What mass of NO2 is formed by the complete reaction of 2 mol O3 with excess NO in the reaction?
O3 + NO --> O2 + NO2
I know the molar mass of O3 is 48 g/mol and NO2 46 g/mol
a) 23.0 g
b) 46.0 g
c) 92.0 g
d) 96.0 g
Use the coefficients to convert mols of what you have to mols of what you want.
2 mols O3 x (1 mol NO2/1 mol O3) = 2 x 1/1 = 2 mols NO2.
Now convert mols NO2 to grams. Grams = mols NO2 x molar mass NO2 = ?
Well, it seems like you have all the information you need to solve the problem. Let's break it down step by step.
We have 2 moles of O3, and according to the balanced equation, 1 mole of O3 reacts with 1 mole of NO to form 1 mole of NO2.
So, if we have 2 moles of O3, we'll end up with 2 moles of NO2.
Now, let's convert that to grams. The molar mass of NO2 is given as 46 g/mol, so if we have 2 moles, we can simply multiply the molar mass by the number of moles:
2 moles NO2 * 46 g/mol = 92 g
So, the mass of NO2 formed by the complete reaction is 92.0 g.
Therefore, the correct answer is c) 92.0 g.
To find the mass of NO2 formed, we need to determine the mole ratio between O3 and NO2 in the balanced chemical equation.
From the balanced equation:
1 mole of O3 reacts to form 1 mole of NO2.
Given that 2 moles of O3 are reacting, we can conclude that 2 moles of NO2 will be formed.
To calculate the mass of NO2 formed, we can use the formula:
Mass = Molar mass × Moles
Mass of NO2 = (Molar mass of NO2) × (Moles of NO2)
= (46 g/mol) × (2 mol)
= 92 g
Therefore, the mass of NO2 formed by the complete reaction of 2 mol O3 with excess NO is 92.0 g.
The correct answer is c) 92.0 g.
To find the mass of NO2 formed by the reaction between O3 and NO, you need to use stoichiometry and the given molar masses.
First, determine the balanced equation for the reaction:
O3 + NO → O2 + NO2
The balanced equation shows that for every 1 mole of O3, 1 mole of NO2 is formed.
You are given that 2 moles of O3 react, which means we will produce 2 moles of NO2.
Next, calculate the molar mass of NO2:
Molar mass of NO2 = 46 g/mol
Now, use the formula:
Mass = Moles × Molar mass
Mass = 2 mol × 46 g/mol
Mass = 92 g
Therefore, the mass of NO2 formed by the reaction is 92 g.
The correct answer is option (c) 92.0 g.