use integer values of x from-3 to 3 to graph the equation y=2x^2=3
can you tell me the coordinates, then i can graph it, i just dont understand how to get them. thanks.
x=0, y=2*0^2+3 = 0+3 = 3
x=1, y=2*1^2+3 = 2+3 = 5
and so on for the other values.
So would the next one be x=3 y=7?
The next x value could be 3, but how did you come up with y=7?
I apologize for the mistake in the equation you provided. There is an extra equal sign before the constant term. The correct equation is actually y = 2x^2 + 3.
To graph this equation using integer values of x from -3 to 3, we can substitute each value of x into the equation to find the corresponding y-values.
Let's start with x = -3:
y = 2(-3)^2 + 3
= 2(9) + 3
= 18 + 3
= 21
So when x = -3, y = 21.
Now let's continue with the remaining integer values of x, substituting each value into the equation:
For x = -2: y = 2(-2)^2 + 3 = 11
For x = -1: y = 2(-1)^2 + 3 = 5
For x = 0: y = 2(0)^2 + 3 = 3
For x = 1: y = 2(1)^2 + 3 = 5
For x = 2: y = 2(2)^2 + 3 = 11
For x = 3: y = 2(3)^2 + 3 = 21
So the coordinates for the graph are:
(-3, 21), (-2, 11), (-1, 5), (0, 3), (1, 5), (2, 11), and (3, 21).
Now, you can plot these points on a graph with the x-axis representing the values of x and the y-axis representing the values of y. Once you have all the points plotted, you can connect them to create a graph of the equation y = 2x^2 + 3.