Chemistry
posted by Joseph on .
A solution is made by dissolving 10.20 grams of glucose (C6H12O6) in 355 grams of water. What is the freezing point depression of the solvent if the freezing point constant is 1.86 °C/m?

delta T = Kf*m
Kf = 1.86
m = mols/kg solvent and mols = grams/molar mass. Substitute and solve for m.
Then substitute into dT = KfM and solve for dT. Post your work if you get stuck.