A tennis ball with a velocity of 30.0 m/s to the right is thrown perpendicularly at a wall. After striking the wall, the ball rebounds in the opposite direction with a velocity of -8 m/s to the left. If the ball is in contact with the wall for 0.010 s, what is the average acceleration of the ball while it is in contact with the wall?
V2 = V1 + a*t.
V2 = -8 m/s, V1 = 30 m/s, t = 0.010 s, a = ?.
To find the average acceleration of the ball while it is in contact with the wall, we need to use the formula:
Average acceleration = (change in velocity) / (time)
First, let's calculate the change in velocity. The initial velocity of the ball is 30.0 m/s to the right, and the final velocity after rebounding is -8 m/s to the left. To find the change in velocity, we subtract the initial velocity from the final velocity:
Change in velocity = final velocity - initial velocity
= -8 m/s - 30.0 m/s
= -38.0 m/s
Next, we need to calculate the time. It is given that the ball is in contact with the wall for 0.010 s.
Now, we can substitute these values into the formula for average acceleration:
Average acceleration = (-38.0 m/s) / (0.010 s)
= -3800 m/s^2
Therefore, the average acceleration of the ball while it is in contact with the wall is -3800 m/s^2.