If a stone is thrown with velocity 10 m/s. How high will it reach after 10 s. Take g = 10 m/s^2

I want to know if this question is practically possible. I tried to solve this problem and ended up getting the answer in negative. Please help me!!! Afterall time of fall is inversely proportional to g.

You are right about the negative answer.

Assuming the stone is thrown straight up,
d=(10 m/s)(10 s) + (1/2)(-10 m/s^2)(10 s)^2
d= -400 m

It coud be possible if the stone were thrown straight up, over a deep pit. It would mean that the stone was located 400m down into the pit at 10 seconds.

with g=10

the highest it gets is 5 m

at t = 1 s

Yes, this question is practically possible to solve. To determine the height the stone will reach after 10 seconds, you can use the equations of motion. The key equation to use is:

h = v₀t - (1/2)gt²

where:
- h is the height the stone reaches,
- v₀ is the initial velocity of the stone,
- t is the time, and
- g is the acceleration due to gravity.

In this case, the initial velocity (v₀) is given as 10 m/s, the time (t) is given as 10 s, and the acceleration due to gravity (g) is given as 10 m/s².

Let's calculate the height by substituting the values into the equation:

h = (10 m/s)(10 s) - (1/2)(10 m/s²)(10 s)²
= 100 m - (1/2)(10 m/s²)(100 s²)
= 100 m - (1/2)(10 m/s²)(10000 s²)
= 100 m - 5000 m
= -4900 m

As you mentioned, you obtained a negative value. However, this negative value indicates that the stone has fallen 4900 meters below its initial position after 10 seconds. It does not mean that the stone reached a negative height. In practical terms, this negative height would imply that the stone has fallen significantly below the surface of the Earth.

To avoid the negative result, it is important to consider the direction and sign conventions while applying the equations. Usually, the positive direction is taken upwards, and the negative sign indicates downwards. So, if you consider the initial position as the reference point (e.g., the ground level), the height should be measured with respect to the reference point.