A student performs an experiment. On her desk, she directs a light ray at the flat surface of an unknown transparent material at an angle to the normal of 47 degrees. The light ray enters the material at an angle to the normal of 34 degrees. What is the index of refraction for this unknown material?
1sin47=(n2)sin34
0.7314=(n2)0.5592
n2=1.31
A) Is that correct?
B) If I were to draw a diagram of this would I have:
A flat surface
The normal line perpendicular to the flat surface
The incident ray coming in at 47 degrees on the left side of the normal
The refracted ray going out underneath the flat surface at 34 degrees on the right side of the normal
Thanks for your time :)
A) Yes, your calculation is correct. The index of refraction for the unknown material is indeed 1.31, given the input values.
B) Your diagram description seems accurate. Here's a step-by-step guide to creating the diagram:
1. Start by drawing a flat surface (represented by a straight line).
2. Draw a line perpendicular to the flat surface. This line represents the normal line.
3. Draw the incident ray coming in from the left side of the normal, making an angle of 47 degrees with the normal line.
4. Draw the refracted ray going out underneath the flat surface on the right side of the normal, making an angle of 34 degrees with the normal line.
Remember that the incident ray should be drawn on one side of the normal, and the refracted ray on the other side, both at the appropriate angles. This will help illustrate the path of the light ray through the unknown transparent material.