3. Consider a freely falling object.

a. What is the acceleration (in m/s2) after 5 seconds of fall?
b. What is the acceleration (in m/s2) after 10 seconds of fall?
c. What is the velocity (in m/s) after 5 seconds of fall?
d. What is the velocity (in m/s) of 10 seconds of fall?

a. the acceleration is a function of gravity...it is essentially constant

b. see a.

gravitational acceleration (g) is 9.8 m/s^2
... for every second you fall, you go 9.8 m/s faster

for c. and d. , multiply the free-fall time by the acceleration (g)

To answer these questions, we need to understand a few concepts related to freely falling objects.

Firstly, we need to know that in the absence of air resistance, all objects near the surface of the Earth experience a constant acceleration known as the acceleration due to gravity, denoted as "g." On Earth, the average value of acceleration due to gravity is approximately 9.8 m/s^2.

a. To find the acceleration after 5 seconds of fall, we can simply use the value of acceleration due to gravity, which is constant. So the acceleration after 5 seconds of fall will also be 9.8 m/s^2.

b. Similarly, after 10 seconds of fall, the acceleration will still be 9.8 m/s^2.

c. To find the velocity after 5 seconds of fall, we can use the equation of motion:

v = u + at

Where:
v = final velocity
u = initial velocity (which is 0 in this case since the object starts from rest)
a = acceleration
t = time

Plugging in the values, we get:

v = 0 + (9.8 m/s^2)(5 s)
v = 49 m/s

So the velocity after 5 seconds of fall will be 49 m/s.

d. Similarly, after 10 seconds of fall, we can use the same equation:

v = 0 + (9.8 m/s^2)(10 s)
v = 98 m/s

So the velocity after 10 seconds of fall will be 98 m/s.

To answer these questions, we need to know the value of the acceleration due to gravity (g), which is approximately 9.8 m/s^2.

a. After 5 seconds of fall, the acceleration of the object is still the acceleration due to gravity, which is 9.8 m/s^2.

b. After 10 seconds of fall, the acceleration of the object is still the acceleration due to gravity, which is 9.8 m/s^2.

c. After 5 seconds of fall, the velocity of the object can be calculated using the formula v = u + at, where v is the final velocity, u is the initial velocity (which is assumed to be zero for a freely falling object), a is the acceleration, and t is the time. Plugging in the values, we get:
v = 0 + (9.8 m/s^2) * 5 s
v = 49 m/s

Therefore, the velocity after 5 seconds of fall is 49 m/s.

d. After 10 seconds of fall, the velocity of the object can be calculated using the same formula:
v = 0 + (9.8 m/s^2) * 10 s
v = 98 m/s

Therefore, the velocity after 10 seconds of fall is 98 m/s.