What quantity of sulfur will exa tly react with 128g of oxygen gas to form sulfur dioxide

S + O2 = SO2

32g+32g = 64g (molecular mass)

So the two reactants are in the ratio of their molecular masses (MM)

Can you find the mass of sulphur required?

To determine the quantity of sulfur required to react with 128g of oxygen gas to form sulfur dioxide, we need to use their respective molar masses and the stoichiometry of the chemical equation.

1. Find the molar mass of oxygen (O₂):
The molar mass of oxygen gas (O₂) is 2 × 16.00 g/mol = 32.00 g/mol.

2. Determine the molar mass of sulfur dioxide (SO₂):
The molar mass of sulfur dioxide (SO₂) can be calculated as follows:
S: 1 × 32.07 g/mol = 32.07 g/mol
O: 2 × 16.00 g/mol = 32.00 g/mol
Total molar mass = 32.07 + 32.00 = 64.07 g/mol.

3. Set up the ratio using the molar masses and molar ratios:
Since the balanced chemical equation for the reaction is:
2S + O₂ → 2SO₂
The ratio of moles between sulfur (S) and oxygen (O₂) is 2:1.

Sulfur:Oxygen = (32.07 g/mol)/(32.00 g/mol) = 1:1
(as the molar mass of sulfur is very close to that of oxygen)

4. Calculate the moles of oxygen:
Moles of oxygen = mass of oxygen (g) / molar mass of oxygen (g/mol)
Moles of oxygen = 128 g / 32.00 g/mol = 4.0 mol

5. Calculate the moles of sulfur:
Since the ratio of sulfur to oxygen in the reaction is 2:1,
Moles of sulfur = 2 × moles of oxygen
Moles of sulfur = 2 × 4.0 mol = 8.0 mol

6. Convert moles of sulfur to grams:
Mass of sulfur = moles of sulfur × molar mass of sulfur (g/mol)
Mass of sulfur = 8.0 mol × 32.07 g/mol = 256.56 g

Therefore, exactly 256.56 grams of sulfur will react with 128 grams of oxygen gas to form sulfur dioxide.

To determine the quantity of sulfur that will react with 128g of oxygen gas to form sulfur dioxide, we need to write and balance the chemical equation for the reaction in which sulfur reacts with oxygen to form sulfur dioxide. The balanced equation is as follows:

2S + 2O2 → 2SO2

From the balanced equation, we can see that 2 moles of sulfur react with 2 moles of oxygen gas to produce 2 moles of sulfur dioxide.

To calculate the quantity of sulfur needed to react with 128g of oxygen gas, we need to convert the given mass of oxygen gas to moles using its molar mass and then use the stoichiometry of the balanced equation to find the mole ratio between sulfur and oxygen gas.

The molar mass of oxygen gas (O2) is 32 g/mol (16 g/mol × 2).

128 g of oxygen gas is equal to:
128 g / (32 g/mol) = 4 mol of oxygen gas

According to the balanced equation, for every 2 moles of oxygen gas, we need 2 moles of sulfur. Therefore, the mole ratio of sulfur to oxygen gas is 1:1.

Since the mole ratio is 1:1, we conclude that 4 moles of sulfur are required to react with 128 g of oxygen gas to form sulfur dioxide.