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April 16, 2014

Homework Help: Math: Calculus

Recent Homework Questions About Calculus

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calculus
Use the principles of translating and reflecting to graph the function f(x)=(x-5)^3 +2
Tuesday, February 4, 2014 at 1:27am

pre calculus
determine the order of magnitude for the following: 1. a $1 bill and a dime 2. two products scored a PH level of 6.1 and 4.o I can't figure out #1… but I did get #2 to be 10^2.1 Please help with #1 and check to see I did #2 right?
Monday, February 3, 2014 at 4:25pm

calculus
y = (-5x+4)/(10-5x) = (4-5x)/(10-5x) At x=2 there is a vertical asymptote, since 10-5x=0 As x gets large, y -> 1 since y = (4/x - 5)/(10/x - 5) -> -5/-5 = 1
Monday, February 3, 2014 at 5:47am

calculus
y= -5x + 4 OVER 10 - 5x find the asymptotes of the function
Monday, February 3, 2014 at 1:37am

Calculus II
Solve the initial value problem using Taylor Series and the following conditions: y'(t) = y(t) + 2t y(0) = A
Sunday, February 2, 2014 at 11:01pm

Calculus
8.42
Sunday, February 2, 2014 at 8:42pm

CALCULUS PLEASE HELP!!!
as you know, the average velocity is the integral divided by the time interval. Since the position is the integral of the velocity, the average velocity in [a,b] = (s(b)-s(a))/(b-a) So, we have i) (s(2)-s(1))/(2-1) = (2sin2π+3)-(2sinπ+3) = 0 ii) (s(1.1)-s(1))/(1.1-1...
Sunday, February 2, 2014 at 8:26pm

CALCULUS PLEASE HELP!!!
SHOW WORK PLEASE!!! The displacement (in centimeters) of a particle moving back and forth along a straight line is given by the equation of motion s = 2 sin πt + 3 cos πt, where t is measured in seconds. (Round your answers to two decimal places.) (a) Find the ...
Sunday, February 2, 2014 at 8:12pm

calculus
g = m t + b m = (17-8)/(47-28) = .4737 so g = .4737 t + b 8 = .4737 (28) + b so b = -5.263 so g = 0.4737 t - 5.263
Sunday, February 2, 2014 at 5:03am

calculus
In a lab experiment 8 grams of acid were produced in 28 minutes and 17 grams in 47 minutes. Let g be the number of grams and m be the number of minutes. Find a linear equation that you could use to calculate g for any number of minutes.
Sunday, February 2, 2014 at 3:28am

calculus
Consider the function f(x) = 5 (x - 5)^(2//3) . For this function there are two important intervals: (-\infty, A) and (A,\infty) where A is a critical number. Find A
Sunday, February 2, 2014 at 2:38am

CALCULUS
I don't understand. Why are you adding 1/4? to both sides? I don't see how you are getting a quadratic formula from this. More importantly, thank you guys for the help!
Sunday, February 2, 2014 at 12:29am

calculus
I guess the foxes were factored in when calculating the surviving rabbit population, eh?
Saturday, February 1, 2014 at 6:41pm

calculus
I bet we want the maximum, but usually the foxes are included in these island problems. dP/dt = 0 at max = 120 -1.6 t^3 t^3 = 120 t = 4.93 months
Saturday, February 1, 2014 at 6:23pm

Calculus & Vectors
240 * 1.25 = 300 @ N20W = <-102.6,281.9> 240 * 2.00 = 480 @ N80E = <472.7,83.4> add 'em up to get <370.1,315.3> So, the distance back is 486.2 300+480+486.2 = 1266.2 km at 240 km/hr = 5.3 hours
Saturday, February 1, 2014 at 6:18pm

Calculus & Vectors
A search and rescue aircraft, travelling at a speed of 240 km/h starts out at a heading of N 20 degrees West. After travelling for 1h and 15 min, it turns to a heading of N 80 degrees E and continues for another two hours before returning to base. Find the total distance the ...
Saturday, February 1, 2014 at 6:10pm

calculus - and?
in the words of Larry King, "What's the question?"
Saturday, February 1, 2014 at 5:32pm

calculus
The rabbit population on a small island is observed to be given by the function P(t)=120t−0.4t4+700 where t is the time (in months) since observations of the island began.
Saturday, February 1, 2014 at 5:28pm

CALCULUS
Whoops !
Saturday, February 1, 2014 at 11:47am

calculus
Well if you only have five days total, hopefully it only takes the remaining one day to solve it! Otherwise, you're in trouble!
Saturday, February 1, 2014 at 11:32am

CALCULUS
noticed an error from line 2 to line 3 y^2 - y = x y^2 - y + 1/4 = x + 1/4 (y - 1/2)^2 =(4x+1)/4 y - 1/2 = ±√(4x+1)/2 y = 1/2 ± √(4x+1)/2 = (1 ± √(4x+1) )/2 , x ≥ -1/4
Saturday, February 1, 2014 at 10:37am

CALCULUS
x = y^2 - y y^2 - y + 1 = x + 1 (y-1)^2 = x + 1 y -1 = sqrt (x+1) y = 1 + sqrt (x+1)
Saturday, February 1, 2014 at 9:46am

COURSE HELP PLEASE ms sue qq
In high school, these courses are usually called Algebra I Algebra II Geometry Pre-calculus AP Calculus Biology AP Biology Chemistry AP Chemistry Physics AP Physics Work with your counselor to make sure you take the required courses for graduation AND as many of these as ...
Saturday, February 1, 2014 at 9:41am

CALCULUS
Find a formula for the inverse of the function. y=x^2-x, x>=(greater than or equal to) 1/2 Please give me a step by step explanation. I think my algebra is wrong... Ty
Saturday, February 1, 2014 at 9:16am

calculus
Four out of five days were used to create a problem, how many days will it take to solve it?
Saturday, February 1, 2014 at 8:21am

calculus
Four out of five days were used to create a problem, how many day will it take to solve it?
Saturday, February 1, 2014 at 8:21am

integral calculus
If you mean ∫[x,4] x/(x-4) dx that's a bit unusual to have the variable of integration as one of the limits. But ok, let's work it out as-is. ∫x/(x-4) dx = x + 4 log(x-4) Evaluating that at 4 and x, we have (4+4log(0))-(x+4log(x-4)) Looks like -∞ to ...
Friday, January 31, 2014 at 10:56pm

integral calculus
Evaluate the limit limit gose from x to 4 (x/x-4)integral from x to 4
Friday, January 31, 2014 at 10:04pm

Calculus
Thank you!
Friday, January 31, 2014 at 10:00pm

Calculus
point in first plane 0,0 something (0 , 0 , 10) d = | 10*0 -8*0 +2*10 -3 | /sqrt(10^2+8^2+4^2) = 17/13.4
Friday, January 31, 2014 at 8:07pm

Calculus
here is an example of how to do this: http://www.math.ucla.edu/~ronmiech/Calcu​lus_Problems/32A/chap11/section5/718d65/​718_65.html
Friday, January 31, 2014 at 8:01pm

Calculus
when x gets really big positive this is y = 2 (big) / sqrt(big ^2) which is y = 2 when x gets really big negative y = 2 (-big number) / big number which is y = - 2 well, let's look at the derivative since they say so [ (x^2+x+1)2 - 2x(.5)(x^2+x+1)^-.5(2x) ]/(x^2+x+1) yuuk...
Friday, January 31, 2014 at 5:50pm

Calculus
we have two points in that plane (8, 0, -2) and (6, 3, 3) a vector through those points has direction (6-8)i + 3 j + (2+2)k = -2 i + 3 j + 4 k so we have two vectors parallel to plane, their cross product is normal to the plane i j k -2 5 2 the given line direction -2 3 4 the ...
Friday, January 31, 2014 at 5:35pm

Calculus
Let f be the function given by f(x)= 2x/(sqrt(x^2 +x +1)) c. Write an equation for each horizontal asymptote of the graph of f. d. Find the range of f. Use f'(x) to justify your answer.
Friday, January 31, 2014 at 5:26pm

Calculus
vector normal to plane has direction 3 i + 2 j + 6 k line normal to plane through point is (1, -5 , 9) + (3, 2, 6) t where does that hit the plane? 3(1+3t) + 2(-5+2t) + 6(9+6t) = 5 solve for t go back and use that t to get x, y, z in plane x = 1+3t y = -5+2t z = 9+6t then d^2...
Friday, January 31, 2014 at 5:09pm

Calculus
pick a point in plane #1, say (2,3,1) Now just use the distance formula to get the distance to 6x-6y+6z=3 or, equivalently, 2x-2y+2z-1 = 0 d = |2*2-2*3+2*1-1|/√(2^2+2^2+1^2) = 1/√5
Friday, January 31, 2014 at 4:47pm

Calculus
see http://www.jiskha.com/display.cgi?id=139​1198824 for the method
Friday, January 31, 2014 at 4:36pm

Calculus
(1+4t) +2 (4t) -(2-3t) = -1 solve for t then use that t to find x, y z
Friday, January 31, 2014 at 4:35pm

Calculus
going from the first point to the second dx = 3 dy = -2 dz = 4 so my line direction is 3 i -2 j + 4 k and my line in parametric form is (1,0,1) + (3, -2, 4) t at intersection x = 1+3t y = -2 t z = 1+4t and we know x + y + z = 10 2 + 5 t = 10 t = 8/5 so x = 1 + 24/5 = 29/5 y...
Friday, January 31, 2014 at 4:32pm

Calculus
perpendicular to the direction 1 i - 1 j + 2 k Vxi + Vyj + Vzk if perpendicular dot product is 0 Vx - Vy + 2 Vz = 0 also parallel to plane x+y+z = constant 2 so normal to the normal to that plane 1 i + 1 j + 1 k Vxi + Vyj + Vzk Vx + Vy + Vz = 0 so we have Vx - Vy + 2 Vz = 0 Vx...
Friday, January 31, 2014 at 4:14pm

Calculus
Find the distance between the given parallel planes. 4z = 4y − 4x, 6z = 3 − 6x + 6y
Friday, January 31, 2014 at 3:15pm

Calculus
Find the distance between the given parallel planes. 5x−4y+z=10, 10x−8y+2z=3
Friday, January 31, 2014 at 3:14pm

Calculus
Find the distance from the point to the given plane. (−3,8,7), x−2y−4z=8
Friday, January 31, 2014 at 3:13pm

Calculus
Find the distance from the point to the given plane. (1,−5,9), 3x+2y+6z=5
Friday, January 31, 2014 at 3:12pm

Calculus
Find parametric equations for the line through the point (0,2,2)that is parallel to the plane x+y+z = 2 and perpendicular to the line x=1+t, y=2−t, z=2t. (Use the parameter t.) (x(t), y(t), z(t)) =
Friday, January 31, 2014 at 3:11pm

Calculus
Where does the line through (1,0,1) and (3,−2,5)intersect the plane x+y+z=10? (x, y, z) =________?
Friday, January 31, 2014 at 3:09pm

Calculus
Find the point at which the line intersects the given plane. x = 1 + 4t, y = 4t, z = 2−3t ; x + 2y − z + 1 = 0 (x, y, z) = _____________?
Friday, January 31, 2014 at 3:07pm

Calculus
Find the point at which the line intersects the given plane. x = 4 − t, y = 5 + t, z = 2t; x − y + 3z = 3 (x, y, z) =____________?
Friday, January 31, 2014 at 3:05pm

Calculus
Find an equation of the plane. The plane that passes through the point (−1, 2, 1)and contains the line of intersection of the planes x + y − z = 4 and 4x − y + 5z = 4
Friday, January 31, 2014 at 3:04pm

Calculus
Find an equation of the plane. The plane that passes through (8, 0, −2)and contains the line x = 6 − 2t, y = 3 + 5t, z = 3 + 2t
Friday, January 31, 2014 at 2:57pm

calculus
22
Friday, January 31, 2014 at 7:27am

CALCULUS
y = 4-(5x-4) = 8-5x
Friday, January 31, 2014 at 6:01am

CALCULUS
Starting with the graph of f(x)=5x, write the equation of the graph that results from reflecting f(x) about the line y =4. y=_______? Thank you!
Friday, January 31, 2014 at 12:27am

Math Pre-Cal
If you do know calculus, find the derivative and set it equal to zero (the slope is 0 at a max or min) 4 x -12 = 0 so x = 3 then y = 2x^2-12x-6 = 2(9) -12(3) -6 =18 - 36 - 6 = -24 that vertex is a minimum because y gets big as x gets big
Thursday, January 30, 2014 at 9:51pm

Math Pre-Cal
If you do not know calculus you must find the vertex of that parabola.
Thursday, January 30, 2014 at 9:45pm

Calculus
l) (g)^2 + (h)^2=1 so 2 g g' + 2 h h' = 0 g g' = -h h' g' = -(h/g) h' 2)g' = h^2 and h' = -g g'/h h' = - g h^2/h = -gh that is part a then If h has a max, then h' has a zero - g h = 0 ? either g = 0 or h = 0 if h is max, look for ...
Thursday, January 30, 2014 at 3:30pm

Calculus
(a) using (i) and (ii) 2gg' + 2hh' = 0 2gh^2 + 2hh' = 0 gh + h' = 0 h' = -gh (b) from (a) and (iv), h'(0) = -g(0)*h(0) = 0 h" = -g'h-gh' so, h"(0) = -g'(0)h(0) Since h(0)>0, g'(0)>0, so h"(0) < 0 (c) from (ii) and...
Thursday, January 30, 2014 at 3:15pm

Calculus
Let g and h be any two twice-differentiable functions that are defined for all real numbers and that satisfy the following properties for all x: I) (g(x))^2 + (h(x))^2=1 ii) g'(x)= (h(x))^2 iii) h(x)>0 iv) g(0)=0 a)Justify that h'(x)=-g(x)h(x) for all x b) Justify ...
Thursday, January 30, 2014 at 2:44pm

Calculus
Thank you!
Thursday, January 30, 2014 at 2:28pm

Calculus II
you know it will be a plane normal to the vector <7,-3,-6> passing through (3/2,9/2,0). I'm sure you've covered that.
Thursday, January 30, 2014 at 11:55am

Calculus II
Find an equation of the set of all points equidistant from the points A(−2, 6, 3) and B(5, 3, −3)
Thursday, January 30, 2014 at 11:33am

Pre-Calculus
factor out 2x^5(x^2-9)^7 and you have 2x^5(x^2-9)^7 * (8x^2 + 3(x^2-9)) = 2x^5(x^2-9)^7 (8x^2+3x^2-27) and voila...
Thursday, January 30, 2014 at 6:09am

Pre-Calculus
Actually I figured out that you use both, and ended up with 16x^7(x^2-9)^7 + 6x^5(x^2-9)^8. but I don't understand how that simplifies to 2x^5(x^2-9)^7(11x^2-27)?
Thursday, January 30, 2014 at 12:47am

Physics
Problem 1 (80 points) Consider a spring of equilibrium length L, lying horizontally in a frictionless trough. The spring has cross sectional area S perpendicular to its length. The trough constrains the motion of the spring so that any wave propagating along the spring is a ...
Wednesday, January 29, 2014 at 11:24pm

Pre-Calculus
Find dy/dx if y= x^6[(x^2-9)^8]? So the answer is supposed to be 2x^5[(x^2-9)^7](11x^2-27), but I don't understand how to get it. Do you use product rule, chain rule or both? thanks
Wednesday, January 29, 2014 at 9:44pm

Calculus
first fall, 40 ft, then second bounce 2(40*3/5), third 2*(40*3/5)(3/5), etc Now, how can you determine what rest is?
Wednesday, January 29, 2014 at 8:17pm

Calculus
A superball is tossed vertically 40 feet and rebounds on each bounce 3/5 of the height from which it fell. How far will it travel before coming to rest?
Wednesday, January 29, 2014 at 8:14pm

Calculus
If you are going to integrate over y, the solid has two parts: a plain old cylinder of height 4 and thickness 2, and a variable-thickness shape of height 2. So, v = π(5^2-3^2)(4) + ∫[4,6] π(R^2-r^2) dy where R=5 and r=x-1=y-1 v = 64π + π∫[4,6] ...
Wednesday, January 29, 2014 at 5:34pm

Calculus
dy/dx = 2/2 = 1 so y = x + b 0 = 3 + b b = -3 so y = x - 3 if x(t) = k t for example then y(t) = x(t) - 3 y(t) = k t - 3
Wednesday, January 29, 2014 at 5:03pm

Calculus
c) as t --->oo v ---->1/t = 0 d) 500 = 5 + .5 ln (t^2+1) 495 (2) = ln(t^2+1) 990 = ln (t^2+1) e^(990) = t^2 + 1 oh, my, calculator overflow :)
Wednesday, January 29, 2014 at 4:58pm

Calculus
dx/dt = t/(1+t^2) that will be maximum when the derivative d^2x/dt^2 = 0 d^2x/dt^2 = [(1+t^2)1 -t(2t) ](1+t^2)^2 0 when numerator is zero 0 = 1 + t^2 - 2 t^2 0 = 1 - t^2 t^2 = 1 so max or min at t = 1 we know it is max because v decreases with big x a ) so max v = 1/2 at t = 1...
Wednesday, January 29, 2014 at 4:53pm

Calculus
A particle starts at the point (5,0) at t=0 and moves along the x-axis in such a way that at time t>0 its velocity v(t) is given by v(t)= t/(1+t^2). a). Determine the maximum velocity of the particle. Justify your answer. b). Determine the position of the particle at t=6. c...
Wednesday, January 29, 2014 at 4:38pm

Calculus
write in parametric form the equation of the line that joins (1,-2) and (3,0)
Wednesday, January 29, 2014 at 4:14pm

Physics
Problem 1 (80 points) Consider a spring of equilibrium length L, lying horizontally in a frictionless trough. The spring has cross sectional area S perpendicular to its length. The trough constrains the motion of the spring so that any wave propagating along the spring is a ...
Wednesday, January 29, 2014 at 3:50pm

Calculus
Consider the solid obtained by rotating the region bounded by the following curves about the line x=1. y=x,y=0,x=4,x=6 Find the volume So it would be pi (integral from 3 to 6) of ((1-y)^2 -(1-0)^2) right? so then you integrate it and get pi(Y^3/3-y^2) from 3 to 6. ?
Wednesday, January 29, 2014 at 3:15pm

Calculus
If the dimensions are x wide and y high, then y = 160/x The printed area is a = (x-2)(y-1-7) = (x-2)(160/x - 8) = 176-8x-320/x da/dx = -8+320/x^2 da/dx=0 when x=2√10 Now figure y and you're done.
Wednesday, January 29, 2014 at 6:16am

calculus
I assumed you wanted the roots of your equation 3x^2+10x-8=7
Wednesday, January 29, 2014 at 5:58am

calculus
how did you get (-5 +/- sqrt(70))/3
Wednesday, January 29, 2014 at 12:12am

Calculus
h = t^(3/4) - 5t^(1/4) h' = 3/4 t^(-1/4) - 5/4 t^(-3/4) = (3√t-5) / 4t^(3/4) h' is undefined at t=0 h' = 0 at t = 25/9
Wednesday, January 29, 2014 at 12:03am

calculus
yes. the mean value theorem lets you pick any interval, but Rolle's theorem says f(a) = f(b). It's just a special case of the MVT where f'(c) = 0. Your interval here meets that condition. As for your exact value, forget about decimal approximations. (-5±&#...
Tuesday, January 28, 2014 at 11:59pm

Calculus
f = x^4 - 8x^2 + 6 f' = 4x^3 - 16x f" = 12x^2 - 16 f'=0 at x = 0,±2 at x = -2, f" > 0 so f has a local min at x = 0, f" = < 0 so f has a local max at x = 2, f" > 0 so f has a local min So, now just evaluate f(x) at 0,±2 and ...
Tuesday, January 28, 2014 at 11:54pm

calculus
i am on "rolles and the mean value theorem" and was just wondering, when i am doing rolles, do i really need to find the exact value of x where f'(c) = 0? for example: f(x) = (x+4)^2 (x-3) on [-4,3] i get to: 3x^2+10x-8=7 then i dont know if i then need to find ...
Tuesday, January 28, 2014 at 11:51pm

Calculus
Find the critical numbers of the function. h(t) = t3/4 − 5t1/4
Tuesday, January 28, 2014 at 10:25pm

Calculus
A poster is to have an area of 160 in2 with 1 inch margins at the bottom and sides and a 7 inch margin at the top. What dimensions will give the largest printed area? (Give your answers correct to one decimal place.)
Tuesday, January 28, 2014 at 10:25pm

Calculus
Find the absolute maximum and absolute minimum values of f on the given interval. f(x) = (x2 - 1)3 [-1, 6]
Tuesday, January 28, 2014 at 10:24pm

Calculus
Find the absolute minimum and absolute maximum values of f on the interval below. f(x) = x4 - 8x2 + 6 [-3, 4]
Tuesday, January 28, 2014 at 10:23pm

Calculus
smaller number --- x larger number ----- x + 132 product=P=x(x+132) = x^2 + 132x dP/dx = 2x + 132 =0 for a min of P 2x = -132 x = -66 the smaller is -66 the larger -66+132 or +66 the two numbers are -66 and +66
Tuesday, January 28, 2014 at 10:20pm

Calculus
let the sides of the base be x cm each let the height be y V= x^2 y 4000/x^2 = y surface area = x^2 + 4xy = x^2 + 4x(4000/x^2 = x^2 + 16000/x d(surface area)/dx = 2x - 16000/x^2 = 0 for a min surface area 2x = 16000/x^2 x^3 = 16000 x = appr 25.2 cm y = 4000/25.2^2 = appr 6.3 cm
Tuesday, January 28, 2014 at 10:17pm

Calculus
Find two numbers whose difference is 132 and whose product is a minimum.
Tuesday, January 28, 2014 at 10:04pm

Calculus
Still not very understand. Where u get the 1/6?
Tuesday, January 28, 2014 at 10:03pm

Calculus
A box with a square base and open top must have a volume of 4,000 cm3. Find the dimensions of the box that minimize the amount of material used.
Tuesday, January 28, 2014 at 10:03pm

Calculus
A poster is to have an area of 160 in2 with 1 inch margins at the bottom and sides and a 7 inch margin at the top. What dimensions will give the largest printed area? (Give your answers correct to one decimal place.)
Tuesday, January 28, 2014 at 10:02pm

pre-calculus
S = 0.9p - 1500
Tuesday, January 28, 2014 at 8:18pm

pre-calculus
The suggested retail price for a new car is p dollars. The dealership advertises a 10% discount and a factory rebate of $1500. Write a function S in terms of p, representing the cost of the car after receiving the dealership discount.
Tuesday, January 28, 2014 at 8:15pm

calculus
I assume that Sn = sum(1..n) An, so Sn -> 3 Dunno where the x comes from, but if you mean when n > 1, An = Sn - s(n-1) = (3n-2)/(n+1) - (3(n-1)-2)/(n-1+1) = 5 / n(n+1)
Tuesday, January 28, 2014 at 5:08am

calculus
If the nth partial sum of an is sn=(3n-2)/(n+1) what is an when x>1? and what is the sum of an?
Tuesday, January 28, 2014 at 1:06am

Calculus
write and row reduce the augmented matrix to find the general solution. x + y - z = 7 2x - y - 5z = 2 -5x + 4y + 14z = 1 3x - y - 7z = 5
Monday, January 27, 2014 at 6:51pm

Calculus HELP!!
The 6 2 1 is supposed to be on the right hand side of the equal sign. I am so sorry again!!!
Monday, January 27, 2014 at 5:38pm

Calculus HELP!!
just add them up: 2u-3v-w = 12-6-6 8-6-2 10-9-1 = 0 0 0
Monday, January 27, 2014 at 5:37pm

Calculus HELP!!
Then after this, use that fact to find x1 and x2 that satisfies the equation: 6 2 6 4 2 2 5 3 {x1 and x2} = 1
Monday, January 27, 2014 at 5:36pm

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