For the equation
3^x - 3^-x = 1 solve for x by writing your final answer in logarithmic form.
let u = 3^x. Then you have
u - 1/u - 1 = 0
u^2-u-1 = 0
solve for u, and then x = log3u
3^x - 3^-x = 1 solve for x by writing your final answer in logarithmic form.
u - 1/u - 1 = 0
u^2-u-1 = 0
solve for u, and then x = log3u