Thirty feet of water exert a pressure of 1 atm. Calculate the pressure (in kPa) exerted on a diver at a depth of 50 feet on a standard day.
the gage pressure (pressure above one atm) would be
(5/3)*1 atm
but 1 atm = 101325 Pascals=101.325kPa
so
(5/3)(101) kPA
if you want absolute pressure add 1 atm or 101 kPa to that
So why is it 5/3 not 3/5 because P1V1=P2V2 right?
To calculate the pressure exerted on a diver at a certain depth, we can use the concept of hydrostatic pressure. Hydrostatic pressure increases with an increase in depth underwater.
The pressure exerted by a column of water can be calculated using the equation:
P = ρ * g * h
Where:
P is the pressure exerted by the column of water (in Pascals or N/m²)
ρ is the density of the fluid (in kg/m³)
g is the acceleration due to gravity (approximately 9.8 m/s²)
h is the height or depth of the fluid (in meters)
First, we need to convert the depth from feet to meters. Since 1 meter is approximately equal to 3.281 feet, we can calculate the depth in meters as:
Depth in meters = 50 feet * (1 meter / 3.281 feet)
Depth in meters = 15.240 meters
Next, we need to calculate the pressure in Pascals. Since 1 atmosphere (atm) is equal to 101325 Pascals, we can calculate the pressure as:
Pressure in Pascals = 1 atm * 101325 Pascals/atm
Pressure in Pascals = 101325 Pascals
Finally, we can calculate the pressure in kilopascals (kPa) by dividing the pressure in Pascals by 1000:
Pressure in kPa = 101325 Pascals / 1000
Pressure in kPa = 101.325 kPa
Therefore, the pressure exerted on the diver at a depth of 50 feet on a standard day is approximately 101.325 kPa.