The solubility of silver sulfate in water is 5.05 grams per liter.

If a silver sulfate solution had a concentration of 7.37 grams per liter, it would be said to be saturated, supersaturated or unsaturated?

To determine whether the silver sulfate solution with a concentration of 7.37 grams per liter is saturated, supersaturated, or unsaturated, we need to compare the concentration with the solubility of silver sulfate in water.

Given that the solubility of silver sulfate in water is 5.05 grams per liter, we can analyze the concentration of 7.37 grams per liter.

- If the concentration is less than the solubility (7.37 grams per liter < 5.05 grams per liter), then the solution is unsaturated. This means that more silver sulfate could still dissolve in the solution.
- If the concentration is equal to the solubility (7.37 grams per liter = 5.05 grams per liter), then the solution is saturated. This means that no more silver sulfate can dissolve, and the solution is already at its maximum capacity.
- If the concentration is greater than the solubility (7.37 grams per liter > 5.05 grams per liter), then the solution is supersaturated. This means that more silver sulfate has dissolved in the solution than can normally be dissolved under normal conditions.

Therefore, in this case, since the concentration of 7.37 grams per liter is greater than the solubility of 5.05 grams per liter, the solution would be classified as supersaturated.