For the reaction 2zn+o2=2zno, how many grams of zinc oxide are produced from 2.25g of oxygen?
a mole of O2 gives 2 moles of ZnO
the molar mass of O2 is ... ?
2.25 g is ? moles of O2
the molar mass of ZnO is ... ?
To determine the number of grams of zinc oxide produced, we need to use the stoichiometry of the reaction.
Step 1: Write the balanced chemical equation:
2 Zn + O2 → 2 ZnO
Step 2: Calculate the molar mass of oxygen (O):
O: 16.00 g/mol
Step 3: Convert the given mass of oxygen (2.25 g) to moles:
moles of O = mass of O / molar mass of O
moles of O = 2.25 g / 16.00 g/mol ≈ 0.14 mol
Step 4: Use the mole ratio from the balanced chemical equation to determine the moles of zinc oxide (ZnO) produced. According to the equation, for every 1 mole of O2, 2 moles of ZnO are produced.
moles of ZnO = 0.14 mol O2 × (2 mol ZnO / 1 mol O2) = 0.28 mol ZnO
Step 5: Calculate the molar mass of zinc oxide (ZnO):
Zn: 65.38 g/mol
O: 16.00 g/mol
molar mass ZnO = Zn + O = 65.38 g/mol + 16.00 g/mol = 81.38 g/mol
Step 6: Convert the moles of zinc oxide (ZnO) to grams:
grams of ZnO = moles of ZnO × molar mass ZnO
grams of ZnO = 0.28 mol × 81.38 g/mol ≈ 22.82 g
Therefore, approximately 22.82 grams of zinc oxide (ZnO) are produced from 2.25 grams of oxygen (O2).
To find out how many grams of zinc oxide are produced from 2.25g of oxygen, we need to use stoichiometry. Stoichiometry is a method used in chemistry to relate the quantities of reactants and products in a chemical reaction.
First, we need to determine the balanced equation for the reaction. In this case, the balanced equation is:
2Zn + O2 → 2ZnO
From the balanced equation, we can see that 1 mole of oxygen (O2) reacts with 2 moles of zinc (Zn) to produce 2 moles of zinc oxide (ZnO).
To find the number of moles of oxygen present, we use the formula:
moles = mass / molar mass
The molar mass of oxygen (O2) is approximately 32 g/mol. Therefore, for 2.25g of oxygen:
moles of oxygen = 2.25g / 32 g/mol
Now, we can use stoichiometry to find the number of moles of zinc oxide produced. From the balanced equation, we know that the stoichiometric ratio between oxygen and zinc oxide is 1:2. This means that for every 1 mole of oxygen consumed, 2 moles of zinc oxide are produced.
Therefore, the number of moles of zinc oxide produced would be:
moles of zinc oxide = moles of oxygen * (2 moles of ZnO / 1 mole O2)
Finally, we can calculate the mass of zinc oxide produced using its molar mass. The molar mass of zinc oxide (ZnO) is approximately 81.4 g/mol.
mass of zinc oxide = moles of zinc oxide * molar mass of ZnO
By substituting the values into the equation, you can calculate the mass of zinc oxide produced from 2.25g of oxygen.