Chlorine+sulphur dioxide+water giving sulphuric acid+hydrogen chloride
Cl2 + SO2 + 2H2O ==> H2SO4 + 2HCl
Thank you
The chemical equation you provided represents a reaction between chlorine gas (Cl2), sulfur dioxide gas (SO2), and water (H2O) to form sulfuric acid (H2SO4) and hydrogen chloride gas (HCl). To explain how to get the answer, we need to understand the reaction and balance the equation.
The reaction you described is a redox reaction, meaning that oxidation and reduction occur simultaneously. The chlorine gas is being reduced, gaining electrons, while the sulfur dioxide is being oxidized, losing electrons.
To balance the equation, we start by identifying the number of atoms of each element on both sides of the equation.
Reactants:
Chlorine: 1 chlorine atom (Cl2)
Sulfur dioxide: 1 sulfur atom (SO2)
Water: 2 hydrogen atoms (H2O)
Products:
Sulfuric acid: 1 sulfur atom and 4 oxygen atoms (H2SO4)
Hydrogen chloride: 1 chlorine atom and 1 hydrogen atom (HCl)
Now we can balance the equation by adjusting coefficients in front of each compound to ensure the same number of atoms on both sides of the equation.
The balanced equation is:
Cl2 + SO2 + H2O → H2SO4 + HCl
So, the reactants are chlorine gas, sulfur dioxide gas, and water, which combine to give sulfuric acid and hydrogen chloride gas as products.