calculate the molarity of sodium carbonate in a solution prepared by dissolving 5.9g in enough water to form 250ml of solution
1/4 liter so four times 5.9 grams in liter
= 23.6 grams in a liter
Na = Na2CO3 = 106 grams/mol
so molarity = 23.6/106 mols/liter
science
To calculate the molarity (M) of a solution, we need to know the number of moles of the solute (in this case, sodium carbonate) and the volume of the solution in liters.
Step 1: Calculate the number of moles of sodium carbonate.
To do this, we use the formula:
Number of moles = mass / molar mass
The molar mass of sodium carbonate (Na2CO3) can be calculated by summing the atomic masses of each element:
Molar mass of Na2CO3 = (2 × atomic mass of Na) + atomic mass of C + (3 × atomic mass of O)
The atomic masses are as follows:
Atomic mass of Na = 22.99 g/mol
Atomic mass of C = 12.01 g/mol
Atomic mass of O = 16.00 g/mol
Now we can calculate the molar mass:
Molar mass of Na2CO3 = (2 × 22.99 g/mol) + 12.01 g/mol + (3 × 16.00 g/mol)
Step 2: Calculate the number of moles.
Number of moles = 5.9g / molar mass of Na2CO3
Step 3: Convert the volume of the solution to liters.
Given that the volume is 250ml, we need to convert it to liters by dividing it by 1000:
Volume in liters = 250ml / 1000
Step 4: Calculate the molarity.
Molarity (M) = number of moles / volume in liters
Now you can plug in the values and calculate the molarity of sodium carbonate in the solution.