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April 18, 2014

Homework Help: Math: Calculus

Recent Homework Questions About Calculus

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Calculus Help
In the following x,y and (a) are all variables. Show steps please! Thank you! 1) y^2 = x^2+a^2 2) y^2+ay = x^2+ax+a^2
Thursday, March 13, 2014 at 8:19pm

Pre Calculus
rcosθ = 3 r = 3secθ
Thursday, March 13, 2014 at 5:04pm

Pre-Calculus
r = 5sinθ r^2 = 5r sinθ x^2+y^2 = 5y x^2 + (y - 5/2)^2 = 25/4
Thursday, March 13, 2014 at 5:03pm

CALCULUS ECONOMICS
Consider the problem of a competitive firm which has fixed costs of $1000, semi-fixed-costs of $1000, and variable costs given by q^2. QUESTION: What is the maximum market price at which the firm decides to supply zero?
Thursday, March 13, 2014 at 4:10pm

CALCULUS ECONOMICS
Consider the problem of a competitive firm which has fixed costs of $1000, semi-fixed-costs of $1000, and variable costs given by q2. QUESTION: What is the maximum market price at which the firm decides to supply zero?
Thursday, March 13, 2014 at 4:09pm

CALCULUS ECONOMICS
Consider a market in which consumption of the good being traded generates a positive externality. There are 100 identical consumers, each with a utility function given by (1/2)*(q^(1/2))+m +(G^(1/2)) where G denotes the total level of consumption in the market. The good is ...
Thursday, March 13, 2014 at 4:08pm

CALCULUS ECONOMICS
Consider a market in which consumption of the good being traded generates a positive externality. There are 100 identical consumers, each with a utility function given by (1/2)*(q^(1/2))+m +(G^(1/2)) where G denotes the total level of consumption in the market. The good is ...
Thursday, March 13, 2014 at 4:06pm

CALCULUS ECONOMICS
Consider an oligopolistic market with two firms. Each of them produces using a cost function given by c(q)=q^2. The aggregate demand in the market is given by 1000−p. Suppose that, in order to increase production, the government gives the firms a $100 per-unit produced ...
Thursday, March 13, 2014 at 3:58pm

CALCULUS ECONOMICS
Consider the same setting as in the previous question. Suppose that firms are NOT owned by consumers. Let s denote the size of the per-unit subsidy/tax given to the firms. Let positive values of s denote subsidies, and negative values of s denote taxes. QUESTION: What is the ...
Thursday, March 13, 2014 at 3:54pm

CALCULUS ECONOMICS
Consider an oligopolistic market with two firms. Each of them produces using a cost function given by c(q)=q^2. The aggregate demand in the market is given by 1000−p. Suppose that, in order to increase production, the government gives the firms a $100 per-unit produced ...
Thursday, March 13, 2014 at 3:53pm

CALCULUS ECONOMICS
Consider an economy in which a monopolistic firm serves two identical, but separate markets, called A and B. The aggregate inverse demand in each market is given by 1000−q. The cost function for the monopolist is given by (qA+qB)^2, where qA andqB denotes the amount sold...
Thursday, March 13, 2014 at 3:52pm

CALCULUS ECONOMICS
Consider a market in which aggregate demand is given by 1000−10p, and aggregate supply is given by 10p, where p denotes the market price. QUESTION: What is the maximum amount of revenue that the government can raise using a per-unit sales tax on consumers?
Thursday, March 13, 2014 at 3:50pm

CALCULUS ECONOMICS
Consider the problem of a rational consumer with an experienced utility function given by 8*x^(1/2)+m. Let p=$1 p/unit denote the market price of good x. Suppose that, initially, the firm selling the good matches his purchases as follows: for every x units that he buys, he ...
Thursday, March 13, 2014 at 3:49pm

CALCULUS ECONOMICS
Consider the problem of a rational consumer with an experienced utility function given by 8x√+m. Let p=$1 p/unit denote the market price of good x. Suppose that, initially, the firm selling the good matches his purchases as follows: for every x units that he buys, he ...
Thursday, March 13, 2014 at 3:47pm

Pre-Calculus
r = sqrt (4^2+3^2) which we know is 5 because of 3 4 5 right triangle so we do not need c^2=a^2+b^2 -4 = 5 cos theta cos theta = -4/5 theta = 143 if you use your calculator but that would be wrong because we are in QUADRANT 3 where sin and cos BOTH negative cos^-1 4/5 = 36.9 ...
Thursday, March 13, 2014 at 3:38pm

Pre Calculus
r = 3, theta = 0
Thursday, March 13, 2014 at 3:29pm

Pre-Calculus
Write the polar equation in rectangular form... r=5sintheta
Thursday, March 13, 2014 at 3:28pm

Pre-Calculus
Find the polar coordinates of each point with the given rectangular coordinates. Use degrees. (-4,-3)
Thursday, March 13, 2014 at 3:25pm

Pre-Calculus
r cos theta = x = -2.598 = - 3(sqrt3/2) r sin theta = y = +1.5 (-2.6 , 1.5 ) or exact: (-3 sqrt 3 /2 , 3/2 )
Thursday, March 13, 2014 at 3:23pm

Pre Calculus
Write the rectangular equation in polar form... x=3
Thursday, March 13, 2014 at 3:17pm

Pre-Calculus
Find the rectangular coordinates of the point with the given polar coordinates. (3, 150°)
Thursday, March 13, 2014 at 3:15pm

Calculus
well, x^2/(2logx) = x^2/log(x^2), so if you can figure out the limit of x/logx, you're ok. Since x->0 and logx->-∞, x/logx -> 0/-∞ = 0 -------------- e^-x -> 0 as x->∞, so the upper limit -> 0 e^0 = 1, so the lower limit -> 2
Thursday, March 13, 2014 at 12:45pm

Calculus
Following 2 questions are from a book at a point where L’Hopital’s Rule, Squeeze Theorem etc. have not been discussed and limits (A) and (B) as given below are to be evaluated by simple methods like algebraic simplification etc. 1. Int. of (xlogx)dx from 0 to 1. ...
Thursday, March 13, 2014 at 2:45am

calculus
nn
Wednesday, March 12, 2014 at 6:15pm

CALCULUS HELP
If we let u = 8x-3 v = 6x+7 then we can make the expression a little easier to read during the computational steps: f' = (5u^4*8*v^12-u^5*12v^11*6)/v^24 Now, you can cancel out v^11 top and bottom to get f' = (40u^4*v - 72u^5)/v^13 Now factor out 4u^4 to get f' = ...
Wednesday, March 12, 2014 at 5:37pm

AP Calculus AB
5
Wednesday, March 12, 2014 at 3:48pm

CALCULUS HELP
Find the derivative of the following function showing your work and fully simplifying your answer. STEP BY STEP PLEASE!!! f(x)=(8x-3)^5/(6x+7)^12 THANK YOU SO MUCH!!!
Wednesday, March 12, 2014 at 2:34pm

Calculus
Following 2 questions are from a book at a point where L’Hopital’s Rule, Squeeze Theorem etc. have not been discussed and limits (A) and (B) as given below are to be evaluated by simple methods like algebraic simplification etc. 1. Int. of (xlogx)dx from 0 to 1. ...
Wednesday, March 12, 2014 at 6:13am

Calculus
limit as x->2- = 5 limit as x->2+ = 5 since one-sided limits are the same, and f(2)=5, f is continuous Do you have to do the delta-epsilon limit proof?
Wednesday, March 12, 2014 at 5:29am

Calculus
Show, using limits, that f(x) = x2 – x + 3, is continuous at x = 2.
Wednesday, March 12, 2014 at 2:15am

Calculus
product rule and chain rule -- if y = uv y' = u'v + uv' Here u=csc^2 x and v = arccos(1-x^2) y' = -2 cscx cscx cotx arccos(1-x^2) + csc^2 x 1/√(1-(1-x^2)^2) * -2x kind of messy, no? well, recall that if cos u = 1-x^2, sin u = x, so we really have y = -csc...
Wednesday, March 12, 2014 at 12:12am

Calculus- typo
64/6 + 8 + 20 - ( -64/6 + 8 -20 ) 64/3 + 0 + 40 184/3
Wednesday, March 12, 2014 at 12:06am

Calculus
what you have tried is the volume when rotating the region about the x-axis. But, of course, the volume of a disk is pi r^2 dx, not pi r^3 dx In addition, your radius is 3-x, not y, since you are rotating about the line x=3, not y=0. So, if you want to use discs, you need to ...
Wednesday, March 12, 2014 at 12:01am

Calculus
At time t, using the law of cosines, d^2 = (7t)^2 + (5t)^2 - 2(5t)(7t)cosπ/4 = 74t^2 - 35√2 t^2 = (74-35√2)t^2 so, 2d dd/dt = 2(74-35√2)t Now, plug in your numbers to get d(15), and solve for dd/dt at t=15 Remember to use appropriate units
Tuesday, March 11, 2014 at 11:47pm

Calculus
as usual, draw a diagram and you will see that if θ=0 when x=0, tanθ = x/4 so, sec^2θ dθ/dt = 1/4 dx/dt Now, you have θ and dθ/dt, so just solve for dx/dt
Tuesday, March 11, 2014 at 11:43pm

Calculus
A lighthouse is located on a small island 4 km away from the nearest point P on a straight shoreline and its light makes three revolutions per minute. How fast is the beam of light moving along the shoreline when it is 1 km from P? (Round your answer to one decimal place.)
Tuesday, March 11, 2014 at 10:12pm

Calculus
Two people start from the same point. One walks east at 5 mi/h and the other walks northeast at 7 mi/h. How fast is the distance between the people changing after 15 minutes? (Round your answer to three decimal places.)
Tuesday, March 11, 2014 at 10:11pm

Calculus Check my answer
integral (x^2/2 + x + 5)dx x^3 /6 + x^2/2 + 5 x at 4 minus at -4 64/6 + 8 + 20 - ( -64/6 + 8 -20 ) 64/3 + 20 + 40 64/3 + 180/3 = 244/3 = 81 1/3
Tuesday, March 11, 2014 at 10:00pm

Calculus
Can you tell me if im doing this right? Find the volume of the region obtained by revolving the area below about the line x=3. y=x3, x=2, y=0 v=pi[2,0] (x^3)^3dx= pi[2,0] x^9 v=pi/10 x^10(2,0)= 1024/10 pi
Tuesday, March 11, 2014 at 9:46pm

Calculus Check my answer
Find the area between the curves y= x^2/2 +2 and y = –x – 3 on the interval –4 ≤ x ≤ 4. I got 40/3 is that correct?
Tuesday, March 11, 2014 at 9:43pm

Calculus
Can someone help me with finding the derivative of this function? y = -( csc x)2 (cos-1(1-x2))
Tuesday, March 11, 2014 at 9:42pm

Calculus Help
just use the quotient rule and chain rule. If f = u/v f' = (u'v-uv')/v^2 f' = 5(8x-3)^4(8)(6x+7)^12 - (8x-3)^5(12)(6x+7)^11(6)]/(6x+7)^24 = -16(8x-3)^4(21x-31)/(6x+7)^13
Tuesday, March 11, 2014 at 4:30pm

Calculus Help
Find the derivative of the following function showing your work and fully simplifying your answer. f(x)=(8x-3)^5/(6x+7)^12 Thank you!!!
Tuesday, March 11, 2014 at 3:36pm

FREE BODY DIAGRAM calculus
12
Tuesday, March 11, 2014 at 12:46pm

calculus
The circle in the x-y plane is x^2 + (y - a/2)^2 = a^2/4 x^2 = a^2/4 - (4y^2-4ay+a^2)/4 = (y^2-ay)/4 The limits of integration in the x-y plane are 0 < y < a 0 < x < (1/2)√(y^2-ay) then use symmetry and multiply by 4
Tuesday, March 11, 2014 at 12:06am

calculus
Find the surface area of the part of the sphere x^2+y^2+z^2=a^2 inside the circular cylinder x^2+y^2=ay (r=a*sin(θ) in polar coordinates), with a>0. First time posting on this website, sorry for the lack of details on my attempts but I am really not sure where to start...
Monday, March 10, 2014 at 10:22pm

Calculus
the answers are the same √[(x-3)/2] = √[(x-3)/2 * 2/2] = √(2x-6)/2
Monday, March 10, 2014 at 8:16pm

Calculus
I think you did it correctly. Of course the domain is limited because the answer is imaginary if x <3
Monday, March 10, 2014 at 6:39pm

Calculus
Determine the equation of the inverse function if f(x) = 2x^2+3, and x≥0. The answer is supposed to be f^-1(x)=[√(2x-6)]/2. This is what I did: x=2y^2+3 2y^2=x-3 y^2=(x-3)/2 y=√[(x-3)/2] Did I do something wrong? Thanks!
Monday, March 10, 2014 at 5:37pm

Calculus
If f(x)= -4x^2+7 and x≤0, what is the equation of the inverse function? The answer is supposed to be f^-1(x)= -[√(7-x)]/2, but this is what I did: x=-4y^2+7 -4y^2=x-7 y^2=(x-7)/-4 y= √[(x-7)/-4] Did I do something wrong? By the way, for the original function...
Monday, March 10, 2014 at 2:12pm

Calculus Help
3/31: t=90 4/21: t=111 L'(t) = 2.8cos[(2π/365)(t − 80)](2π/365) now just plug in t=90 and t=111 The answer, of course, will be in hr/day.
Monday, March 10, 2014 at 5:11am

Calculus
Since the derivative is the slope of the tangent line, we need -2sinx - 2cosx*sinx = 0 -2sinx(1+cosx) = 0 sinx = 0 means x = nπ cosx = -1 means x = (2n+1)π so, f(x) has a horizontal tangent at x=nπ
Monday, March 10, 2014 at 5:03am

Calculus
Find all points on the graph of the function f(x) = 2 cos x + cos^2 x at which the tangent line is horizontal. (Use n as your arbitrary integer.) smaller y-value (x,y)= larger y-value (x,y)=
Sunday, March 9, 2014 at 10:40pm

Calculus Help
A model for the length of daylight (in hours) in Philadelphia on the tth day of the year is L(t) = 12 + 2.8 sin[(2π/365)(t − 80)]. Use this model to compare how the number of hours of daylight is increasing in Philadelphia on March 21 and April 21. (Assume there are...
Sunday, March 9, 2014 at 9:56pm

calculus
r' = 2.4/(3t+6) r = 0.8 log(3t+6)+c solve for c at t=0 in 0.8 log6 + c = 3.8 now just plug in t=16 for the final answer.
Saturday, March 8, 2014 at 10:02pm

calculus
r' = 2.1/(t+5) r = 2.1 log(t+5) + C at t=0, 3.8 = 2.1 log5 + C C = 3.8-2.1log5 = 0.42 so, r = 2.1 log(t+5)+0.42 now just plug in t=27
Saturday, March 8, 2014 at 9:59pm

calculus
a = 2t-4, not 2t^2-4
Saturday, March 8, 2014 at 9:55pm

Calculus
It requires 8 inch pounds of work to stretch a certain spring 2 inches from its rest position. Assuming that the spring follows hooke's law, what is k? Please answer this question. Thanks for your answers in advance.
Saturday, March 8, 2014 at 8:13pm

calculus
A. Integrate the velocity x = (t^3)/3-2t+3t substitute 4 and 6 [(4^3)/3 - 2(4)+3(4)] - [(6^3)/3 - 2(6)+3(6)] = m? B. get the derivatives of velocity a = 2t^2 - 4 substitute t=6 2(6)^2-4 = m/s^2?
Saturday, March 8, 2014 at 8:00pm

Integral calculus
It requires 8 inch pounds of work to stretch a certain spring 2 inches from its rest position. Assuming that the spring follows hooke's law, what is k? Thanks for your answers! :)
Saturday, March 8, 2014 at 7:36pm

calculus
a=2.675543 b=7.23334
Saturday, March 8, 2014 at 6:04pm

calculus
The velocity of a skateboard is v(t) = t^2 - 4 t + 3 m/s when moving in a straight line. A. Find the the change in displacement of the skateboard between 4 seconds and 6 seconds. (Note this may or may not be negative, meaning it goes in the opposite direction, if so then be ...
Saturday, March 8, 2014 at 6:03pm

calculus
\int_{4}^{13} f(x) \,dx - \int_{4}^{11} f(x) \,dx = \int_{a}^{b} f(x) \,dx where a= and b= .
Saturday, March 8, 2014 at 6:02pm

calculus
pretty easy upper limit of b is 25.15 lower limit of a is 16.23
Saturday, March 8, 2014 at 6:01pm

calculus
A long narrow piece of land gets flooded each year by a river. The flooded area is in the shape of the area under the curve y = 2.3 x^3 and above the x-axis, for 0 \le x \le 3.2. All the distances are in metres.
Saturday, March 8, 2014 at 6:01pm

calculus
a. The value of \displaystyle \int_{-2}^{-1} \frac{14}{ 4 x } dx is b. The value of \displaystyle \int_{1}^{2} \frac{14}{ 4 x } dx is
Saturday, March 8, 2014 at 6:01pm

calculus
The following definite integral can be evaluated by subtracting F(B) - F(A), where F(B) and F(A) are found from substituting the limits of integration. \int_{0}^{4} \frac{1600 x +1200 }{(2 x^2 +3 x +1)^5}dx After substitution, the upper limit of integration (B) is : and the ...
Saturday, March 8, 2014 at 6:00pm

calculus
At a summer campfire, the radius of a marshmallow on a stick expands at the rate of \ {r ' (t)} = \frac{2.4 }{3 t + 6} mm/s where t is the time of heating in seconds. Initially the radius was 3.8 mm. Find the radius after 16 seconds using the following steps: When ...
Saturday, March 8, 2014 at 6:00pm

calculus
Ice cream drips out of the bottom of an ice cream cone on a hot day at a rate of r(t) mL per second, as a child eats it slowly, where t is in seconds. If r(t) = 10 e^{-k t}, complete the definite integral expressing the quantity of ice cream lost in the first 3 minutes(s). (...
Saturday, March 8, 2014 at 5:59pm

calculus
At a summer campfire, the radius of a marshmallow on a stick expands at the rate of \ {r ' (t)} = \frac{2.1 }{1 t + 5} mm/s where t is the time of heating in seconds. Initially the radius was 3.8 mm. Find the radius after 27 seconds using the following steps: When ...
Saturday, March 8, 2014 at 5:59pm

calculus
Find the area of the region under the curve y = 16 e ^{4 x} between x = -1.4 to x =1.4 .
Saturday, March 8, 2014 at 5:58pm

Calculus
what's the trouble? Straightforward integration: a = ∫[-2.6,2.6] 12e^(3x) dx = 4e^3x [2.6,-2.6] = 9762.41
Saturday, March 8, 2014 at 5:47pm

typo, gravity wrong
a) Hey, you know what h is when t = zero! b ) h = -4(1) + 16(1) + 9 = 21 c) If you do not know any calculus, which I assume you do not or you would not be asking, then you must complete the square to find the vertex of the parabola t^2 - 4 t = -h/4 + 9/4 t^2 - 4 t + 4 = -h/4...
Saturday, March 8, 2014 at 1:54pm

Calculus
what's your name. i think i'm in your class. I'm having the same problem. Hopital isn't the way to solve this problem though.
Friday, March 7, 2014 at 8:54pm

calculus
3 * 2 pi = 6 pi radians/minute pi/6 = 30 degrees by the way I call your angle theta A dA/dt = 6 pi rad/min tan A = x/7 x = 7 tan A dx/ dt = 7 d/dt(tan A ) = (7/cos^2A) dA/dt cos^2 (30) = .75 so dx/dt = (7 miles/.75)(6 pi rad/min) dx/dt = 176 miles/min * 60 = 1055 miles/hr so ...
Friday, March 7, 2014 at 7:26pm

calculus
by the way, d/dt (tan A) = sec^2 A * dA/dt = (1/cos A)^2 * dA/dt
Friday, March 7, 2014 at 7:14pm

calculus
A searchlight rotates at a rate of 3 revolutions per minute. The beam hits a wall located 7 miles away and produces a dot of light that moves horizontally along the wall. How fast (in miles per hour) is this dot moving when the angle \theta between the beam and the line ...
Friday, March 7, 2014 at 7:13pm

calculus
Hey, I just did one very much like this. Your turn.
Friday, March 7, 2014 at 7:03pm

calculus
A hot air balloon rising vertically is tracked by an observer located 4 miles from the lift-off point. At a certain moment, the angle between the observer's line-of-sight and the horizontal is \frac{\pi}{3} , and it is changing at a rate of 0.1 rad/min. How fast is the ...
Friday, March 7, 2014 at 7:00pm

calculus
Oh, it is pointed at the bottom? area = pi r^2 radius = (1/3) h for 1 at the top and 0 at the bottom so surface area A = pi (1/9)h^2 for h = 2.6, A = 2.36 meters^2 d V = A dh dV/dt = A dh/dt or dh/dt = (1/A)dV/dt dV/dt given as 1.4 m^3/min so dh/dt = 1.4/2.36 = .593 m/min
Friday, March 7, 2014 at 7:00pm

Calculus
y = 1 e^(rx) y' = r e^(rx) y" = r^2 e^(rx) r^2 - 4 r + 1 = 0 r = [4 +/- sqrt (16 -4) ] /2 r = [ 4 +/- 2 sqrt 3 ]2 r = 2 +/- sqrt 3
Friday, March 7, 2014 at 6:49pm

Calculus
for what values of r does the function y=e^rx satisfy the differential equation y''-4y'+y=0 Show steps please! Thank you!
Friday, March 7, 2014 at 6:43pm

calculus
A man of height 1.5 meters walk away from a 5-meter lamppost at a speed of 1.8 m/s. Find the rate at which his shadow is increasing in length.
Friday, March 7, 2014 at 6:30pm

calculus
A conical tank has height 3 m and radius 2 m at the top. Water flows in at a rate of 1.4 \text{m}^3\text{/min}. How fast is the water level rising when it is 2.6 m?
Friday, March 7, 2014 at 5:53pm

Calculus Help Please!!!
y' = 8x-6x^2 so, at x=a, y' = 8a-6a^2 = m Use the above info to plug into the point-slope form of the lines. No sweat.
Friday, March 7, 2014 at 4:44pm

Calculus Help Please!!!
--- Find the slope m of the tangent to the curve y = 4 + 4x^2 − 2x^3 at the point where x = a. ---- Find equations of the tangent lines at the points (1,6) and (2,4). (1,6) Y(x)= (2,4) Y(x)=
Friday, March 7, 2014 at 4:40pm

Calculus Help Please!!!
(c) (15005-10237)/2 = 2384 (d) (16684-12435)/2 = 2124.5 (e) Looks like growth is slowing down
Friday, March 7, 2014 at 4:22pm

Calculus Help Please!!!
c) Estimate the instantaneous rate of growth in 2006 by measuring the slope of the tangent line through (2005, 10237) and (2007, 15005). d) Estimate the instantaneous rate of growth in 2007 by measuring the slope of the tangent line through (2006, 12435) and (2008, 16684). e)...
Friday, March 7, 2014 at 4:07pm

Calculus Help
dy/dx = 2ax + bx when x = 1, 2a + b = 6 when x = -1 -2a +b = -14 add them 2b = -8 b= -4, then a = 5 to find c, sub in (2,17) into the original: 17 = 4a + 2b + c 17 = 20 -8 + c c = 5 y = 5x^2 - 4x + 5 check: for (2,17) 17 = 20 - 8 + 5 ---> true dy/dx = 10x - 4 at x = 1, dy/...
Friday, March 7, 2014 at 3:33pm

Calculus Help
Find a parabola with equation y = ax^2 + bx + c that has slope 6 at x = 1, slope −14 at x = −1, and passes through the point (2, 17).
Friday, March 7, 2014 at 2:56pm

Criminal justice
1. Which of the following, according to Carl Klockars, is NOT an important consideration in determining whether the good ends of police work justify immoral means in a given scenario? A. Are there other, non-dirty, means that may be effective but that we may be overlooking? B...
Friday, March 7, 2014 at 2:21pm

Calculus Please help!
f(-3) = 54 + 18 + 9 + 2 = 83 f(-1) = -2 + 2 + 3 + 2 = 5 slope = (5-83)/(-1+3) = -39 f ' (x) = -6x^2 + 4x - 3 then -6x^2 + 4x - 3 = -39 6x^2 - 4x -36 = 0 3x^2 - 2x - 18 = 0 x = (2 ± √220)/6 = appr 2.8054 or appr -2.1388
Friday, March 7, 2014 at 8:20am

Calculus...URGENT..show steps please
The "solving" becomes a bit easier if you change the original equation to (x-y)^2 - 6x + 2y + 17 = 0 sub in : y = x - 3 (x - (x-3))^2 - 6x + 2(x-3) + 17 = 0 9 - 6x + 2x - 6 + 17 = 0 -4x = -20 x = 5 then y = 2 the horizontal asymptote touches at (5,2) I will do the ...
Friday, March 7, 2014 at 8:03am

Calculus...URGENT..show steps please
2xdx-2y dx-2xdy + 2y dy -6dx+2dy=0 for horizontal lines, dy/dx=0 2x-2y-6)/(-2x+2y+2)=0 or y=x-3 for vertical tangent, dy/dx=undifined or -2x+2y+2=0 y=x-2 now solve the points on the parabola. for horizontal lines, substutute x-2 for y in the given equation, solve. Then, do the...
Friday, March 7, 2014 at 6:02am

Calculus Please help!
average slope=(f(5)-f(2))/(5-2) set average slope above to equal f=-2/sqrt(x) then solve for x.
Friday, March 7, 2014 at 5:56am

Calculus Please help!
Consider the function f(x)=4sqrt(x)+4 on the interval [2,5] . Find the average or mean slope of the function on this interval _______ <---A By the Mean Value Theorem, we know there exists a c in the open interval (2,5) such that f'(c) is equal to this mean slope. For ...
Friday, March 7, 2014 at 3:25am

Calculus Please help!
f(x) -2x^3+2x^2-3x+2 Find the average slope of this function on the interval (–3–1) ________ <--A By the Mean Value Theorem, we know there exists a c in the open interval (–3–1) such that f'(c) is equal to this mean slope. Find the value of c in the ...
Friday, March 7, 2014 at 3:23am

calculus
A certain radioactive isotope decays at a rate of 2% per 100 years. If t represents time in years and y represents the amount of the isotope left then the equation for the situation is y= y0e-0.0002t. In how many years will there be 93% of the isotope left?
Friday, March 7, 2014 at 3:08am

calculus
$4000 is invested at 9% compounded quarterly. In how many years will the account have grown to $14,500? Round your answer to the nearest tenth of a year
Friday, March 7, 2014 at 2:53am

Calculus Please help!
$4000 is invested at 9% compounded quarterly. In how many years will the account have grown to $14,500? Round your answer to the nearest tenth of a year
Friday, March 7, 2014 at 2:52am

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