A golf ball was hit and projected at an angle of 65° with the horizontal. If the initial velocity of the ball was 60m/s.Calculate the time the golf ball was in the air and the horizontal distance the ball travelled

The airborne time will be given by:

t = v1/g where t is the time taken, v1 is the initial velocity and g is the acceleration due to the gravity pulling the golf ball towards the center of the earth.

t=60/9.8
t=6.12244897959 seconds.

Multiplying that by 2 to have the total airborne time,

actual time = 12.2448979592 seconds.

Now, for the horizontal distance traveled,

Using simple height and distance, if the golf ball covered a distance of 60 meters in one second at an angle of 65° then the horizontal distance covered must be 25.3570957044 meters.

Multiplying that by the airborne time, we have,

25.3570957044 * 6.12244897959
= 155.247524721 meters.

So the golf ball was in the air for 6.1 seconds and the horizontal distance covered was 155.2 meters.

To solve this problem, we can analyze the ball's motion in the horizontal and vertical directions separately.

Step 1: Finding the vertical component of velocity
The initial velocity can be broken down into horizontal and vertical components.
Given:
Initial velocity (V₀) = 60 m/s
Angle of projection (θ) = 65°

The vertical component of velocity (Vᵥ) can be found using the formula:
Vᵥ = V₀ * sin(θ)

Vᵥ = 60 * sin(65°)
Vᵥ ≈ 51.92 m/s

Step 2: Finding time of flight
The time of flight can be calculated using the formula:
Time of flight (T) = (2 * Vᵥ) / g

Where g is the acceleration due to gravity (approximately 9.8 m/s²).

T = (2 * 51.92) / 9.8
T ≈ 10.58 seconds

Therefore, the golf ball was in the air for approximately 10.58 seconds.

Step 3: Finding the horizontal distance traveled
The horizontal distance traveled (D) can be calculated using the formula:
D = V₀ * cos(θ) * T

D = 60 * cos(65°) * 10.58
D ≈ 399.84 meters

Therefore, the golf ball traveled approximately 399.84 meters horizontally.

To calculate the time the golf ball was in the air and the horizontal distance it traveled, we can use the equations of projectile motion.

The motion of the golf ball can be split into horizontal and vertical components. The horizontal motion is affected only by the initial horizontal velocity, while the vertical motion is affected by both the initial vertical velocity and the acceleration due to gravity.

1. Calculate the time of flight:
The time of flight of the golf ball is the time it takes for the ball to reach the ground after being hit. We can calculate this using the equation:
Time = (2 * initial vertical velocity) / acceleration due to gravity

Given:
Initial vertical velocity (Vy) = initial velocity * sine(angle)
Acceleration due to gravity (g) = 9.8 m/s^2

Plug in the values:
Time = (2 * 60 m/s * sin(65°)) / 9.8 m/s^2

Calculate the time.

2. Calculate the horizontal distance:
The horizontal distance traveled by the golf ball can be calculated using the equation:
Distance = initial horizontal velocity * time

Given:
Initial horizontal velocity (Vx) = initial velocity * cosine(angle)
Time (from step 1) = calculated time

Plug in the values:
Distance = (60 m/s * cos(65°)) * time

Calculate the distance.

By following these steps and performing the calculations, you will be able to find the time the golf ball was in the air and the horizontal distance it traveled.