Two pellets, each with a charge of 0.80 microcoulomb (8.0×10−7 C ), are located 2.8 cm (2.8×10−2 m ) apart.
Part A
Find the electric force between them.
To find the electric force between the two pellets, you can use Coulomb's Law, which states that the electric force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.
The formula for electric force (F) can be written as:
F = (k * q1 * q2) / r^2
Where:
- F is the electric force between the two pellets
- k is the electrostatic constant, approximately 9 × 10^9 Nm^2/C^2
- q1 and q2 are the charges of the two pellets
- r is the distance between the two pellets
In this case, the charges of the pellets are both 0.80 microcoulomb, which is equivalent to 8.0 × 10^-7 C. The distance between the pellets is 2.8 cm, which is equivalent to 2.8 × 10^-2 m.
Now let's substitute the values into the formula:
F = (9 × 10^9 Nm^2/C^2) * (8.0 × 10^-7 C) * (8.0 × 10^-7 C) / (2.8 × 10^-2 m)^2
Simplifying the expression:
F = (9 × 10^9 Nm^2/C^2) * (8.0 × 10^-7 C)^2 / (2.8 × 10^-2 m)^2
F = (9 × 8.0^2) * (10^9 * 10^-7 * 10^-7) / (2.8^2 * 10^-2^2)
F = 57.6 × 10^9 * 10^-14 / 7.84 * 10^-4
F = 57.6 / 7.84 * 10^-5
F = 7.35 × 10^-4 N
Therefore, the electric force between the two pellets is 7.35 × 10^-4 N.
force=coulombs law= k qq/.028^2
you are given q, and I assume you know coulombs constant, if not look it up and memborize