12gm of potassium sulphate is dissolved in 25 gm of water at 60 degree. what is solubility in water at that temperature?

To find the solubility of potassium sulfate in water at 60 degrees Celsius, we need to determine the maximum amount of potassium sulfate that can be dissolved in 25 grams of water at that temperature.

The solubility of a substance is often expressed in terms of grams of solute dissolved in a given amount of solvent (in this case, grams of potassium sulfate dissolved in grams of water).

To calculate the solubility, we can divide the mass of potassium sulfate dissolved by the mass of water and then convert it to a percentage.

Given:
Mass of potassium sulfate = 12 grams
Mass of water = 25 grams

Solubility = (mass of potassium sulfate / mass of water) * 100

Solubility = (12 grams / 25 grams) * 100
Solubility = 0.48 * 100
Solubility = 48%

Therefore, the solubility of potassium sulfate in water at 60 degrees Celsius is 48%.

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