Yuri surveyed randomly selected middle school students in his neighborhood. He found that around 60% of them plan to participate in a charity walk organized by the town council. What is the estimated probability that it will take at least six middle school students to find one who doesn't plan to participate in the charity walk?
Use the table of simulated values to answer the question. The numbers 0 to 5 represent middle school students planning to participate in the charity walk, and 6 to 9 represent those who are not planning to participate.
7 1 0 7 8 8 8 5 3 0 3 0 0 5 7 3 8 5 4 6 5 6 6 4 2
9 3 0 7 7 9 2 5 4 4 5 4 0 2 8 4 8 3 9 8 4 0 0 8 1
4 4 4 1 4 7 0 2 7 3 8 9 3 9 8 5 2 4 7 6 7 6 1 7 1
9 3 4 7 2 4 5 4 3 2 2 6 6 2 6 3 8 5 3 2 7 5 9 6 2
9 5 4 2 7 1 5 7 1 1 8 8 4 4 1 1 0 2 0 4 5 0 5 1 6
5 1 3 0 6 8 3 3 1 6 2 0 6 9 5 3 1 5 4 2 6 2 5 6 9
7 0 8 4 9 5 8 0 0 1 6 6 2 2 4 8 1 8 7 9 4 4 8 7 7
9 6 7 8 7 2 8 6 0 8 1 0 4 6 8 1 8 3 1 7 2 2 4 2 6
6 0 7 0 2 3 6 4 3 0 1 8 2 5 7 5 5 5 1 8 3 8 9 7 7
5 6 7 2 5 8 4 3 5 1 7 8 6 0 5 6 1 9 3 6 3 1 1 0 5
0.02
0.10
0.30
0.60
0.02
the correct answer is not A. 0.02 it is C 0.30
To find the estimated probability of it taking at least six middle school students to find one who doesn't plan to participate in the charity walk, we need to look at the values in the table of simulated values.
From the given table, we can see that the numbers 6 to 9 represent those who do not plan to participate in the charity walk. Let's calculate the proportion of values equal to or greater than 6 in each row.
Row 1: 3 out of 5 values are greater than or equal to 6.
Row 2: 2 out of 5 values are greater than or equal to 6.
Row 3: 0 out of 5 values are greater than or equal to 6.
Row 4: 2 out of 5 values are greater than or equal to 6.
Row 5: 3 out of 5 values are greater than or equal to 6.
Row 6: 3 out of 5 values are greater than or equal to 6.
Row 7: 4 out of 5 values are greater than or equal to 6.
Row 8: 2 out of 5 values are greater than or equal to 6.
Row 9: 1 out of 5 values is greater than or equal to 6.
Row 10: 2 out of 5 values are greater than or equal to 6.
Now, let's calculate the average proportion across all rows:
(3/5 + 2/5 + 0/5 + 2/5 + 3/5 + 3/5 + 4/5 + 2/5 + 1/5 + 2/5)/10 = 22/50 = 0.44
So, the estimated probability that it will take at least six middle school students to find one who doesn't plan to participate in the charity walk is approximately 44%, which is closest to option 0.10.
To find the estimated probability that it will take at least six middle school students to find one who doesn't plan to participate in the charity walk, we need to analyze the simulated values in the table.
Looking at the table, we can see that the numbers from 0 to 5 represent middle school students planning to participate in the charity walk, and numbers from 6 to 9 represent those who are not planning to participate.
First, count the total number of entries in the table. In this case, there are 100 values.
Next, count the number of entries in the table where the value is 6 or higher, representing middle school students who do not plan to participate in the charity walk. From the table, we can identify the following entries: 7, 7, 9, 8, 8, 8, 7, 9, 7, 7, 7, 9, 7, 6, 8, 9, 8, 9, 7, 8, 8, 9, 6, 7, 6, 9, 7, 8, 7, 9, 6, 7, 8, 7, 8, 7, 8, 8, 9, 6, 9, 7, 8, 8, 9, 6, 6, 7, 8, 7, 9, 8, 7, 7, 7, 9, 7, 7, 7, 9, 7, 8, 8, 9, 7, 6, 7, 7, 8, 7, 6, 7, 6, 9, 8, 7, 7, 8, 8, 7, 7, 7, 9, 7, 9, 8, 7, 9, 7, 8, 7, 6, 7, 8, 9, 8, 7, 8, 9, 7, 8, 8, 9, 7, 7, 9, 7, 6, 8, 7, 7, 7, 8
Counting all of the entries, we find that there are 96 values that are 6 or higher.
Finally, calculate the estimated probability by dividing the count of entries that are 6 or higher by the total number of entries: 96 / 100 = 0.96.
Therefore, the estimated probability that it will take at least six middle school students to find one who doesn't plan to participate in the charity walk is approximately 0.96, or 96%.
Please note that the options you provided for the answer do not match the calculated probability.