A golfer hits a 0.05 kg golf ball with an impulse of +3 N-s. What is the change in velocity of the ball?

the product of force and time is 3

3 N for 1 s isn't realistic for golf, but it's easy to work with

f = m a ... 3 = .05 a ... a = 60 m/s^2

t = 1 s , so the velocity is 60 m/s

To solve this problem, we can use the impulse-momentum relationship:

Impulse (J) = Change in Momentum (Δp)

Impulse is the product of force and time, and momentum is the product of mass and velocity. Since we know the impulse (J) and the mass of the golf ball, we can calculate the change in velocity (Δv).

Here's how you can calculate the change in velocity of the golf ball:

Step 1: Identify the given values:
- Impulse (J) = +3 N-s
- Mass of the golf ball (m) = 0.05 kg

Step 2: Use the formula for impulse-momentum relationship:
J = Δp
J = m * Δv

Step 3: Rearrange the formula:
Δv = J / m

Step 4: Substitute the known values:
Δv = (3 N-s) / (0.05 kg)

Step 5: Calculate the change in velocity:
Δv = 60 m/s

Therefore, the change in velocity of the golf ball is 60 m/s.