Find the second, fourth, and tenth terms of the sequence described the the rule.
A(n)=4+(n-1)(8)
huh? Just plug in the numbers for n:
A(2) = 4+(2-1)(8) = 4+1*8 = 4+8 = 12
and similarly for any other values of n.
To find the second, fourth, and tenth terms of the sequence described by the rule A(n) = 4 + (n-1)(8), we can substitute the respective values of n into the formula and evaluate.
Let's start with the second term (n = 2):
A(2) = 4 + (2-1)(8)
= 4 + 1(8)
= 4 + 8
= 12
Therefore, the second term is 12.
Next, let's find the fourth term (n = 4):
A(4) = 4 + (4-1)(8)
= 4 + 3(8)
= 4 + 24
= 28
Therefore, the fourth term is 28.
Finally, we'll determine the tenth term (n = 10):
A(10) = 4 + (10-1)(8)
= 4 + 9(8)
= 4 + 72
= 76
Therefore, the tenth term is 76.
In summary:
- The second term is 12.
- The fourth term is 28.
- The tenth term is 76.