Which force(s) provide(s) the centripetal force needed for a car to make a turn on a banked
curve?
A. Weight, only
B. Tension, only.
C. Friction, only.
D. Coriolis force, only.
E. Friction and normal force.
Is it D?
nope
E
friction from the tires and normal force from the banking
No, the correct answer is E. Friction and normal force.
To understand why, let's break it down:
In order for an object to move in a curved path, it must experience a centripetal force, which is directed towards the center of the curve. This force is responsible for continuously changing the object's direction.
In the case of a car making a turn on a banked curve, there are two main forces involved:
1. Friction: The friction force between the car's tires and the road surface provides the necessary centripetal force. As the car turns, the friction force acts towards the center of the curve, helping to keep the car on the desired path.
2. Normal force: The normal force is the force exerted by a surface to support the weight of an object resting on it. On a banked curve, the road is angled or banked towards the center of the curve. This tilted surface results in a normal force that has both a vertical and a horizontal component. The horizontal component of the normal force acts towards the center of the curve and contributes to the centripetal force.
Weight (force due to gravity) plays a role in creating the normal force, but it does not provide the centripetal force directly. Tension is not typically involved in a car making a turn on a banked curve. The Coriolis force is a fictitious force that comes into play in rotating reference frames, but it does not provide the centripetal force in this scenario.
Therefore, the centripetal force needed for a car to make a turn on a banked curve is provided by the combination of friction and the horizontal component of the normal force, making option E the correct answer.