm

Geometry
Suppose point J has coordinate of -2 and JK=4. Then what is the possible coordinate(s) for K?
Friday, January 10, 2014 at 2:42pm

geometry
abcd is a square picture frame. efgh is a square inscribed within abcd as a space for a picture. the area of efgh (for the picture) is equal to the area of the picture frame (the area of abcd minus the area of efgh). if AB=6, what is the length of EF
Friday, January 10, 2014 at 1:44pm

geometry
Consider the right triangles with AD and BC as hypotenuses. Their height is the same, so their base legs are also the same. So, with all three sides congruent, the angles are also congruent.
Friday, January 10, 2014 at 12:56pm

geometry
Suppose ABCD is a trapezium in which AB is parallel to CD and AD=BC.prove that angle A=angle B and angle C=angle D.
Friday, January 10, 2014 at 11:34am

geometry
I don't know
Wednesday, January 8, 2014 at 8:34pm

geometry
y = [x/4] where [n] is the greatest integer less than or equal to n.
Wednesday, January 8, 2014 at 5:45am

geometry
what is the algebraic rule for x=4,y=1;x=6,y=1;x=8,y=2;x=10,y=2;x=12,y=​3;x=14,y=3;x=16,y=4;x=18,y=4...
Wednesday, January 8, 2014 at 5:39am

geometry
just use a simple ratio .... 5/2 = h/8 h = 8(5/2) = 20
Tuesday, January 7, 2014 at 8:30pm

geometry
if a 5-foot tall bush casts a 2-foot shadow how tall is a tree standing next to the bush that casts an 8-foot shadow at the same time?
Tuesday, January 7, 2014 at 8:27pm

Geometry
its 15
Tuesday, January 7, 2014 at 7:05pm

geometry
so we are doing: (x,y) --->(x-1, y+3) ----> (x+4, y-1) so for R(-2,-2) (-2,-2) --->(-3, 1) ----> (1, 0) do the same for the other points (I am not sure why you have quotations around S and T in the final result. Are you saying that only S and T are transformed? If ...
Monday, January 6, 2014 at 9:09pm

geometry
RST with vertices R (-2, -2) , S (-3, 1) , and T (1, 1) is translated by (x, y) → (x - 1, y + 3) . Then the image, RST , is translated by (x, y) → (x + 4, y - 1) , resulting in R "S"T ". a. Find the coordinates for the vertices of R &...
Monday, January 6, 2014 at 9:01pm

Geometry
Open the book and learn the material. The examples in the textbook you have are pretty easy to follow and correspond to what you are asked on the assessments. HS math is not so difficult that you cannot get at least 60% of the material by your own work with a little effort. ...
Monday, January 6, 2014 at 2:06pm

help hexagon geometry
drwls you were close it's 4/3
Friday, January 3, 2014 at 8:53pm

geometry
You have 6 identical equilateral triangles. the area of one of them = (1/2)(11)(11)sin60° = (121/2)(√3/2) so the are of the hexagon = 6(121/2)(√3/2) =appr 314 to the nearest whole number
Friday, January 3, 2014 at 5:03pm

geometry
what is the area of a hexagon with a base of 11m to the nearest whole number?
Friday, January 3, 2014 at 12:25pm

Geometry
Since the diagonals of a rectangle are equal, 2x+30 = 36 x = 3
Thursday, January 2, 2014 at 6:56pm

Geometry
In rectamhle ABCD, diagonals AC and BD intersect at E. if AC=36 and BD=2x+30, find x.
Thursday, January 2, 2014 at 6:03pm

Geometry
idk
Thursday, January 2, 2014 at 2:18pm

Geometry
nigaa
Tuesday, December 31, 2013 at 1:33pm

geometry
Recall that surface area of cone is SA = pi*r^2 + pi*r*s where r = radius s = slant height Substituting, SA = 3.14 * 15^2 + 3.14 * 15 * 11 SA = 706.5 + 518.1 SA = 1224.6 sq units Hope this helps :3
Monday, December 30, 2013 at 7:56am

geometry
Find the surface area of a cone with a slant height of 11 and a radius of 15. Use 3.14 for ð. Round your answer to the nearest tenth.
Sunday, December 29, 2013 at 11:44pm

Geometry
200%
Friday, December 27, 2013 at 11:50pm

geometry
kkmk
Friday, December 27, 2013 at 3:23am

Geometry
thanks
Tuesday, December 24, 2013 at 7:39pm

Geometry
Since DE is parallel to OA, and DB = 1/2 AB and EB = 1/2 OB, DE = 1/2 OA
Tuesday, December 24, 2013 at 6:50pm

Geometry
a,b,o are points in the triangle Then it wants to know an distance and d Is the midpoint of ab and e is the midpoint of Bo so if who take the two midpoints and connect them it' wants to know the distance of them
Tuesday, December 24, 2013 at 2:24pm

Geometry - eh?
Hard to say. Are a and b points or distances? Where the heck are d and e? Usually, points are labeled with capital letters, and line segments with small letters, or by the two endpoints, as AB or DE.
Tuesday, December 24, 2013 at 5:50am

Geometry
If point a is (0,n) and b is (k,0) and point o is (0,0) what is the length of a and b And the length of de Do not solve just wants letters
Tuesday, December 24, 2013 at 12:23am

geometry
Did you sketch it ? AB= √(0^2 + 8^2) = 8 F is (5/2,8) E is (5/2, 0) FE = √( (5/2-5/2)^2 + (8-0)^2 ) = √(0 + 64) = 8 so AB = EF
Saturday, December 21, 2013 at 8:37pm

geometry
Given: Rectangle ABCD with coordinates A(0, 0), B(0, 8), C(5, 8), and D(5, 0). E is mdpt. of BC, and F is mdpt. of AD. Prove: EF = AB
Saturday, December 21, 2013 at 7:24pm

Geometry.
the distance must be less than the longest side The longest side is less than the sum of the other two sides The perimeter is the sum of the longest side and the other two sides. That should help.
Friday, December 20, 2013 at 12:43am

Geometry.
no; the altitudes always intersect. Nor can you infer anything.
Friday, December 20, 2013 at 12:39am

Geometry.
can you imply something if you are given that two altitudes intersect in a triangle?
Thursday, December 19, 2013 at 7:08pm

Geometry.
prove that the distance between any two points inside triangle abc is not greater than half the perimeter of triangle abc my teacher said to try doing this proof by contradiction. can someone please help??
Thursday, December 19, 2013 at 6:59pm

geometry
I sketched your triangle and concluded that the right angle must be at N It is easy to show that triangle MPN ≈ triangle NPO then MP/PN = PN/PO 15/9 = 9/PO 15PO = 81 PO = 81/15 = 27/5
Thursday, December 19, 2013 at 11:52am

geometry
M 15 z P 9 x N y O
Thursday, December 19, 2013 at 9:02am

geometry
In a triangle MNO with altitude NP with MP of 15 and NP of 9 what is the length of PO? MNO creates a right angle!
Thursday, December 19, 2013 at 8:43am

Pages: <<Prev | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | 13 | 14 | 15 | Next>>

Post a New Question | Current Questions

Homework Help: Math

Search
Members