a ball of weight 200 grams,is tied to the end of a cord and whirled in a horizontal circle of radius 0.6 m.if the ball makes five complete revolutions in 2 seconds,what will be the linear speed of the ball?
since speed = distance/time, just plug in your numbers:
((2π*0.6)*5 m)/(2s) = 3π m/s
Circumference = pi*D = 3.14*1.2m = 3.77 m.
5rev/2s. * 3.77m/rev = 9.42 m/s. = Linear speed.
To find the linear speed of the ball, we can use the formula:
v = (2πr) / t
where:
v = linear speed
r = radius
t = time
In this case, the radius of the circle is given as 0.6 m, and the time taken for 5 complete revolutions is given as 2 seconds.
Plugging these values into the formula:
v = (2π * 0.6) / 2
v ≈ 1.884957 m/s
Therefore, the linear speed of the ball is approximately 1.884957 m/s.
To find the linear speed of the ball, we can use the formula:
Linear speed = (2πr) / t
Where:
- Linear speed is the velocity at which the ball is moving in a circular path.
- π (pi) is a mathematical constant approximately equal to 3.14.
- r is the radius of the circular path.
- t is the time taken to complete the circular path.
In this case, the radius (r) is given as 0.6 m and the time (t) taken to complete five revolutions is given as 2 seconds.
Step 1: Calculate the circumference of the circle
Circumference = 2πr
Substituting the given value of r:
Circumference = 2 * 3.14 * 0.6 m
Circumference = 3.76 m
Step 2: Calculate the distance traveled by the ball in 5 revolutions.
Distance = 5 * Circumference
Substituting the value of Circumference:
Distance = 5 * 3.76 m
Distance = 18.8 m
Step 3: Calculate the linear speed.
Linear speed = Distance / Time
Substituting the given value of Time:
Linear speed = 18.8 m / 2 s
Linear speed = 9.4 m/s
Therefore, the linear speed of the ball is 9.4 m/s.