Thursday
March 13, 2014

# Homework Help: Math: Calculus

calculus
suppose you use symbols instead of words: f(x) = 3x-k for x < 5 = kx+1 for x >= 5 for f to be continuous at x=5, we need 15-k = 5k+1 14 = 6k k = 7/3
Wednesday, February 5, 2014 at 7:54pm

calculus
x^2+4x <= f(x) <= -(x^2+4x) If x = -2, -4 <= f(x) <= 4 I don't think squeezing applies.
Wednesday, February 5, 2014 at 7:52pm

calculus
what is wrong with using symbols? 2x/(√x-2) the limit as x->4 is 8/0 which is undefined. In fact, since √x-2 is positive as x->4 from the right and negative as x->4 from the left, it's both unbounded and unequal from left and right. I think (b) is the ...
Wednesday, February 5, 2014 at 7:49pm

Pre-Calculus
thanks
Wednesday, February 5, 2014 at 7:46pm

Pre-Calculus
amount= origamount*1.5^timeInYears so in four years, amount=orig*1.5^4 earned=amount-orig=orig^1.5^4-orig 29250=orig (1.5^4-1) solve for orig, then then solve for amountafter4years, and amount after three years, and subtract. amounteared4thyr= orig(1.5^4-1.5^3) = orig (1.5^3)(...
Wednesday, February 5, 2014 at 7:30pm

Pre-Calculus
A certain sum of money is invested in a business. in each year this investment earns 1 1/2 times as much as in the preceding year. If the investment earned a total of $29,250.00 in four years, how much did it earn in the fourth year? Wednesday, February 5, 2014 at 7:22pm calculus Which of the following best describes the limit as x approaches 4 of the quotient of 2 times x divided by the quantity negative 2 plus square root of x ? It exists and equals 4 It fails to exist because it is unbounded. It fails to exist because its one-sided limits are not ... Wednesday, February 5, 2014 at 6:58pm calculus It is known that x 2 + 4x ≤ f(x) ≤ -x 2 -4x the interval [-4, 0]. Use the Squeeze Theorem to evaluate the limit as x approaches negative 2 of f of x. -4 0 4 Squeeze Theorem does not apply Wednesday, February 5, 2014 at 6:58pm calculus Suppose f of x equals 3 times x minus k when x is less than 5 and equals 1 plus k times x when x is greater than or equal to 5.Find the value of k that would make f continuous at x = 5. -3 0 7/3 no such k will make f continuous Wednesday, February 5, 2014 at 6:57pm calculus At a constant temperature, the pressure, P, and volume, V, of a trapped gas have the relationship P equals the quotient of k divided by V , where k is some positive constant. What occurs if the volume is compressed such that V → 0+? The pressure increases without bound. ... Wednesday, February 5, 2014 at 6:56pm Calculus 2 M = ∫[0,4]∫[x/2+4,√x+4] ​61; dy dx = ρ∫[0,4] (√x+4)-(x/2+4) dx = ρ∫[0,4] √x - x/2 dx = ρ (2/3)x^(3/2) - (1/4)x^2 [0,4] = ρ (2/3)(8)-(1/4)(16) = 4/3 ρ Mx = ∫[0,4]∫[x/2+4,√x+4] ​... Wednesday, February 5, 2014 at 5:52pm Calculus 2 Find Mx, My, and (x, y) for the laminas of uniform density ρ bounded by the graphs of the equations. y=sqrt(x)+4 y=(1/2)x+4 The I keep getting 20/3 for Mx but webassign acts like it is wrong. Wednesday, February 5, 2014 at 1:51pm calculus at time t, the distance d is d^2 = (90-20t)^2 + (15t)^2 d^2 = 625t^2 - 3600t + 8100 2d dd/dt = 1250t-3600 dd/dt=0 when t=72/25 d(72/25) = 54 Wednesday, February 5, 2014 at 1:04pm calculus At midnight, ship B was 90 km due south of ship A. Ship A sailed east at 15 km/hr and ship B sailed north at 20 km/hr. At what time were they closest together? Wednesday, February 5, 2014 at 10:38am calculus At midnight, ship B was 90 km due south of ship A. Ship A sailed east at 15 km/hr and ship B sailed north at 20 km/hr. At what time were they closest together? Wednesday, February 5, 2014 at 10:35am Calculus u=1-3√x du = -3/(2√x) = (-3/2)(1/√x) you already have 1/√x, so the new integrand becomes ʃ 1/u (-2/3)du that should make it clear Wednesday, February 5, 2014 at 6:04am Calculus I'd really like some help in solving an integral. ʃ 1/ √x (1-3√x) In numerator: 1 In denominator: the square root of x times 1 minus 3 times the square root of x The answer given is -2/3 ln l1-3√xl + C but I don't know how to get there. Wednesday, February 5, 2014 at 12:05am CALCULUS 2 Use calculus to find the volume of the following solid S: The base of S is an elliptical region with boundary curve 9x^2+4y^2=36. Cross-sections perpendicular to the x-axis are isosceles right triangles with hypotenuse in the base. Tuesday, February 4, 2014 at 10:47pm Calculus http://answers.yahoo.com/question/index?​qid=20101016110803AAKwID9 Tuesday, February 4, 2014 at 10:36pm Calculus I am wondering what rule you are using... I suspect it is Simpsons Rule, if so do that. That will give you the distance of the path. see http://answers.yahoo.com/question/index?​qid=20101016110803AAKwID9 Tuesday, February 4, 2014 at 10:36pm Calculus A steady wind blows a kite due west. The kite's height above ground from horizontal position x = 0 to x = 60 ft is given by the following. y= 155-(1/40)(x-50)^2 Find the distance traveled by the kite. Tuesday, February 4, 2014 at 10:27pm Calculus Find the distance traveled by the kite Tuesday, February 4, 2014 at 10:24pm Calculus http://en.wikipedia.org/wiki/Simpson%27s​_rule Tuesday, February 4, 2014 at 10:14pm Calculus and the question...? Tuesday, February 4, 2014 at 10:12pm Calculus A steady wind blows a kite due west. The kite's height above ground from horizontal position x = 0 to x = 60 ft is given by the following. y= 155-(1/40)(x-50)^2 Tuesday, February 4, 2014 at 10:09pm Calculus Use Simpson's Rule with n = 10 to estimate the arc length of the curve. y = tan x, 0 < x < π/9 Tuesday, February 4, 2014 at 10:08pm calculus just take the graph of y=x^3 and shift it right 5 and up 2. Tuesday, February 4, 2014 at 5:25am calculus Use the principles of translating and reflecting to graph the function f(x)=(x-5)^3 +2 Tuesday, February 4, 2014 at 1:27am pre calculus determine the order of magnitude for the following: 1. a$1 bill and a dime 2. two products scored a PH level of 6.1 and 4.o I can't figure out #1… but I did get #2 to be 10^2.1 Please help with #1 and check to see I did #2 right?
Monday, February 3, 2014 at 4:25pm

calculus
y = (-5x+4)/(10-5x) = (4-5x)/(10-5x) At x=2 there is a vertical asymptote, since 10-5x=0 As x gets large, y -> 1 since y = (4/x - 5)/(10/x - 5) -> -5/-5 = 1
Monday, February 3, 2014 at 5:47am

calculus
y= -5x + 4 OVER 10 - 5x find the asymptotes of the function
Monday, February 3, 2014 at 1:37am

Calculus II
Solve the initial value problem using Taylor Series and the following conditions: y'(t) = y(t) + 2t y(0) = A
Sunday, February 2, 2014 at 11:01pm

Calculus
8.42
Sunday, February 2, 2014 at 8:42pm

as you know, the average velocity is the integral divided by the time interval. Since the position is the integral of the velocity, the average velocity in [a,b] = (s(b)-s(a))/(b-a) So, we have i) (s(2)-s(1))/(2-1) = (2sin2π+3)-(2sinπ+3) = 0 ii) (s(1.1)-s(1))/(1.1-1...
Sunday, February 2, 2014 at 8:26pm

SHOW WORK PLEASE!!! The displacement (in centimeters) of a particle moving back and forth along a straight line is given by the equation of motion s = 2 sin πt + 3 cos πt, where t is measured in seconds. (Round your answers to two decimal places.) (a) Find the ...
Sunday, February 2, 2014 at 8:12pm

calculus
g = m t + b m = (17-8)/(47-28) = .4737 so g = .4737 t + b 8 = .4737 (28) + b so b = -5.263 so g = 0.4737 t - 5.263
Sunday, February 2, 2014 at 5:03am

calculus
In a lab experiment 8 grams of acid were produced in 28 minutes and 17 grams in 47 minutes. Let g be the number of grams and m be the number of minutes. Find a linear equation that you could use to calculate g for any number of minutes.
Sunday, February 2, 2014 at 3:28am

calculus
Consider the function f(x) = 5 (x - 5)^(2//3) . For this function there are two important intervals: (-\infty, A) and (A,\infty) where A is a critical number. Find A
Sunday, February 2, 2014 at 2:38am

CALCULUS
I don't understand. Why are you adding 1/4? to both sides? I don't see how you are getting a quadratic formula from this. More importantly, thank you guys for the help!
Sunday, February 2, 2014 at 12:29am

calculus
I guess the foxes were factored in when calculating the surviving rabbit population, eh?
Saturday, February 1, 2014 at 6:41pm

calculus
I bet we want the maximum, but usually the foxes are included in these island problems. dP/dt = 0 at max = 120 -1.6 t^3 t^3 = 120 t = 4.93 months
Saturday, February 1, 2014 at 6:23pm

Calculus & Vectors
240 * 1.25 = 300 @ N20W = <-102.6,281.9> 240 * 2.00 = 480 @ N80E = <472.7,83.4> add 'em up to get <370.1,315.3> So, the distance back is 486.2 300+480+486.2 = 1266.2 km at 240 km/hr = 5.3 hours
Saturday, February 1, 2014 at 6:18pm

Calculus & Vectors
A search and rescue aircraft, travelling at a speed of 240 km/h starts out at a heading of N 20 degrees West. After travelling for 1h and 15 min, it turns to a heading of N 80 degrees E and continues for another two hours before returning to base. Find the total distance the ...
Saturday, February 1, 2014 at 6:10pm

calculus - and?
in the words of Larry King, "What's the question?"
Saturday, February 1, 2014 at 5:32pm

calculus
The rabbit population on a small island is observed to be given by the function P(t)=120t−0.4t4+700 where t is the time (in months) since observations of the island began.
Saturday, February 1, 2014 at 5:28pm

CALCULUS
Whoops !
Saturday, February 1, 2014 at 11:47am

calculus
Well if you only have five days total, hopefully it only takes the remaining one day to solve it! Otherwise, you're in trouble!
Saturday, February 1, 2014 at 11:32am

CALCULUS
noticed an error from line 2 to line 3 y^2 - y = x y^2 - y + 1/4 = x + 1/4 (y - 1/2)^2 =(4x+1)/4 y - 1/2 = ±√(4x+1)/2 y = 1/2 ± √(4x+1)/2 = (1 ± √(4x+1) )/2 , x ≥ -1/4
Saturday, February 1, 2014 at 10:37am

CALCULUS
x = y^2 - y y^2 - y + 1 = x + 1 (y-1)^2 = x + 1 y -1 = sqrt (x+1) y = 1 + sqrt (x+1)
Saturday, February 1, 2014 at 9:46am

COURSE HELP PLEASE ms sue qq
In high school, these courses are usually called Algebra I Algebra II Geometry Pre-calculus AP Calculus Biology AP Biology Chemistry AP Chemistry Physics AP Physics Work with your counselor to make sure you take the required courses for graduation AND as many of these as ...
Saturday, February 1, 2014 at 9:41am

CALCULUS
Find a formula for the inverse of the function. y=x^2-x, x>=(greater than or equal to) 1/2 Please give me a step by step explanation. I think my algebra is wrong... Ty
Saturday, February 1, 2014 at 9:16am

calculus
Four out of five days were used to create a problem, how many days will it take to solve it?
Saturday, February 1, 2014 at 8:21am

calculus
Four out of five days were used to create a problem, how many day will it take to solve it?
Saturday, February 1, 2014 at 8:21am

integral calculus
If you mean ∫[x,4] x/(x-4) dx that's a bit unusual to have the variable of integration as one of the limits. But ok, let's work it out as-is. ∫x/(x-4) dx = x + 4 log(x-4) Evaluating that at 4 and x, we have (4+4log(0))-(x+4log(x-4)) Looks like -∞ to ...
Friday, January 31, 2014 at 10:56pm

integral calculus
Evaluate the limit limit gose from x to 4 (x/x-4)integral from x to 4
Friday, January 31, 2014 at 10:04pm

Calculus
Thank you!
Friday, January 31, 2014 at 10:00pm

Calculus
point in first plane 0,0 something (0 , 0 , 10) d = | 10*0 -8*0 +2*10 -3 | /sqrt(10^2+8^2+4^2) = 17/13.4
Friday, January 31, 2014 at 8:07pm

Calculus
here is an example of how to do this: http://www.math.ucla.edu/~ronmiech/Calcu​lus_Problems/32A/chap11/section5/718d65/​718_65.html
Friday, January 31, 2014 at 8:01pm

Calculus
when x gets really big positive this is y = 2 (big) / sqrt(big ^2) which is y = 2 when x gets really big negative y = 2 (-big number) / big number which is y = - 2 well, let's look at the derivative since they say so [ (x^2+x+1)2 - 2x(.5)(x^2+x+1)^-.5(2x) ]/(x^2+x+1) yuuk...
Friday, January 31, 2014 at 5:50pm

Calculus
we have two points in that plane (8, 0, -2) and (6, 3, 3) a vector through those points has direction (6-8)i + 3 j + (2+2)k = -2 i + 3 j + 4 k so we have two vectors parallel to plane, their cross product is normal to the plane i j k -2 5 2 the given line direction -2 3 4 the ...
Friday, January 31, 2014 at 5:35pm

Calculus
Let f be the function given by f(x)= 2x/(sqrt(x^2 +x +1)) c. Write an equation for each horizontal asymptote of the graph of f. d. Find the range of f. Use f'(x) to justify your answer.
Friday, January 31, 2014 at 5:26pm

Calculus
vector normal to plane has direction 3 i + 2 j + 6 k line normal to plane through point is (1, -5 , 9) + (3, 2, 6) t where does that hit the plane? 3(1+3t) + 2(-5+2t) + 6(9+6t) = 5 solve for t go back and use that t to get x, y, z in plane x = 1+3t y = -5+2t z = 9+6t then d^2...
Friday, January 31, 2014 at 5:09pm

Calculus
pick a point in plane #1, say (2,3,1) Now just use the distance formula to get the distance to 6x-6y+6z=3 or, equivalently, 2x-2y+2z-1 = 0 d = |2*2-2*3+2*1-1|/√(2^2+2^2+1^2) = 1/√5
Friday, January 31, 2014 at 4:47pm

Calculus
see http://www.jiskha.com/display.cgi?id=139​1198824 for the method
Friday, January 31, 2014 at 4:36pm

Calculus
(1+4t) +2 (4t) -(2-3t) = -1 solve for t then use that t to find x, y z
Friday, January 31, 2014 at 4:35pm

Calculus
going from the first point to the second dx = 3 dy = -2 dz = 4 so my line direction is 3 i -2 j + 4 k and my line in parametric form is (1,0,1) + (3, -2, 4) t at intersection x = 1+3t y = -2 t z = 1+4t and we know x + y + z = 10 2 + 5 t = 10 t = 8/5 so x = 1 + 24/5 = 29/5 y...
Friday, January 31, 2014 at 4:32pm

Calculus
perpendicular to the direction 1 i - 1 j + 2 k Vxi + Vyj + Vzk if perpendicular dot product is 0 Vx - Vy + 2 Vz = 0 also parallel to plane x+y+z = constant 2 so normal to the normal to that plane 1 i + 1 j + 1 k Vxi + Vyj + Vzk Vx + Vy + Vz = 0 so we have Vx - Vy + 2 Vz = 0 Vx...
Friday, January 31, 2014 at 4:14pm

Calculus
Find the distance between the given parallel planes. 4z = 4y − 4x, 6z = 3 − 6x + 6y
Friday, January 31, 2014 at 3:15pm

Calculus
Find the distance between the given parallel planes. 5x−4y+z=10, 10x−8y+2z=3
Friday, January 31, 2014 at 3:14pm

Calculus
Find the distance from the point to the given plane. (−3,8,7), x−2y−4z=8
Friday, January 31, 2014 at 3:13pm

Calculus
Find the distance from the point to the given plane. (1,−5,9), 3x+2y+6z=5
Friday, January 31, 2014 at 3:12pm

Calculus
Find parametric equations for the line through the point (0,2,2)that is parallel to the plane x+y+z = 2 and perpendicular to the line x=1+t, y=2−t, z=2t. (Use the parameter t.) (x(t), y(t), z(t)) =
Friday, January 31, 2014 at 3:11pm

Calculus
Where does the line through (1,0,1) and (3,−2,5)intersect the plane x+y+z=10? (x, y, z) =________?
Friday, January 31, 2014 at 3:09pm

Calculus
Find the point at which the line intersects the given plane. x = 1 + 4t, y = 4t, z = 2−3t ; x + 2y − z + 1 = 0 (x, y, z) = _____________?
Friday, January 31, 2014 at 3:07pm

Calculus
Find the point at which the line intersects the given plane. x = 4 − t, y = 5 + t, z = 2t; x − y + 3z = 3 (x, y, z) =____________?
Friday, January 31, 2014 at 3:05pm

Calculus
Find an equation of the plane. The plane that passes through the point (−1, 2, 1)and contains the line of intersection of the planes x + y − z = 4 and 4x − y + 5z = 4
Friday, January 31, 2014 at 3:04pm

Calculus
Find an equation of the plane. The plane that passes through (8, 0, −2)and contains the line x = 6 − 2t, y = 3 + 5t, z = 3 + 2t
Friday, January 31, 2014 at 2:57pm

calculus
22
Friday, January 31, 2014 at 7:27am

CALCULUS
y = 4-(5x-4) = 8-5x
Friday, January 31, 2014 at 6:01am

CALCULUS
Starting with the graph of f(x)=5x, write the equation of the graph that results from reflecting f(x) about the line y =4. y=_______? Thank you!
Friday, January 31, 2014 at 12:27am

Math Pre-Cal
If you do know calculus, find the derivative and set it equal to zero (the slope is 0 at a max or min) 4 x -12 = 0 so x = 3 then y = 2x^2-12x-6 = 2(9) -12(3) -6 =18 - 36 - 6 = -24 that vertex is a minimum because y gets big as x gets big
Thursday, January 30, 2014 at 9:51pm

Math Pre-Cal
If you do not know calculus you must find the vertex of that parabola.
Thursday, January 30, 2014 at 9:45pm

Calculus
l) (g)^2 + (h)^2=1 so 2 g g' + 2 h h' = 0 g g' = -h h' g' = -(h/g) h' 2)g' = h^2 and h' = -g g'/h h' = - g h^2/h = -gh that is part a then If h has a max, then h' has a zero - g h = 0 ? either g = 0 or h = 0 if h is max, look for ...
Thursday, January 30, 2014 at 3:30pm

Calculus
(a) using (i) and (ii) 2gg' + 2hh' = 0 2gh^2 + 2hh' = 0 gh + h' = 0 h' = -gh (b) from (a) and (iv), h'(0) = -g(0)*h(0) = 0 h" = -g'h-gh' so, h"(0) = -g'(0)h(0) Since h(0)>0, g'(0)>0, so h"(0) < 0 (c) from (ii) and...
Thursday, January 30, 2014 at 3:15pm

Calculus
Let g and h be any two twice-differentiable functions that are defined for all real numbers and that satisfy the following properties for all x: I) (g(x))^2 + (h(x))^2=1 ii) g'(x)= (h(x))^2 iii) h(x)>0 iv) g(0)=0 a)Justify that h'(x)=-g(x)h(x) for all x b) Justify ...
Thursday, January 30, 2014 at 2:44pm

Calculus
Thank you!
Thursday, January 30, 2014 at 2:28pm

Calculus II
you know it will be a plane normal to the vector <7,-3,-6> passing through (3/2,9/2,0). I'm sure you've covered that.
Thursday, January 30, 2014 at 11:55am

Calculus II
Find an equation of the set of all points equidistant from the points A(−2, 6, 3) and B(5, 3, −3)
Thursday, January 30, 2014 at 11:33am

Pre-Calculus
factor out 2x^5(x^2-9)^7 and you have 2x^5(x^2-9)^7 * (8x^2 + 3(x^2-9)) = 2x^5(x^2-9)^7 (8x^2+3x^2-27) and voila...
Thursday, January 30, 2014 at 6:09am

Pre-Calculus
Actually I figured out that you use both, and ended up with 16x^7(x^2-9)^7 + 6x^5(x^2-9)^8. but I don't understand how that simplifies to 2x^5(x^2-9)^7(11x^2-27)?
Thursday, January 30, 2014 at 12:47am

Physics
Problem 1 (80 points) Consider a spring of equilibrium length L, lying horizontally in a frictionless trough. The spring has cross sectional area S perpendicular to its length. The trough constrains the motion of the spring so that any wave propagating along the spring is a ...
Wednesday, January 29, 2014 at 11:24pm

Pre-Calculus
Find dy/dx if y= x^6[(x^2-9)^8]? So the answer is supposed to be 2x^5[(x^2-9)^7](11x^2-27), but I don't understand how to get it. Do you use product rule, chain rule or both? thanks
Wednesday, January 29, 2014 at 9:44pm

Calculus
first fall, 40 ft, then second bounce 2(40*3/5), third 2*(40*3/5)(3/5), etc Now, how can you determine what rest is?
Wednesday, January 29, 2014 at 8:17pm

Calculus
A superball is tossed vertically 40 feet and rebounds on each bounce 3/5 of the height from which it fell. How far will it travel before coming to rest?
Wednesday, January 29, 2014 at 8:14pm

Calculus
If you are going to integrate over y, the solid has two parts: a plain old cylinder of height 4 and thickness 2, and a variable-thickness shape of height 2. So, v = π(5^2-3^2)(4) + ∫[4,6] π(R^2-r^2) dy where R=5 and r=x-1=y-1 v = 64π + π∫[4,6] ...
Wednesday, January 29, 2014 at 5:34pm

Calculus
dy/dx = 2/2 = 1 so y = x + b 0 = 3 + b b = -3 so y = x - 3 if x(t) = k t for example then y(t) = x(t) - 3 y(t) = k t - 3
Wednesday, January 29, 2014 at 5:03pm

Calculus
c) as t --->oo v ---->1/t = 0 d) 500 = 5 + .5 ln (t^2+1) 495 (2) = ln(t^2+1) 990 = ln (t^2+1) e^(990) = t^2 + 1 oh, my, calculator overflow :)
Wednesday, January 29, 2014 at 4:58pm

Calculus
dx/dt = t/(1+t^2) that will be maximum when the derivative d^2x/dt^2 = 0 d^2x/dt^2 = [(1+t^2)1 -t(2t) ](1+t^2)^2 0 when numerator is zero 0 = 1 + t^2 - 2 t^2 0 = 1 - t^2 t^2 = 1 so max or min at t = 1 we know it is max because v decreases with big x a ) so max v = 1/2 at t = 1...
Wednesday, January 29, 2014 at 4:53pm

Calculus
A particle starts at the point (5,0) at t=0 and moves along the x-axis in such a way that at time t>0 its velocity v(t) is given by v(t)= t/(1+t^2). a). Determine the maximum velocity of the particle. Justify your answer. b). Determine the position of the particle at t=6. c...
Wednesday, January 29, 2014 at 4:38pm

Calculus
write in parametric form the equation of the line that joins (1,-2) and (3,0)
Wednesday, January 29, 2014 at 4:14pm

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