The area of a trapezoid is 720 cm square. The height is 10 cm. The two bases of the trapezoid are parallel. Find the length of each base, if one base is 3 times as long as the other.

area of trap

= (a+b)(h)/2, where a and b are the two parallel sides and h is the distance between them.

you have:
(x+3x)(10)/2 = 720

solve for x , then the bases are x and 3x

Thank you

no,

(x+3x)(10)/2 = 720
multiply both sides by 2
10(4x) = 1440
40x = 1440
x = 36

so the sides are 36 and 108

check:
area = (36+108)(10)/2
= 144(5) = 720 as required.

Time to review how to solve simple equations.

Ok so is this correct?

20x + 60x= 720
80x=720
X=9 length of base

Hi can you help me how to find base and height of a trapezoid?

To find the length of each base of the trapezoid, we can use the formula for the area of a trapezoid.

The formula for the area of a trapezoid is:

Area = (1/2) * (base1 + base2) * height

Given that the area of the trapezoid is 720 cm square and the height is 10 cm, we can substitute these values into the formula:

720 = (1/2) * (base1 + base2) * 10

Simplifying the equation, we have:

720 = 5 * (base1 + base2)

Dividing both sides by 5, we get:

144 = base1 + base2

We are also given that one base is 3 times as long as the other. Let's say the shorter base is x, then the longer base would be 3x.

Substituting these values into the equation, we have:

144 = x + 3x

Combining like terms, we get:

144 = 4x

Dividing both sides by 4, we find:

x = 36

So the shorter base is 36 cm, and the longer base is 3 times that, which is:

3 * 36 = 108 cm

Therefore, the length of each base of the trapezoid is 36 cm and 108 cm respectively.