Write out the first five terms of the sequence

an=3(4n-1)

To find the first five terms of the sequence defined by the formula an = 3(4n-1), we need to substitute different values of n into the formula.

Let's plug in n = 1:
a1 = 3(4(1)-1)
= 3(4-1)
= 3(3)
= 9

Now let's plug in n = 2:
a2 = 3(4(2)-1)
= 3(8-1)
= 3(7)
= 21

Next, n = 3:
a3 = 3(4(3)-1)
= 3(12-1)
= 3(11)
= 33

For n = 4:
a4 = 3(4(4)-1)
= 3(16-1)
= 3(15)
= 45

Finally, n = 5:
a5 = 3(4(5)-1)
= 3(20-1)
= 3(19)
= 57

Therefore, the first five terms of the sequence defined by an = 3(4n-1) are 9, 21, 33, 45, and 57.

c'mon. Just substitute values for n, from 1 to 5:

a1 = 3(4*1-1) = 3(4-1) = 3(3) = 9
and so on