Show the steps needed to determine the energy in a red photon of 7.0 x 10^2 nm.
E= h * (c/λ)
6.62e-34 * (3e8/2e-7)
2.837e-19 J?
Is this correct?
Where did you use lambda of 7E-7 m?
Yes, sorry typo.
To determine the energy of a photon, you can use the equation:
E = h * (c / λ)
Where:
E is the energy of the photon in joules (J)
h is Planck's constant, approximately 6.626 x 10^-34 J·s
c is the speed of light, approximately 3.0 x 10^8 m/s
λ is the wavelength of the photon in meters (m)
Given the wavelength of the red photon as 7.0 x 10^2 nm, we need to convert it to meters by dividing by 1 x 10^9 (since there are 1 billion nanometers in a meter), or in scientific notation, by 1 x 10^-9.
7.0 x 10^2 nm = 7.0 x 10^-7 m
Now we can substitute the values into the equation:
E = (6.626 x 10^-34 J·s) * (3.0 x 10^8 m/s) / (7.0 x 10^-7 m)
Calculating this expression:
E = 2.837 x 10^-19 J
So, yes, your calculation is correct. The energy of the red photon with a wavelength of 7.0 x 10^2 nm is approximately 2.837 x 10^-19 J.