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April 21, 2014

Homework Help: Math: Calculus

Recent Homework Questions About Calculus

Post a New Question | Current Questions

Calculus Help Please!!!
Find the absolute maximum and absolute minimum values of f on the given interval. f(x) = xe^((−x^2)/98), [−6, 14]
Tuesday, April 1, 2014 at 9:14pm

Calculus Help Please!!!
Find the absolute maximum and absolute minimum values of f on the given interval. f(t) = (t square root of (64 − t^2)) ,[−1,8]
Tuesday, April 1, 2014 at 9:11pm

Calculus Help!
Find the absolute maximum and absolute minimum values of f on the given interval. f(x) = xe^(−x^(2)/98), [−6, 14]
Tuesday, April 1, 2014 at 9:09pm

calculus
5x^2
Tuesday, April 1, 2014 at 8:19pm

Calculus Help Please!!!
looks like we both messed up in the f(x) calculations should be f(4) = 2(64) - 3(16) - 72(4) + 7 = -201 f(-3) = 2(-27) - 3(9) - 72(-3)+7 = 142 end-values: f(-4) = 2(-64) - 3(16)( - 72(-4) + 7 = 119 f(5) = 2(125) - 3(25) - 72(5) + 7 = -178
Tuesday, April 1, 2014 at 6:34pm

Calculus
f ' (t) = -8sin t + 2(4 cos t) = -8sint + 8cost = 0 for a max/min 8sint = 8cost sint/cost = 1 tant = 1 t = 45° or 225° or t = π/4 , t = 5π/4 -->(outside our domain) so evaluate f(0) f(π/4) f(π/2) and determine which is the largest and which ...
Tuesday, April 1, 2014 at 6:24pm

Calculus Help Please!!!
so it the same way you were just given in your previous post. Let us know what you got
Tuesday, April 1, 2014 at 6:07pm

Calculus Help Please!!!
f ' (x) = 6x^2 - 6x - 72 = 0 for a local max/min x^2 - x - 12 = 0 (x-4)(x+3) = 0 x = 4, or x = -3 f(4) = 2(64) - 3(16) - 72(4) + 7 = -201 f(-3) = 2(-27) - 3(9) - 72(-3)+7 = 115 end-values: f(-4) = 2(-64) - 2(16)( - 72(-4) + 7 = 135 f(5) = 2(125) - 3(25) - 72(5) + 7 = -178 ...
Tuesday, April 1, 2014 at 6:04pm

Calculus Help Please!!!
f'(x) = 6x^2 -6x -72 f'(0) = 6(x^2 -x-12) 0 = 6(x+ 3) (x-4) x = -3, 4 f(-4) = 2(-4)^3 -3(-4)^2 -72(-4) +7= 139 f(-3) = 2(-3)^3 -3(-3)^2 -72(-3) +7=132 f(4) = 2(4)^3 -3(4)^2 -72(4) + 7= -145 f(5) = 2(5)^3 -3(5)^2 -72(5)+7= -178
Tuesday, April 1, 2014 at 6:01pm

Calculus
Find the absolute minimum and absolute maximum values of f on the given interval. f(t) = 8 cos t + 4 sin 2t, [0, π/2]
Tuesday, April 1, 2014 at 5:45pm

Calculus Help Please!!!
Find the absolute maximum and absolute minimum values of f on the given interval. f(t) = (t square root of (64 − t^2)), [−1, 8]
Tuesday, April 1, 2014 at 5:27pm

Calculus Help Please!!!
Find the absolute maximum and absolute minimum values of f on the given interval. f(x) = 2x^3 − 3x^2 − 72x + 7 , [−4, 5]
Tuesday, April 1, 2014 at 5:26pm

calculus and vectors
Add the 2 equations ... 6x + y = 6 y = 6-6x let x = 0 , y = 6 2(0) + 4(6) + z = 5 --> z = -19) we have a point (0,6,-19) on the line of intersection let x = 1, y = 0 2(1) + 4(0) + z = 5 --> z = 3 and (1,0,3) is another point on that line So a direction vector of that ...
Tuesday, April 1, 2014 at 5:18pm

calculus and vectors
Determine an equation of the line of intersection of the planes 4x − 3y − z = 1 and 2x + 4y + z = 5.
Tuesday, April 1, 2014 at 4:59pm

calculus
max area for a given perimeter is a circle. Is the wire evenly divided? If so, c = p/2, so r = p/4π, and the total area is a = 2(πr^2) = 2π(p^2/16π^2) = p^2/8π If not, then if we have a tiny circle, (area effectively zero), then r = p/2π and a...
Tuesday, April 1, 2014 at 12:30pm

calculus
Twenty feet wire is used to make two figures? What is the maximum areas of enclosed figures.
Tuesday, April 1, 2014 at 11:14am

Calculus
Thanks Mr. Steve for the guidance.
Tuesday, April 1, 2014 at 5:21am

Calculus
Looks good to me. I get ∫[1,2] (3-x) - 2/x dx = 3x - 1/2 x^2 - 2logx [1,2] = 3/2 - 2log2 gotta be a typo in the answer. 2log2 is correct.
Tuesday, April 1, 2014 at 4:52am

Calculus
Find the area cut off by x+y=3 from xy=2. I have proceeded as under: y=x/2. Substituting this value we get x+x/2=3 Or x+x/2-3=0 Or x^2-3x+2=0 Or (x-1)(x-2)=0, hence x=1 and x=2 are the points of intersection of the curve xy=2 and the line x+y=3. Area under curve above X axis ...
Tuesday, April 1, 2014 at 3:07am

Calculus
Good idea. However, in an attempt to use your math, and also to apply to a possibly more general problem later, try implicit differentiation: x^2 + y^2 = 18 2x + 2yy' = 0 y' = -x/y So, if -x/y = 1 and x^2+y^2 = 18, 2x^2 = 18 x = ±3 Now, figuring y should not be ...
Monday, March 31, 2014 at 1:02pm

Calculus
LOL, sketch a graph !
Monday, March 31, 2014 at 11:46am

Calculus
The circle defined by the equation x^2 + y^2 = 18 has two points where the slope of its tangent line is m=1. Find those points.
Monday, March 31, 2014 at 11:41am

Calculus: Integral
recall that sec^2 = 1+tan^2, so you have ∫sec^4(4x) dx = ∫sec^2(4x)(1 + tan^2(4x)) dx = ∫sec^2(4x) dx + ∫tan^2(4x) sec^2(4x) dx = 1/4 tan(4x) + (1/4)(1/3) tan^3(4x) and you can massage that in several ways.
Monday, March 31, 2014 at 5:32am

Calculus: Integral
I don't understand how to do this one integral problem that involves secant. I'm asked to find the integral of sec^4 (4x). I'm not really sure how to go about solving this problem.
Monday, March 31, 2014 at 3:32am

Calculus Help Please!!!
looking at a diagram, if A is a away from Q and B is b away from Q, then √(a^2+144) + √(b^2+144) = 39 a/√(a^2+144) da/dt + b/√(b^2+144) db/dt = 0 Now just plug in da/dt = 3.5 a = 5 b = 23.065 (from 1st equation when a=5) and solve for db/dt
Monday, March 31, 2014 at 12:27am

Calculus Help
v = 2/3 pi r^3 (half a sphere) dv = 2 pi r^2 dr now just plug in the given r and dr watch the units.
Monday, March 31, 2014 at 12:07am

Calculus Help Please!!!
v = 4/3 pi r^3 dv = 4 pi r^2 dr c = 2pi r dc = 2pi dr so, dr = dc/(2pi) meaning that dv = 4 pi r^2 dc/(2pi) = 2 r^2 dr so, using the given numbers, dv = 2*(80/2pi)^2 * 0.5 = 1600/pi^2
Monday, March 31, 2014 at 12:05am

Calculus Help Please!!!
looks good to me
Monday, March 31, 2014 at 12:01am

pre calculus
24
Sunday, March 30, 2014 at 11:40pm

Calculus Help Please!!!
Verify the given linear approximation at a = 0. Then determine the values of x for which the linear approximation is accurate to within 0.1. (Enter your answer using interval notation. Round your answers to three decimal places.) fourth root of (1 + 2x)≈ 1 + (1/2)x
Sunday, March 30, 2014 at 11:21pm

Calculus Help Please!!!
The circumference of a sphere was measured to be 80 cm with a possible error of 0.5 cm. 1) Use differentials to estimate the maximum error in the calculated volume. (Round your answer to the nearest integer.) 2) What is the relative error? (Round your answer to three decimal ...
Sunday, March 30, 2014 at 11:17pm

Calculus Help
Use differentials to estimate the amount of paint needed to apply a coat of paint 0.03 cm thick to a hemispherical dome with diameter 54 m. (Round your answer to two decimal places.)
Sunday, March 30, 2014 at 11:16pm

Calculus Help Please
f(x) = f(a) + (x-a) f'(a) f(x) = x^4 df/dx = 4x^3 let a = 2 then f(a) = 2^4 = 16 f'(a) = 4*8 = 32 f(x) = 16 + (x-a)(32) x-a = - .001 so f(1.999) = 16 -.001(32) = 16 - .032 f(1.999) = 15.968 with calculator it is 15.968 also
Sunday, March 30, 2014 at 10:29pm

Calculus Help Please!!!
at x = 3 y = 3*3 - 9 = 0 at x = 2.4 y = 3(2.4) - 2.4^2 = 1.44 delta y = 1.44 -0 = 1.44 dy/dx = 3 - 2 x at x = 3 dy/dx = 3 - 6 = -3 if dx = -.6 dy = -3 (-.6) = 1.8
Sunday, March 30, 2014 at 10:21pm

Calculus
Thanks Damon, that really clears it up for me
Sunday, March 30, 2014 at 10:17pm

Calculus Help Please
Use a linear approximation (or differentials) to estimate the given number. (1.999)^4
Sunday, March 30, 2014 at 10:14pm

Calculus Help Please!!!
Oh, I see f(x) = ln (1+x) df/dx = 1/(1+x) d^2f/dx^2 = -1/(1+x)^2 f(x) = f(0) + [1/(1+0)] x - x^2/2! ... f(x) = 0 + x - x^2/2 + ..... well at a first cut when is x^2/2 =.1 x? x/2 = .1 x = .2
Sunday, March 30, 2014 at 10:13pm

Calculus Help Please!!!
Compute Δy and dy for the given values of x and dx = Δx. (Round your answers to three decimal places.) y = 3x − x^2, x = 3, Δx = −0.6 Δy=???
Sunday, March 30, 2014 at 9:57pm

Calculus Help Please!!!
Verify the given linear approximation at a = 0. Then determine the values of x for which the linear approximation is accurate to within 0.1. (Enter your answer using interval notation. Round your answers to three decimal places.) ln(1 + x) ≈ x xE
Sunday, March 30, 2014 at 8:28pm

Calculus Help Please!!!
Two carts, A and B, are connected by a rope 39 ft long that passes over a pulley P (see the figure). The point Q is on the floor h = 12 ft directly beneath P and between the carts. Cart A is being pulled away from Q at a speed of 3.5 ft/s. How fast is cart B moving toward Q at...
Sunday, March 30, 2014 at 7:16pm

Calculus Help Please!!!
LOL - Guess which of us is the mathematician and which is the Engineer :)
Sunday, March 30, 2014 at 7:15pm

Calculus Help Please!!!
when the water has depth x, the cross-section is a trapezoid with bases 30 and 30+x. So the volume of water at depth x is v = (60+x)/2 * x * 500 cm^3 = 250x^2 + 15000x so, knowing that dv/dt = (500x + 15000) dx/dt just solve that for dx/dt when x=20
Sunday, March 30, 2014 at 7:12pm

Calculus Help Please!!!
Q = incoming flow rate = .1 m^3/min dh/ dt = Q A where A = surface area = length * width at 20 cm depth which depth is (1/2) height width = 30 + 1/2(70-30) = 30+20 = 50 cm = .5 m wide water surface so A = 5 * .50 =2.5 m^3 so finally dh/dt = .1 * 2.5 = .25 m/min = 25 cm/min
Sunday, March 30, 2014 at 7:11pm

Calculus Help Please!!!
A water trough is 5 m long and has a cross-section in the shape of an isosceles trapezoid that is 30 cm wide at the bottom, 70 cm wide at the top, and has height 40 cm. If the trough is being filled with water at the rate of 0.1 m3/min how fast is the water level rising when ...
Sunday, March 30, 2014 at 6:43pm

physics
find the difference in PE in the two locations. Hold one charge stationary. PEtotal= kQQ/.1 PE(new total)=KQQ/.06 subtract the first from the second, that must equal the work done. There are more difficult ways to work this, involving finding work in an integral calculus ...
Sunday, March 30, 2014 at 10:11am

Calculus
when dy/du = u^½ what does y = ? Just a simple power rule substitution. dy/du = u^n y = u^(n+1) / (n+1) + C
Saturday, March 29, 2014 at 4:38pm

Calculus
Thanks Steve! Finally got this one correct on Math Lab! I am eternally grateful, and have made an account here so I can get help and I have already tried helping others as well. I am very pleased with the service of this site and am glad to have found it :) Hooray!!!
Saturday, March 29, 2014 at 4:34pm

Calculus
When dy/dx=(x-6)^½ what does y equal?
Saturday, March 29, 2014 at 4:11pm

Calculus
the rate of change of volume is the surface area times the rate of change of height 450 ft^3/min = surface area * dh/dt surface area = pi r^2 450 = pi (30^2) dh/dt dh/dt = .159 ft/min You could do this by saying V = pi r^2 h dV/dh = pi r^2 dV/dh*dh/dt = pi r^2 dh/dt chain rule...
Friday, March 28, 2014 at 11:48pm

Calculus
Jesse has constructed a huge cylindrical can with a diameter of 60 ft. The can is being filled with water at a rate of 450 ft3/min. How fast is the depth of the water increasing? (Hint: The volume of water in the cylinder is determined by πr2h where r is the radius and h ...
Friday, March 28, 2014 at 11:39pm

math
assume no calculus allowed thus complete he square to find the vertex of this parabola 16 t^2 - 20 t - 2 = -h 16 t^2 -20 t = - h + 2 t^2 - 5/4 t = - h/16 + 1/8 t^2- 5/4 t+ 25/64 = -h/16 + 8/64 + 25/64 (t - 5/8)^2 = -(1/16)(h - 33/4) so in 5/8 of a second it reaches the vertex ...
Friday, March 28, 2014 at 10:37pm

Calculus
so it is positive for x>.316 and for x <.316
Friday, March 28, 2014 at 8:12pm

Calculus
Note that you did the second derivative correctly. It is easier to write it their way y" = 10e^(-5x^2)(10x^2-1) It is zero at x = +/- .316
Friday, March 28, 2014 at 8:11pm

Calculus
first http://www.wolframalpha.com/input/?i=plo​t++e^%28-5x^2%29 Then this for second derivative and graph https://www.wolframalpha.com/input/?i=se​cond+derivative+of+e^%28-5x^2%29
Friday, March 28, 2014 at 7:57pm

Calculus
first http://www.wolframalpha.com/input/?i=plo​t++e^%28-5x^2%29
Friday, March 28, 2014 at 7:52pm

Calculus
At what interval is e^(-5x^2) concave up? I know the second derivative is 100x^2*e^-5x^2-10*e^-5x^2 but I just can not figure this one out. Thank you for your help!
Friday, March 28, 2014 at 7:38pm

Calculus
Thanks for the advice. I checked the problem statment and answer several times and got the same result. I also suspect it to be a print mistake in the book.
Friday, March 28, 2014 at 7:46am

Calculus
As a first check, I went to http://www.wolframalpha.com/input/?i=2%E​2%88%AB[3%2C4]+%282%2F3+%E2%88%9A%28x^2-​9%29%29+dx and saw that they show the area as 2.28 So, I suspect there is an error in the problem or the answer. Your calculation appears to be correct, ...
Friday, March 28, 2014 at 5:43am

Calculus
Find the area cut off by x=4 from the hyperbola x^2/9-y^2/4=1. Answer is 4.982 in the book. I have proceeded as under: Y=2/3*sqrt(x^2-9) and rhe reqd. area is double of integral 2/3*sqrt(x^2-9) from 3 to 4. Int= 2/3*[xsqrt(x^2-9)/2 – 9/2*log{x+sqrt(x^2-9)}] from 3 to 4 =x...
Friday, March 28, 2014 at 2:17am

Calculus Help Please!!!
One of us made an arithmetic mistake. It is up to Tanya to get it right :)
Thursday, March 27, 2014 at 9:06pm

Calculus Help Please!!!
According to Newton's Law of Cooling T(t) = roomtemp + (37 - 20)e^(-kt) , where t is the time in hours and k is a constant so we get two equations: 32.5 = 20 + 17e^(-kt) ---> 12.5 = 17e^(-kt) and 30.3 = 20 + 17e^(-k(t+1)) ---> 10.3 = 17e^(-kt - k) divide them: 115/...
Thursday, March 27, 2014 at 9:02pm

Calculus Help Please!!!
rate of change of temp proportional to temp above room temp which is 20 to make it easy on the arithmetic define T' = real T - 20 dT'/dt = k (T') dT/T' = k dt ln T' = k t T' = C e^kt let's call t = 0 at 1:30 T = 32.5 so T' = 12.5 12.5 = C e^0 = ...
Thursday, March 27, 2014 at 8:54pm

Calculus Help Please!!!
I am going to assume it is algebra first take t = 0 at 1:30 T = Ti - k t Ti = 32.5 so T = 32.5 - k t 30.3 = 32.5 - k (1 hour) k = 2.2 so T = 32.5 - 2.2 t 37 = 32.5 - 2.2 t t = - 2.04 call it 2 hours so by that linear model 11:30 am now I will work on the more realistic ...
Thursday, March 27, 2014 at 8:38pm

Calculus Help Please!!!
Are you sure this is calculus? You want exponential decay to room temp? Or is it algebra and you want a linear function?
Thursday, March 27, 2014 at 8:30pm

Calculus Help Please!!!
In a murder investigation, the temperature of the corpse was 32.5 C at 1:30pm and 30.3 C an hour later. Normal body temperature is 37.0 C and the temperature of the surrounding was 20.0 C. When did the murder take place? PLEASE SHOW STEP BY STEP
Thursday, March 27, 2014 at 8:16pm

Calculus
best use radians, pi/2
Thursday, March 27, 2014 at 3:20pm

Calculus
when t=90?
Thursday, March 27, 2014 at 2:59pm

Calculus
y" = 5cos(t) so, when is that zero?
Thursday, March 27, 2014 at 2:52pm

Calculus
A weight oscillates in a vertical motion according to the position function y(t)=-5 cos(t). Assuming t≥0, when will the acceleration if the weight be zero for the first time?
Thursday, March 27, 2014 at 2:51pm

Calculus
-9.8 m/s^2
Thursday, March 27, 2014 at 2:45pm

Calculus
An object in free fall has its distance from the ground measured by the function d(t)=-4.9t^2 +50, where d is in meters and t is in seconds. If gravity is the only acceleration affecting the object, what is gravity's constant value?
Thursday, March 27, 2014 at 2:37pm

Calculus
Ahh. I see that I was interpreting 243^3/5 as (243^3)/5
Thursday, March 27, 2014 at 12:05pm

Calculus
just using ln a^b = b ln a ln (243^3/5 *32^4/5) = ln ( (3^5)^(3/5) * (2^5)^(4/5) ) = ln ( 3^3 * 2^4) = ln (27*16) = ln(432) 1/5 ln (243^3 * 32^4) = ln [ (243^3 * 32^4) ^(1/5) ] = ln (243^(3/5) * 32^(4/5) ) = .... = ln(432)
Thursday, March 27, 2014 at 12:01pm

Calculus
No one is bothered by the fact that 5 does not divide powers of 2 and 3?
Thursday, March 27, 2014 at 11:37am

Calculus
same as y": -cosx
Thursday, March 27, 2014 at 11:25am

Calculus
If y=cos x, what is y^(6) (x)?
Thursday, March 27, 2014 at 11:18am

Calculus
I agree with Damon's "huh" since ln (243^3/5 *32^4/5) = 1/5 ln (243^3 * 32^4)
Thursday, March 27, 2014 at 10:30am

CALCULUS problem
int x^-3 dx = -.5 x^-2 + c at x = 3 = -.5/9 at x = 1 = -.5 so A = .5 - .5/9 = .5(8/9) = 4/9 B at x = h int = -.5/h^2 right half = -.5/9 +.5/h^2 left half = -.5 h^2 +.5 so -.5 h^2 + .5 = -5/9 +.5/h^2 1/h^2 = .5 + 5/9 = 4.5/9 + 5/9 = 9.5/9 = 19/18 int 1 to 3 of pi (x^-6)dx = -pi...
Thursday, March 27, 2014 at 9:53am

CALCULUS problem
There are four parts to this one question, and would really appreciate if you could show and explain how you get to the answer, because I tried looking up how to find the answer myself, but nothing made sense. Thank you! 11. The region R is bounded by the x-axis, x = 1, x = 3...
Thursday, March 27, 2014 at 8:51am

Calculus
huh?
Thursday, March 27, 2014 at 7:51am

Calculus
good except for this step: ln (243^3/5 *32^4/5) should be 1/5 ln (243^3 * 32^4)
Thursday, March 27, 2014 at 5:36am

Calculus
The hands of a clock in some tower are 4.5m and 2m in length. How fast is the distance between the tips of the hands changing at 9:00 at time t hours after 12:00, (at t=0) the minute hand is at 4.5 sin(2pi*t) the hour hand is at 2.0sin(2pi*t/12) at 9:00, the distance d is d^2...
Thursday, March 27, 2014 at 5:34am

Calculus
x = ln 243 y = ln 32 LET Z = e^((3x + 4y)/5) ln [z ]= (3x+4y)/5 ln z = (1/5)( 3 ln 243 + 4 ln 32) = ln (243^3/5 *32^4/5) = ln (27*16) = ln(432) if ln z = ln 432 then z = 432
Thursday, March 27, 2014 at 3:54am

Calculus
Posted by MG on Wednesday, March 26, 2014 at 6:54pm. The hands of a clock in some tower are 4.5m and 2m in length. How fast is the distance between the tips of the hands changing at 9:00? (Hint: Use the law of cosines) The distance between the tips of the hands is changing at ...
Thursday, March 27, 2014 at 3:36am

Calculus
If e^x = 243 and e^y = 32 then e^((3x + 4y)/5) =? The answer is 432, but I don't understand why.
Thursday, March 27, 2014 at 3:34am

College Calculus
Thank you for the response, i tried the method mentioned above three times and was incorrect each time, i double checked all my work to match the method above. The correct answer is always just .3 under the answer All of your arithmetic is right as well, so it is not that. ...
Thursday, March 27, 2014 at 3:31am

pre calculus
C(x) = 2.00 for 0 < x <= 1 2.00 + .20(10x) for 1 < x < 2 since there are 10 charging units per mile.
Thursday, March 27, 2014 at 12:10am

pre calculus
A taxi company charges $2.00 for the first mile (or part of a mile) and 20 cents for each succeeding tenth of a mile (or part). Express the cost C (in dollars) of a ride as a piecewise-defined function of the distance x traveled (in miles) for 0 < x < 2
Thursday, March 27, 2014 at 12:07am

Calculus
Thank you very much!
Wednesday, March 26, 2014 at 11:46pm

Pre calculus
yes. The reason the law of sines can give two triangles is because sin(x) is positive all the way from 0 to 180. cos(x) becomes negative for x>90, so the formula takes that into account, always leaving only one possible answer. I mean, think about it geometrically. If you ...
Wednesday, March 26, 2014 at 11:46pm

Calculus
Since velocity is the derivative of position, v(t) = -32t + 160 now just solve -32t+160 = 32 -32t+128 = 0 t = 4
Wednesday, March 26, 2014 at 11:39pm

Calculus
The height in feet above the ground of a ball thrown upwards from the top of a building is given by s=-16t^2 + 160t + 200, where t is the time in seconds. If the maximum height is 600 feet, what is v^-1(32)? The answer is supposed to be 4 seconds, but I don't understand ...
Wednesday, March 26, 2014 at 11:07pm

argggh - Calculus
messed up in my expansion volume should have been 4x^3- 120x^2 + 800x and V' = 12x^2 - 240x + 800 = 0 3x^2 - 60x + 200=0 to get x = 4.23
Wednesday, March 26, 2014 at 10:11pm

Calculus
First things first: width --- s length ---- 2s 2s^2 = 800 s^2 = 400 s = 20 so the piece of metal is 20 by 40 let the side of the square to be cut out be x so the width is 20-2x the length is 40-2x the height is x Volume = x(20-2x)(40-2x) = 2x^3 - 120x^2 + 800x d(Volume)/dx = ...
Wednesday, March 26, 2014 at 10:05pm

Calculus
You are given a piece of sheet metal that is twice as long as it is wide an has an area of 800m^2. Find the dimensions of the rectangular box that would contain a max volume if it were constructed from this piece of metal by cutting out squares of equal area at all four ...
Wednesday, March 26, 2014 at 9:49pm

Calculus
you should have recalled that sin (-x) = -sinx so that sin(-.1) could not have been positive. did you mean -.1 ?
Wednesday, March 26, 2014 at 9:14pm

Calculus
Use a tangent line approximation at x=0 to estimate the value of sin(-0.1). I got 0.1
Wednesday, March 26, 2014 at 8:56pm

Calculus
yes v(t) = h ' (t) = -16t + 5 so v(0) = -16(0) + 5 = 5
Wednesday, March 26, 2014 at 8:54pm

Calculus
The vertical position of an object is modeled by the function h(t)=-16t^2 +5t+7, where h is measured in feet and t is measured in seconds. Find the object's initial velocity (that is, the velocity at t=0). Is it 5 feet per second?
Wednesday, March 26, 2014 at 8:46pm

Pre calculus
For the most part, will a law of cosines always be one triangle? As in one triangle to solve?
Wednesday, March 26, 2014 at 8:35pm

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