A fixed amount of oxygen gas is held in a .500 L tank at a pressure of 4.09 atm. The tank is connected to an empty 1.50 L tank by a tube with a valve. After this valve has been opened and the oxygen is allowed to flow freely between the two tanks at a constant temperature, what is the final pressure in the system?
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Use p1v1 = p2v2
v1 is 0.5L
v2 is 2.0 L
To find the final pressure in the system, we can use the combined gas law equation:
(P1 * V1)/T1 = (P2 * V2)/T2
Where:
P1 = initial pressure of the first tank
V1 = initial volume of the first tank
T1 = constant temperature
P2 = final pressure of the combined system
V2 = final volume of the combined system
T2 = constant temperature
Given:
P1 = 4.09 atm (initial pressure of the first tank)
V1 = 0.5 L (initial volume of the first tank)
V2 = 2 L (final volume of the combined system)
Since the temperature is constant, we can disregard the temperature terms (T1 and T2) in the equation. Rearranging the equation, we get:
P2 = (P1 * V1) / V2
Substituting the values:
P2 = (4.09 atm * 0.5 L) / 2 L
P2 = 2.045 atm
Therefore, the final pressure in the system is 2.045 atm.