3log2 plus log 20 - log1.6
Evaluate without any table 3 log 2 + log 20 - log 1.6
Evaluate without any table 3 log 2 + log 20 - log 1.6
i need answer
i need the answer
3log2+log20-log1.6
8x20/1.6 = 100 = 2
To evaluate the expression 3log2 + log20 - log1.6, we can start by simplifying each term step by step.
1. First, let's simplify the logarithmic expressions using logarithmic properties:
a) 3log2: Using the logarithmic property log(ab) = b * log(a), we can rewrite this term as log(2^3) = log(8).
b) log20: Since there is no base indicated for the logarithm, we assume it to be base 10. So, log20 represents log base 10 of 20.
c) log1.6: Similarly, log1.6 represents log base 10 of 1.6.
2. Now, we can calculate the logarithmic values:
a) log(8): You can use a calculator to find log(8) ≈ 0.9031.
b) log(20): Similarly, use a calculator to find log(20) ≈ 1.3010.
c) log(1.6): Use a calculator to find log(1.6) ≈ 0.2041.
3. Now, substitute these calculated logarithmic values back into the equation:
3log2 + log20 - log1.6 can be rewritten as:
3(0.9031) + 1.3010 - 0.2041
4. Now, perform the arithmetic operations:
3(0.9031) + 1.3010 - 0.2041 = 2.7093 + 1.3010 - 0.2041 = 3.8062
Therefore, the value of the expression 3log2 + log20 - log1.6 is approximately 3.8062.