The sum of two numbers is equal to 495. The last digit of one of them is zero. If you cross the zero off the first number you will get the second. What are the numbers?

x+10x=495

11x=495
x=45 10x=450

Looks like 45 and 450 to me.

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45 and 450

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To find the two numbers, let's break down the given information and explore the solution step by step.

We are given the following information:
1. The sum of two numbers is equal to 495.
2. The last digit of one of the numbers is zero.
3. If we remove the zero from the first number, we will get the second number.

Let's assume the first number is a0, where a is a digit (0-9) and 0 represents the last digit being zero. According to the third condition, the second number will be obtained by removing the zero, resulting in just the digit a.

Considering the sum of the two numbers being 495, we can form the equation:
a0 + a = 495

To solve this equation, we need to find the value of a.

Let's start by subtracting a from both sides of the equation:
a0 - a + a = 495 - a
a0 = 495 - a

We also know that a0 is a hundred digit number because the last digit is zero. So a cannot be greater than or equal to 5 since subtracting it from 495 would not result in a three-digit number. Thus, a must be less than 5.

Now, let's try different values for a less than 5 and find the corresponding value for a0:

1. When a = 1, a0 = 495 - 1 = 494. However, 494 is not a hundred digit number, so this solution is invalid.
2. When a = 2, a0 = 495 - 2 = 493. Again, 493 is not a hundred digit number, so this solution is invalid.
3. Continuing this process, when a = 3, a0 = 495 - 3 = 492. Once again, 492 is not a hundred digit number, so this solution is invalid.
4. Finally, when a = 4, a0 = 495 - 4 = 491. This time, 491 is a hundred digit number, so this solution satisfies all the given conditions.

Therefore, the two numbers are 491 and 41.

thx

45 and 450

wasup