The square root of number that is two bigger than k is twice as big as the square root of the number one less than k. What is k?
No idea, but
√(k+2) = 2√(k-1)
If you solve the equation above, k=2
To find the value of k, we can set up an equation based on the given information.
Let's break down the information given:
The square root of a number that is two bigger than k can be written as √(k + 2).
The square root of the number one less than k can be written as √(k - 1).
According to the given information, we have the equation √(k + 2) = 2 * √(k - 1).
Now, let's solve the equation:
Square both sides of the equation to get rid of the square roots:
(√(k + 2))^2 = (2 * √(k - 1))^2
Simplifying both sides, we get:
k + 2 = 4(k - 1)
Expand the right side of the equation:
k + 2 = 4k - 4
Move the k terms to one side and the constant terms to the other side:
k - 4k = -4 - 2
-3k = -6
Divide both sides of the equation by -3 to solve for k:
k = (-6) / (-3)
k = 2
Therefore, the value of k is 2.