Recent Homework Questions About Calculus
Calculus Fundamental Theorem
Evaluate the definite integral. function: x+13 with respect to variable x lower limit:0 upper limit:22
Wednesday, November 20, 2013 at 4:47pm
without a diagram, I assume point A is an anchor in between the towers. If its distance from T1 is x, then the cable length is d = √(60^2+x^2) + √(20^2+(140-x)^2) to find the minimum, we want dd/dx = 0 That happens when x=105
Wednesday, November 20, 2013 at 2:30am
wow that was a silly mistake I didn't see the x next to 500 and thought I could just subtract it from 1000 thank you!
Wednesday, November 20, 2013 at 1:38am
Wow, I didn't realize that finding (x-2) was already finding the equation of the line. Thanks!
Tuesday, November 19, 2013 at 10:05pm
f" = -4sin2x f' = 2cos2x + c 2+c = 4 c=2 so, f' = 2cos2x + 2 f = sin2x + 2x + c 0+0+c = -6 c = -6 so, f = sin2x + 2x - 6
Tuesday, November 19, 2013 at 9:17pm
f" = 5x+2sinx f' = 5/2 x^2 - 2cosx + c f'(0)=3, so 0-2+c=3 c=5 so, f' = 5/2 x^2 - 2cosx + 5 f = 5/6 x^3 - 2sinx + 5x + c f(0)=3, so 0-0+0+c=3 c=3 so, f=5/6 x^3 - 2sinx + 5x + 3 I assume you can now find f(3)
Tuesday, November 19, 2013 at 7:21pm
oh yeah thanks I forgot that the reciprocal had to be negative
Tuesday, November 19, 2013 at 8:22am
since F(1) = 0, we have -7 + 6/5 + c = 0 which you can plug in to evaluate F(2)
Monday, November 18, 2013 at 8:16pm
if the rectangular window has width 2x and height h, then the area of the whole shape is a = 2xh + pi/2 x^2 You also know that x+2h+pi*x = 25, so solve for h and plug into the formula for area. The set da/dx = 0.
Monday, November 18, 2013 at 8:07pm
If the printed area has width x and height y, xy = 386 The total area is thus a = (x+8)(y+4) = (x+8)(386/x + 4) = 4x + 418 + 3088/x max area is where da/dx=0 da/dx = 4 - 3088/x^2 so, da/dx = 0 when x = 2√193 Now just evaluate y.
Monday, November 18, 2013 at 8:06pm
Thursday, November 20, 2008 at 8:14pm