If the absolute pressur at the bottom of a fresh water pond is 2.313time10^5PA.what will be the depth of the pond?
To calculate the depth of the pond, we need to use the concept of pressure in a fluid. The pressure at a certain depth in a fluid is given by the equation:
P = P₀ + ρgh
Where:
- P is the pressure at the given depth
- P₀ is the atmospheric pressure (approximately 1.013 × 10^5 Pa)
- ρ is the density of the fluid (in this case, fresh water, which has a density of approximately 1000 kg/m³)
- g is the acceleration due to gravity (approximately 9.8 m/s²)
- h is the depth from the surface of the pond to the point where the pressure is measured (which is what we want to find)
To solve the equation for h, we rearrange it as follows:
h = (P - P₀) / (ρg)
Now we can substitute the given values into the equation:
P = 2.313 × 10^5 Pa (given)
P₀ = 1.013 × 10^5 Pa (atmospheric pressure)
ρ = 1000 kg/m³ (density of fresh water)
g = 9.8 m/s² (acceleration due to gravity)
Substituting the values:
h = (2.313 × 10^5 - 1.013 × 10^5) / (1000 × 9.8)
h = 1.3 × 10^5 / 9800
h ≈ 13.3 meters
Therefore, the depth of the pond is approximately 13.3 meters.