Fred and Jane are brother and sister. Fred is 3years older than twice jane's age. The sum of their ages is less than 36. Taking jane's age

To be x years form a inequation. What can you say about jane's age.

Jane ---- x

Fred ---- 2x+3

x + 2x+3 < 36
3x < 33
x < 11

Looks like Jane is less than 11 years old.

testing:
let Jane be 10
then Fred is 23 , their sum is < 36

To solve this problem, we need to break it down step by step:

1. Let's assume Jane's age is x years.
2. According to the given information, Fred is 3 years older than twice Jane's age. So, Fred's age is 2x + 3 years.
3. The sum of their ages is less than 36. Therefore, the equation would be: x + (2x + 3) < 36.
4. Simplifying the equation, we get: 3x + 3 < 36.
5. Subtracting 3 from both sides, we have: 3x < 33.
6. Dividing by 3, we find: x < 11.

So, we can conclude that Jane's age (x) is less than 11 years.