back from break, need help again
The height , h, in feet, of a bottle rocket is modeled by:
where t is the time in seconds.
A. Factor the expression.
H = -16t^2 + 60t = 4t(-4t + 15)
B. What is the height of the rocket after 2 seconds?
When t = 2
H = 4t(-4 times 2 + 15) = 28
C. What is the height of the rocket after 3.75 seconds? Explain the solution.
When t = 3.75
H = 4t(-4 times 3.75 + 15) = 0?
(when I try to calculate this I get 0 and that can't be right, I'm doing something completely wrong I think)
Forgot to post the Modeled by part: h = -16t^2 + 60t
B. calculation error
C. zero is correct
... the rocket has to come back down at some point
What was the error in my calculation on B?
it's fairly obvious ... troubleshoot it ...
Let's work through the problem together to find the correct answer.
To find the height of the rocket after 3.75 seconds, we can substitute the value of t into the expression for the height, H.
Given: H = 4t(-4t + 15)
Substituting t = 3.75 into the equation:
H = 4(3.75)(-4(3.75) + 15)
= 4(3.75)(-15 + 15)
= 4(3.75)(0)
= 0
It seems like you made a small error when calculating. The height of the rocket after 3.75 seconds is indeed 0 feet.
This means that at 3.75 seconds, the rocket has reached its maximum height and is starting to descend back to the ground.