A toddler applies a 25.0 N force to a chair over a distance of 2.5 m, the chair is being pushed across a smooth floor against a force of friction (10.0 N resistance). How much work is being done?

Work due to frictional resistance

= frictional force * Distance
Here
force = 10.0 N (due to friction)
Distance = 2.5 m

The answer says 62 J not 25

From the data given, I cannot explain the difference. If you have a diagram, please post.

Perhaps someone else can enlighten you on this.

To calculate the work done, we need to use the formula:

Work = Force × Distance

In this scenario, the toddler is applying a force of 25.0 N to the chair over a distance of 2.5 m. However, there is also a force of friction opposing the motion, which we need to take into account. The resistance due to friction is 10.0 N.

To find the net force, we subtract the force of friction from the force applied by the toddler:

Net Force = Force applied - Force of friction

Net Force = 25.0 N - 10.0 N

Net Force = 15.0 N

Now we can use the formula to calculate the work done:

Work = Net Force × Distance

Work = 15.0 N × 2.5 m

Work = 37.5 Joules

Therefore, the work done to push the chair is 37.5 Joules.