the lenth of a poal is 11\2 meter. 1\3rd of the poal is painted red, 1\4th is painted in green and the remaining portion in blue. find thd lenth of the portion painted in blue?

It would help if you proofread your questions before you posted them.

Is the length of the pole 11.2 meters or 11 halves (11/2) of a meter?

1 - 1/3 - 1/4 = 1 - 4/12 - 3/12 = 5/12

So the blue portion is 5/12 of whatever the length of the pole is.

11/2-{(11/2X1/3)+(11/2X1/4)}=2 7/24

11/2-{(11/2X1/3)+(11/2X1/4)}

=11/2-(11/6+11/8)
=11/2-77/24
=55/24=2*7/24

To find the length of the portion painted in blue, we need to determine how much of the pole is painted in red and green first.

1. Start by finding the length of the pole painted in red:
Divide the total length of the pole by the denominator of the fraction that represents the portion painted in red.
11/2 ÷ 3/3 = 11/2 ÷ 1/3 = 11/2 × 3/1 = 33/2 = 16.5 meters

Therefore, the length of the pole painted in red is 16.5 meters.

2. Next, find the length of the pole painted in green:
Repeat the same process as above, but this time divide the total length of the pole by the denominator of the fraction representing the portion painted in green.
11/2 ÷ 4/4 = 11/2 ÷ 1/4 = 11/2 × 4/1 = 44/2 = 22 meters

Thus, the length of the pole painted in green is 22 meters.

3. Finally, calculate the length of the portion painted in blue:
Subtract the sum of the lengths of the portions painted in red and green from the total length of the pole.
Total length of the pole = 11/2 meters
Length painted in red = 16.5 meters
Length painted in green = 22 meters

Blue portion length = Total length - (Length painted in red + Length painted in green)
Blue portion length = 11/2 - (16.5 + 22)
Blue portion length = 11/2 - 16.5 - 22
Blue portion length = -16.5 - 22
Blue portion length = -38.5

Hence, based on the given information, the length of the portion painted in blue is -38.5 meters.