A certain material has a work function 0 (angle sign) = 1.5 eV.
a)what is the frequency of a photon that ejects an electron from his material, giving the electron an energy of 1.6 eV?
b)what type of EM radiation is this?
To find the frequency of the photon that ejects an electron from a material, we can start by using the relationship between energy and frequency in the context of photons:
E = hf
Where:
E is the energy of the photon,
h is the Planck's constant (approximately 4.13567 x 10^-15 eV·s), and
f is the frequency of the photon.
a) To determine the frequency of the photon that gives the electron an energy of 1.6 eV, we can rearrange the equation to solve for frequency:
E = hf
Divide both sides of the equation by h:
f = E / h
Substitute the given values:
f = 1.6 eV / 4.13567 x 10^-15 eV·s
Calculating this value will give us the frequency of the photon.
b) Determining the type of electromagnetic (EM) radiation depends on the frequency or wavelength of the photon. There are various categories of EM radiation, including radio waves, microwaves, infrared, visible light, ultraviolet, X-rays, and gamma rays.
To identify the type of EM radiation, we need to compare the frequency of the photon calculated in part a) with known ranges for different types of EM radiation. Here are the general ranges:
- Radio Waves: frequencies from about 30 kHz to 300 GHz
- Microwaves: frequencies from about 300 MHz to 300 GHz
- Infrared: wavelengths from about 700 nm to 1 mm
- Visible Light: wavelengths from about 400 nm (violet) to 700 nm (red)
- Ultraviolet: wavelengths from about 100 nm to 10 nm
- X-rays: wavelengths from about 10 nm to 0.001 nm
- Gamma Rays: wavelengths below 0.001 nm
By comparing the frequency with the ranges mentioned above, we can determine the type of EM radiation associated with the given frequency.