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April 21, 2014

Homework Help: Math: Calculus

Recent Homework Questions About Calculus

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calculus help
I've tried your answers to this question but they were all marked wrong. Thanks anyway!
Saturday, April 19, 2014 at 5:57pm

Calculus Help
I did put these answers in but they're marked wrong Thank you!
Saturday, April 19, 2014 at 5:41pm

calculus help
Nothing. I use SCI unless ordered otherwise :)
Saturday, April 19, 2014 at 5:11pm

calculus help
what's wrong with 28/3 mi/hr/s ? :-)
Saturday, April 19, 2014 at 5:04pm

calculus help
4.14 m/s^2 = 13.6 ft/s^2 :)
Saturday, April 19, 2014 at 4:55pm

calculus help
ignore the very last "the acceleration is 9.33" pressed "post answer" too soon so the acceleration is a = 13.59 ft/s^2 and v = 13.59t + 32.2667 a = 13.59 ft/s^2
Saturday, April 19, 2014 at 4:52pm

Calculus Help
b) the answer is in (a) twice 2178 feet I think you can figure the rest out
Saturday, April 19, 2014 at 4:45pm

calculus help
If the acceleration is a then v = at + c , where c is a constant: when t=0 , v = 22 mi/h = 32.2666.. ft/s 32.266.. = a(0) + c c = 32.2666.. when t = 3s , v = 50 mi/h = 73.333.. ft/s 73.333.. = a(3) + 32.26666... 3a = 41.06666.. a = 13.58888.. the acceleration is 13.89 ft/s^2 ...
Saturday, April 19, 2014 at 4:44pm

Calculus Help
90 mi/hr = 132 ft/s (a) first how long and how far to reach 132 ft/s v = 0 + 4 t 132 = 4 t t = 33 s to reach 132 d = .5 a t^2 = 2 (33)^2 = 2178 ft to reach cruising speed 15*60 = 900 seconds total 900 - 33 = 867 seconds left how far at cruising speed 132 ft/s * 867 s = 114,...
Saturday, April 19, 2014 at 4:43pm

calculus help
22 mph = 9.83 m/s 50 mph = 22.35 m/s a = change in velocity/time = (22.35 -9.81)/3 = 4.18 m/s^2 or about half g
Saturday, April 19, 2014 at 4:32pm

Calculus Help
A high-speed bullet train accelerates and decelerates at the rate of 4 ft/s2. Its maximum cruising speed is 90 mi/h. (Round your answers to three decimal places.) (a) What is the maximum distance the train can travel if it accelerates from rest until it reaches its cruising ...
Saturday, April 19, 2014 at 3:55pm

calculus help
What constant acceleration is required to increase the speed of a car from 22 mi/h to 50 mi/h in 3 s? (Round your answer to two decimal places.)
Saturday, April 19, 2014 at 3:42pm

calculus
x^2+1=0 x^2=-1 in real numbers it cant be. so x=i and x=-i (solution in the set of complex numbers)
Saturday, April 19, 2014 at 9:09am

calculus
x^4 + 2x^2 + 1 = 0 (x^2)^2 +2x^2 +1 = 0 (x^2 + 1)^2 = 0 I don't know where to go now although I know the answer is x = i, -i
Saturday, April 19, 2014 at 9:03am

Calculus Help Please Urgent!!!
I stand by mine and Damon's answer for a minimum area. I even ran a simple 1980's style "BASIC" program to show it 10 a = 5000 20 for x = 0 to 14 step 1.000000E-05 30 y = (14-4*x)/3 40 na = x*x+sqr(3)/4*y*y 50 if na < a then a = na : side = x 60 next x 70 ...
Saturday, April 19, 2014 at 8:24am

Calculus Please Need Urgent3 :/
see what I said here: http://www.jiskha.com/display.cgi?id=139​7810241
Saturday, April 19, 2014 at 4:54am

Calculus Please Need Urgent2 :/
what, no ideas at all? Just straightforward integration. f"(x) = 8x+4sin x f'(x) = 4x^2 - 4cos x + C So, since f'(0) = 2, 16-4+C = 2 C = -10 and so f'(x) = 4x^2 - 4cos x - 10 Now do that all over again to get f(x)
Saturday, April 19, 2014 at 4:52am

Calculus Please Need Urgent :/
you have ∫-8e^x - 6sec^2 x dx = -8e^x - 6tan x + C
Saturday, April 19, 2014 at 4:50am

Calculus Help Please!
what's the problem? The integral is just normal power stuff ∫ t^3 + 6t^2 + 4 dt = 1/4 t^4 + 2t^3 + 4t now evaluate that at x and 0, and you have f(x) = 1/4 x^4 + 2x^3 + 4x so, f"(x) = 3x^2 + 12x
Saturday, April 19, 2014 at 4:48am

calculus - garbled
better try just typing in the text, rather than copying from you application.
Saturday, April 19, 2014 at 4:45am

calculus
Let f x   coth x . Use the Graph software posted in Moodle to do the following: (a) Graph f x  . (b) Graph the tangent and normal lines to the graph of f x  at x 1. (c) Graph f x  . (d) ...
Saturday, April 19, 2014 at 3:19am

Calculus Please Need Urgent3 :/
Find the derivative of the following function using the appropriate form of the Fundamental Theorem of Calculus. F(x)= (s^2)/(1+3s^4)ds from sqrtx to 1 F'(x)=? Thank you so much guys!
Saturday, April 19, 2014 at 12:39am

Calculus Please Need Urgent2 :/
Consider the function f(x) whose second derivative is f''(x)=8x+4sin(x). If f(0)=3 and f'(0)=2, what is f(x)? f(x)=??
Saturday, April 19, 2014 at 12:38am

Calculus Please Need Urgent :/
Find the most general antiderivative of f(x)=–8e^x–6secant^2(x) where -pi/2<x<pi/2 Note: Any arbitrary constants used must be an upper-case "C". F(x)=?
Saturday, April 19, 2014 at 12:37am

Calculus Help Please!
If f(x)=Integral (t^3+6t^2+4)dt from 0 to x then f''(x)=?
Saturday, April 19, 2014 at 12:34am

Calculus Help and Check
v = 3/2 √t s = t^(3/2)+C 8+C = 17, so C=9 s(t) = t^(3/2) + 9 How did you get C=1?
Saturday, April 19, 2014 at 12:24am

Calculus Help Please Urgent!!!
How about this then? if the side of the square is x and the side of the triangle is y, then 4x + 3y = 14 and the total area is x^2 + y^2 √3/4 = x^2 + √3/4 (14-4x)/3)^2 = 1/18 (18x^2 - 2√3 x + 7√3) just a parabola, with vertex at x = 1/(6√3) So, ...
Saturday, April 19, 2014 at 12:19am

Calculus Help and Check
how about the third one!
Friday, April 18, 2014 at 11:56pm

Calculus Help and Check
first: correct, also x/5)- ln(x^3)+C second 2x^2+x^3+3x^4+8x+Cx + K f(o)=2=k or K=2 f(1)=10=2+1+3+8+C +2 means C=10-16=-6 >>>f(x)=2x^2+x^3+3x^4+8x -6x + 2 f'= 4x + 3x^2 +12x^3 + 2 f"= 4+6x + 36x^2
Friday, April 18, 2014 at 11:00pm

Calculus Help and Check
1)Find the most general antiderivative of the function. (Check your answer by differentiation. Use C for the constant of the antiderivative. Remember to use ln |u| where appropriate.) f(x) = (1/5)−(3/x) -----> (x/5)-3lnx+C 2)Find f. f ''(x) = 4 + 6x + ...
Friday, April 18, 2014 at 10:47pm

Calculus Help Please Urgent!!!
Thank you both! But your answers were wrong.
Friday, April 18, 2014 at 10:40pm

Calculus Help Please Urgent!!!
I also got 6.09 (actually 6.0895..) I defined the side of the triangle slightly different from Damon to avoid as many fractions as I could. let each side of the square be x m let each side of the equilateral triangle be 2y m that way I can say that the height of the triangle ...
Friday, April 18, 2014 at 8:20pm

Calculus Help Please Urgent!!!
square side = x triangle side = y perimeter = 4 x + 3 y = 14 area = x^2 + sqrt3 (y^2)/4 x = (14 - 3 y)/4 area = (196 - 84 y +9y^2)/16 + 4 (3^.5)y^2/16 = [1/16] (196 - 84 y + 15.93 y^2) dA/dy = 0 for max or min 0= -84 y + 31.86 y^2 so y = 0 or y = 2.63 so x = 14/4 or 1.528 so 4...
Friday, April 18, 2014 at 8:02pm

Calculus Help Please Urgent!!!
A piece of wire 14 m long is cut into two pieces. One piece is bent into a square and the other is bent into an equilateral triangle. (a) How much wire should be used for the square in order to maximize the total area? 14 m this one I got right (b) How much wire should be used...
Friday, April 18, 2014 at 6:57pm

calculus
your equation came out looking rather jibberish on my computer, but I see it contans x's and y's I can give you the general method of doing this question .... Find the derivative with respect to t, then your result should contain dx/dt and dy/dt , as well as x and y ...
Friday, April 18, 2014 at 8:23am

calculus
when the man is x from the pole, and his shadow is s, 150/300 = h/(250+300) so, the pole's height is h=275 cm so, at any time, 150/s = 275/(x+s) or, more easily manipulated, (x+s)/275 = s/150 x/275 = s/330 x = 5/6 s so, at any time dx/dt = 5/6 ds/dt since dx/dt = 15, ds/dt...
Friday, April 18, 2014 at 5:39am

Calc
Find the derivative of the following function using the appropriate form of the Fundamental Theorem of Calculus. intergral s^2/(1+3s^4) ds from sqrtx to 1 F'(x)=?
Friday, April 18, 2014 at 4:37am

Calculus
Consider the function f(x) whose second derivative is f''(x)=8x+4sin(x). If f(0)=3 and f'(0)=2, what is f(x)?
Friday, April 18, 2014 at 4:35am

Calculus
Find the derivative of the following function using the appropriate form of the Fundamental Theorem of Calculus. intergral s^2/(1+3s^4) ds from sqrtx to 1 F'(x)=?
Friday, April 18, 2014 at 4:34am

calculus
A bug crawls along the graph of 2 y x x    4 1 , where x and y are positive and measured in centimeters. If the x-coordinate of the bug’s position x y,  changes at a constant rate of 3 cm/min, how fast is the y-coordinate changing ...
Friday, April 18, 2014 at 3:48am

calculus
A person 150cm tall is walking away from a lamp post at the rate of 15 meter per minute. when the man is 2.5m from the lamp post, his shadow is 3m long. Find the rate at which the length of the shadow is increasing when he is 7m from the lamp post.
Friday, April 18, 2014 at 1:09am

calculus
1
Thursday, April 17, 2014 at 10:45pm

Calculus
g' = 8f + 8x * f' g'(3) = 8f(3) + 24*f'(3) = 8*4 + 24*5 = 152
Thursday, April 17, 2014 at 1:22pm

Calculus
Given f(3)=4 and f'(3)=5, find g'(3), where g(x)=8x.f(x)
Thursday, April 17, 2014 at 1:17pm

CALCULUS
with a slight change to the numbers, this question is treated at http://www.jiskha.com/display.cgi?id=139​2927547
Thursday, April 17, 2014 at 12:08pm

Calculus
let be base be x ft by x ft let the height be y ft (x^2)(y) = 3 y = 3/x^2 Cost = 3(x^2) + 2(4xy) = 3x^2 + 8x(3/x^2) = 3x^2 + 24/x d(cost)/dx = 6x - 24/x^2 = 0 for a min of cost 6x = 24/x^2 x^3 = 4 x = cuberoot(4) = appr 1.6 ft the base should be appr 1.6 ft by 1.6 ft (the ...
Thursday, April 17, 2014 at 9:25am

Calculus
An open top box with a square base is to be made so that it holds 3 cubic feet. Assuming the material on the base costs $3 per square foot and the material on the sides costs $2 per square foot, determine the size of the base that minimizes the total cost.
Wednesday, April 16, 2014 at 11:09pm

CALCULUS
The base of S is a circular disk with radius 3r. Parallel cross-sections perpendicular to the base are isosceles triangles with height 8h and unequal side in the base. a. set up an interval for volume of S b. by interpreting the intergal as an area, find the volume of S
Wednesday, April 16, 2014 at 9:49pm

calculus help
https://www.wolframalpha.com/input/?i=de​rivative+of+x^2%28x%2B3%29%2F%28x%2B1%29​^3 6x / (x+1)^4
Wednesday, April 16, 2014 at 7:21pm

calculus help
then do it again :)
Wednesday, April 16, 2014 at 7:19pm

calculus help
[(x+1)^2 (3 x^2)-x^3 (2)(x+1)] /(x+1)^4 [(x+1)(3x^2) - 2 x^3 ]/ (x+1)^3 [ 3 x^3 + 3 x^2 -2 x^3 ] / (x+1)^3 [ x^3 + 3 x^2] /(x+1)^3 x^2 (x+3) / (x+1)^3
Wednesday, April 16, 2014 at 7:15pm

calculus help
https://www.wolframalpha.com/input/?i=de​rivative+of+%28x^3%29%2F%28%28x%2B1%29^2​%29+
Wednesday, April 16, 2014 at 7:09pm

calculus help
find y' and y'' for the equation below. Show work please!!! y= (x^3)/((x+1)^2)
Wednesday, April 16, 2014 at 6:53pm

calculus
http://www.mathsisfun.com/data/function-​grapher.php f' = 7 e^7x - e^-x when is that zero? 7 e^7x = e^-x 7 e^8x = 1 e^8x = 1/7 8 x = ln(1/7) x = -.243 at min
Wednesday, April 16, 2014 at 6:12pm

calculus help
try : https://www.google.com/search?q=graph+ln​%28x%29+from+1+to+6&ie=utf-8&oe=utf-8&aq​=t&rls=org.mozilla:en-US:official&client​=firefox-a&channel=sb ln 6 = 1.79 ln 1 = 0 ln 6 - ln 1 = 1.79 1.79/5 = .36 approx ln x = .36 e^ln x = ? = e^.36 so x = 1.43 sure ...
Wednesday, April 16, 2014 at 5:54pm

calculus help
Play with this: https://www.wolframalpha.com/input/?i=de​rivative+of+1%2B%281%2Fx%29%2B%285%2Fx^2​%29%2B%281%2Fx^3%29+
Wednesday, April 16, 2014 at 5:45pm

calculus help check and help
a) calculate lim t->infinity (v. answer: mg/c ----->what is the meaning of this limit ============================== It is the "terminal velocity" (Google that) which is the speed where the drag force equals the weight. One uses a parachute so that one's ...
Wednesday, April 16, 2014 at 5:39pm

calculus help
Produce graphs of f that reveal all the important aspects of the curve. Then use calculus to find the intervals of increase and decrease and the intervals of concavity. f(x)= 1+(1/x)+(5/x^2)+(1/x^3) find the interval of increase. find the interval of decrease. find the ...
Wednesday, April 16, 2014 at 5:37pm

calculus help check and help
if an object with mass m is dropped from rest, one model for its speed v after t seconds, taking air resistance into account is v= mg/c(1-e^(-ct/m)) where g is the acceleration due to gravity and c is a positive constant describing air resistance. a) calculate lim t->...
Wednesday, April 16, 2014 at 5:01pm

calculus
consider the equation below f(x)=e^(7x)+e^(-x) find the intervals on which f is increasing and decreasing (enter your answers using interval notation) find the local minimum of f. find the interval on which f is concave up.
Wednesday, April 16, 2014 at 4:24pm

calculus help
Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval? f(x)= ln(x) , [1,6] If it satisfies the hypotheses, find all numbers c that satisfy the conclusion of the Mean Value Theorem. (Enter your answers as a comma-separated list. If it does not...
Wednesday, April 16, 2014 at 4:15pm

Calculus Help Please!!!
As mentioned, let BC = x distance over water: √(x^2+49) distance over land: 11-x (a) energy expended: y = 1.3√(x^2+49) + 11-x dy/dx = 1.3x/√(x^2+49) - 1 y'=0 at x = 70/√69 what do you get for the other parts?
Wednesday, April 16, 2014 at 3:54pm

calculus help
There's a nice discussion here: http://math.stackexchange.com/questions/​126755/lhospitals-rule-with-indeterminat​e-powers
Wednesday, April 16, 2014 at 3:44pm

calculus help
explain fully what trick you must use in order to us L'Hospital's rule for indeterminate powers?
Wednesday, April 16, 2014 at 3:33pm

Calculus Help!!!!!
should be no problem. That's just Algebra II. Anyway, y = x^3/(x+1)^2 y' = x^2(x+3)/(x+1)^3 y" = 6x/(x+1)^4 see the graph and some analysis here: http://www.wolframalpha.com/input/?i=x^3​%2F%28x%2B1%29^2
Wednesday, April 16, 2014 at 3:29pm

Calculus Help!!!!!
sketch the graph of the following. Show all your work and include all the important points and asymptotes. also find y' and y'' ? y= (x^3)/(x+1)^2
Wednesday, April 16, 2014 at 3:21pm

Calculus Help Please!!!
Ornithologists have determined that some species of birds tend to avoid flights over large bodies of water during daylight hours. It is believed that more energy is required to fly over water than land because air generally rises over land and falls over water during the day. ...
Wednesday, April 16, 2014 at 2:26pm

Calculus Help Please Urgent!!!
1/3 pi r^2 h = 30, so h = 90/(pi r^2) surface area = 2 pi r s where r^2+h^2 = s^2, so a = 2 pi r √(r^2 + (90/(pi r^2))^2) = 2/r √(pi^2 r^6 + 8100) for minimum paper, we need da/dr = 0, so, as wolframalpha so ably shows at http://www.wolframalpha.com/input/?i=2+p&#...
Wednesday, April 16, 2014 at 6:06am

calculus help please
let each side of the square be x m let each side of the equilateral triangle be 2x (that way, the height is √3y, from the ratio of the 30-60-90° triangle) a) for a max area, you are right, all should be used for the square b) 4x + 6y = 14 2x + 3y = 7 x = (7-3y)/4 OR ...
Tuesday, April 15, 2014 at 11:41pm

calculus help
R(x)=x(1800-6x) R(x)=1800x-6x^2 R'(x)=1800-12x C'(x)=600-1.2x+.012x^2 Marginal revenue = marginal cost 1800-12x=600-1.2x+.012x^2 1200=10.8x+.012x^2 1200=.012x(900+x) 100,000=x(900+x) 100,000=900x+x^2 x^2+900x-100000 =0 (x-100)(x-1000) =0 x = 100 x+1000) = 0 x = 100 At ...
Tuesday, April 15, 2014 at 10:33pm

calculus help please
A piece of wire 14 m long is cut into two pieces. One piece is bent into a square and the other is bent into an equilateral triangle. (a) How much wire should be used for the square in order to maximize the total area? = 14 m (b) How much wire should be used for the square in ...
Tuesday, April 15, 2014 at 10:10pm

calculus help
If C(x) = 12000 + 600x − 0.6x^2 + 0.004x^3 is the cost function and p(x) = 1800 − 6x is the demand function, find the production level that will maximize profit. (Hint: If the profit is maximized, then the marginal revenue equals the marginal cost.)
Tuesday, April 15, 2014 at 8:35pm

Calculus Help Please Urgent!!!
A cone-shaped paper drinking cup is to be made to hold 30 cm^3 of water. Find the height and radius of the cup that will use the smallest amount of paper. (Round your answers to two decimal places.) Height = ? Radius = ? Show work please!!!
Tuesday, April 15, 2014 at 8:06pm

Math--Calculus
Hmm. Don't know...
Tuesday, April 15, 2014 at 1:42pm

Calculus II
Compute the first 5 terms of the sequence: {b(n)}n=1-> infinity = nsqrt(6n) + (5/6)^n. ((that is:(Bsub(n))from n=1 to infinity = nth root of 6n + (5/6)raised to n.)) If the sequence converges, find the limit.
Tuesday, April 15, 2014 at 1:08pm

Calculus II
Consider the sequence: (a,sub(n))={1/n E(k=1 to n) 1/1+(k/n)} Show that the limit(as n-> infinity) A(sub(n))= ln 2 by interpreting a(sub(n)) as a Reimann Sum of a Definite Integral.
Tuesday, April 15, 2014 at 1:07pm

calculus
1/10 ∫[0,10] 3/(x+1) dx = 3/10 ln(11)
Tuesday, April 15, 2014 at 5:05am

calculus
find average value of f [0,10] f(x)= 3/x+1
Tuesday, April 15, 2014 at 12:47am

calculus
So, the height is 40/x^2 c(x) = 2x^2*5 + 4x(40/x^2)*2 = 10x^2 + 320/x set the derivative to zero, and you find minimum cost at x = 2∛2
Tuesday, April 15, 2014 at 12:11am

calculus
A box is contructed out of two different types of metal. The metal for the top and bottom, which are both square, costs $5 per square foot and the metal for the sides costs $2 per square foot. Find the dimensions that minimize cost if the box has a volume of 40 cubic feet.
Monday, April 14, 2014 at 11:41pm

calculus
false
Monday, April 14, 2014 at 11:09pm

Calculus II
Compute the first 5 terms of the sequence: {b(n)}n=1¨‡ = nã6n + (5/6)^n. ((that is:(Bsub(n))from n=1 to infinity = nth root of 6n + (5/6)raised to n.)) If the sequence converges, find the limit.
Monday, April 14, 2014 at 5:44pm

Calculus 2
In the following series x is a real number. In each case, use the ratio test to determine the radius of convergence of the series. Analyze the behavior at the endpoints in order to determine the interval of convergence. a. Summation n=0 to infinity (n(x^n))/(n^2 + 2) b. ...
Monday, April 14, 2014 at 2:55pm

Calculus Help Please Urgent!!!
Hmmm. we all know that tan x -> x as x->0 so, cot x -> 1/x as x->0 so the limit ought to be zero.
Sunday, April 13, 2014 at 11:33pm

Calculus Help Please Urgent!!!
lim -> 0 (cot(x)-(1/x)) , x---> 0 = sec^2 x + 1/x^2 by L'Hospital's Rule but that is just as bad try experimentally ... using a Calculator let x = .0001 I get -.0000333 let x = .000001 my calculator says 0 http://www.wolframalpha.com/input/?i=lim​it+cot%28x...
Sunday, April 13, 2014 at 11:06pm

Calculus Help Please Urgent!!!
find the limit algebraically. Use L'Hospital's Rule where appropriate. If there is a moare elementary method, consider using it. If L'Hospital's Rule doesn't apply, explain why lim -> 0 (cot(x)-(1/x)) show work please!!!
Sunday, April 13, 2014 at 10:39pm

Calculus
let the length of the side using bricks be x ft let the other two sides each be y ft given: xy = 900 --> y = 900/x cost = 5(x + 2y) + 10x = 15x + 10y = 15x + 10(900/x) d(cost)/dx = 15 - 9000/x^2 = 0 for min of cost 15 = 9000/x^2 15x^2 = 9000 x^2 = 600 x = √600 = 10&#...
Sunday, April 13, 2014 at 10:03pm

Calculus
ABC Daycare wants to build a fence to enclose a rectangular playground. The area of the playground is 900 square feet. The fence along three of the sides costs $5 per foot and the fence along the fourth side, which will be made of brick, costs $10 per foot. Find the length of ...
Sunday, April 13, 2014 at 9:48pm

Math 10
sure, all you have to do is to find the vertex of this "downwards" parabola. I will assume that you do not know Calculus , so (easiest way): the x of the vertex for y = ax^2 + bx + c is -b/(2a) so for your equation, the t of the vertex is -10/-10 = 1 sub into the ...
Sunday, April 13, 2014 at 6:57pm

calculus
if the printed area has width and height x and y, then the total area is a = (x+8)(y+12) and xy=384 a = (x+8)(384/x + 12) = 12x + 3072/x + 480 that is minimum when da/dx = 0, so we need 12 - 3072/x^2 = 0 x = 16 so the poster is (16+8) by (24+6) or 24x30
Sunday, April 13, 2014 at 6:48am

calculus
Hmmm. If the population is p, then we have dp/dt = kp dp/p = k dt ln(p) = kt + c p = c e^kt Now we know that p triples in 14 days, so we can forgo using e, and just use 3 as our base: p(t) = Po * 3^(t/14) so, starting with 100, and gaining 15 per day and losing 23 each day, ...
Sunday, April 13, 2014 at 6:42am

calculus
A population of a very rare insect in an area in a discrete rural region in ASEAN will grow at a rate that is proportional to their current population. In the absence of any outside factors, the population will triple in two weeks’ time. On any given day there is a net ...
Sunday, April 13, 2014 at 12:19am

calculus
The top and bottom margins of a rectangular poster are 6 centimeters each, and the side margins are 4 centimeters each. If the area printed on the poster is fixed at 384 cm2, a) Sketch the figure. b) Find the dimensions of the poster using the least amount of paper.
Sunday, April 13, 2014 at 12:17am

calculus
in the following series x is a real number. In each case use the ratio test to determine the radius of convergence of the series. Analyze the behavior of the series at the endpoints in order to determine the interval of convergence. A) (nx^n)/(n^2 + 2) B)((n^2)(x-2)^n)/2^n C...
Saturday, April 12, 2014 at 9:18pm

CALCULUS
algebraically, since both functions are symmetric about the origin, the area is zero. geometrically, using symmetry, you have the area is 2∫[0,pi/9] (tan3x - 2sin3x) dx = 2/3 (2cos 3x - log cos 3x)[0,pi/9] = 2/3 (log2 - 1)
Saturday, April 12, 2014 at 6:37pm

Calculus
y = xe^(-4x) y' = (1-4x)e^(-4x) y" = 8(2x-1)e^(-4x) since e^(-4x) > 0 for all x, y" < 0 when 2x-1 < 0. see the graph at http://www.wolframalpha.com/input/?i=+xe​^%28-4x%29+for+0+%3C%3D+x+%3C%3D+1
Saturday, April 12, 2014 at 6:27pm

CALCULUS
or thats not right
Saturday, April 12, 2014 at 5:30pm

CALCULUS
thank you!
Saturday, April 12, 2014 at 5:27pm

Calculus
For what values of x is the graph of y=x e^{-4 x} concave down?
Saturday, April 12, 2014 at 5:07pm

CALCULUS
If I read it correctly, you have y=4/x, y=16x, and y=x/16 for x>0 You need to break the area into two regions, because the two top curves intersect at x = 1/2 So the area is ∫[0,1/2] 16x - x/16 dx + ∫[1/2,8] 4/x - x/16 dx = (8x^2-x^2/32)[0,1/2] + (4logx-x^2/32)[...
Saturday, April 12, 2014 at 4:47pm

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