The probability that John wins a game is 4/5, and, independently, the probability that Meghan wins is 9/11. What is the probability that Meghan wins and John loses the game?
prob(John wins) = 4/5 -----> prob(John loses) = 1/5
Since the events do not depend on each other, what do we do with the probabilities in
Prob(Megan winds AND John loses) ??
do I multiply them?
more specifically, do I multiply 1/5 and 9/11?
yes. just review your text on the topic of independent events.
ok thanks!
To find the probability that Meghan wins and John loses the game, we need to multiply their individual probabilities.
The probability that Meghan wins is given as 9/11.
The probability that John loses is the complement of the probability that John wins, which can be calculated as 1 - (4/5) = 1/5.
To find the probability that Meghan wins and John loses, we simply multiply these probabilities together:
Probability (Meghan wins and John loses) = (9/11) * (1/5)
Multiplying the fractions, we get:
Probability (Meghan wins and John loses) = 9/55
Therefore, the probability that Meghan wins and John loses the game is 9/55.