Carbon disulphide reacts with oxygen gas to produce carbo dioxide gas and sulphur dioxide gas (balance)

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To balance the chemical equation for the reaction between carbon disulfide (CS2) and oxygen gas (O2) to produce carbon dioxide gas (CO2) and sulfur dioxide gas (SO2), we need to ensure that the number of atoms of each element is the same on both sides of the equation.

The unbalanced equation is:
CS2 + O2 → CO2 + SO2

To balance it, follow these steps:

1. Determine the number of each type of atom on both sides of the equation:
Left side (reactants): 1 carbon (C) atom, 2 sulfur (S) atoms, and 2 oxygen (O) atoms.
Right side (products): 1 carbon (C) atom, 2 sulfur (S) atoms, and 2 oxygen (O) atoms.

2. Start by balancing the elements that appear in only one reactant and one product. In this case, carbon and sulfur are already balanced, so we can focus on oxygen.

3. Calculate the number of oxygen atoms on the left side: 2 oxygen atoms in CS2 + 2 oxygen atoms in O2 = a total of 4 oxygen atoms.

4. Calculate the number of oxygen atoms on the right side: 2 oxygen atoms in CO2 + 2 oxygen atoms in SO2 = a total of 4 oxygen atoms.

5. Since the number of oxygen atoms is already balanced, the equation is now balanced. The balanced equation is:
CS2 + 3O2 → CO2 + 2SO2

Now, there are 1 carbon (C) atom, 2 sulfur (S) atoms, and 6 oxygen (O) atoms on both the reactant and product sides of the equation, making it balanced.