A heavy uniform bar is carried by two men on their shoulders. The weight of the bar is W. If one man lets it fall from the end carried by him, what will be the weight experienced by the other?
A.W
B.W/2
C.W/4
D.0
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To solve this problem, we can consider the principles of equilibrium and Newton's third law of motion.
When two men are carrying a heavy uniform bar, the weight of the bar is evenly distributed between them. Therefore, each man carries half the weight of the bar, which is W/2.
According to Newton's third law of motion, when one man lets go of his end of the bar, the reaction force exerted by the other man on the bar will be equal in magnitude and opposite in direction. Hence, the weight experienced by the other man will still be W/2.
Therefore, the correct answer is B. W/2.
To determine the weight experienced by the other man when one man lets the bar fall from the end carried by him, we need to consider the distribution of weight on the bar.
Let's assume that the length of the bar is L, and each man is carrying the bar at its midpoint. Since the bar is uniform, the weight is evenly distributed along its length.
When both men are carrying the bar, each man is supporting half of the weight. So, each man is carrying W/2 weight.
Now, if one man lets go of the bar, the entire weight of the bar will be transferred to the other man. Since the weight of the bar is W, the other man will now be carrying the full weight of W.
Therefore, the weight experienced by the other man when one man lets the bar fall is option A, W.